Research article

General and optimal decay rates for a system of wave equations with damping and a coupled source term

  • Received: 18 July 2024 Revised: 02 October 2024 Accepted: 12 October 2024 Published: 17 October 2024
  • MSC : 35L05, 35L20

  • In this article, we aim to investigate the decay characteristics of a system consisting of two viscoelastic wave equations with Dirichlet boundary conditions, where the dispersion term and nonlinear weak damping term are taken into account. Under appropriate conditions, we establish both general and optimal decay results. This work generalizes and improves earlier results in the literature.

    Citation: Qian Li, Yanyuan Xing. General and optimal decay rates for a system of wave equations with damping and a coupled source term[J]. AIMS Mathematics, 2024, 9(10): 29404-29424. doi: 10.3934/math.20241425

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  • In this article, we aim to investigate the decay characteristics of a system consisting of two viscoelastic wave equations with Dirichlet boundary conditions, where the dispersion term and nonlinear weak damping term are taken into account. Under appropriate conditions, we establish both general and optimal decay results. This work generalizes and improves earlier results in the literature.



    In this paper, we study the following system of nonlinear viscoelastic equations:

    {uttΔuΔutt+t0g1(tτ)Δu(τ)dτ+|ut|m2ut=f1(u,v),(x,t)Ω×(0,+),vttΔvΔvtt+t0g2(tτ)Δv(τ)dτ+|vt|r2vt=f2(u,v),(x,t)Ω×(0,+),u(x,t)=v(x,t)=0,(x,t)Ω×(0,+),u(x,0)=u0(x),ut(x,0)=u1(x),xΩ,v(x,0)=v0(x),vt(x,0)=v1(x),xΩ. (1.1)

    Here, Ω is a bounded domain of Rn(n1) with a smooth boundary Ω, g1 and g2 denote the kernel of the memory term and the index number m,r2, u and v represent the transverse displacements of waves, and f1 and f2 are given functions to be specified later.

    To motivate our work, we recall some results related to our work. For a single viscoelastic wave equation of the form

    uttΔuωΔut+μut=uln|u|,(x,t)Ω×(0,),

    Xu and Lian [1] studied the above initial boundary value problem at three different initial energy levels, they proved the local existence of a weak solution, and in the framework of a potential well, they showed the global existence and energy decay of the solution with sub-critical initial energy. Then, through a scaling technique, they parallelly extended all the results for the subcritical case to the critical case. A similar result was also obtained in [2,3]. In [4], Xu et al. considered the following initial boundary value problem

    uttΔuΔutt+t0g(ts)Δu(s)dsΔut+ut=u|u|p1,inΩ×(0,), (1.2)

    they obtained the invariant sets, and proved the existence and nonexistence of a global solution. Moreover, they got a finite time blow-up result for certain solutions under a high energy case. In [5,6], Messaoudi proved, by using the perturbed energy method and under the supposition that g(t)ξ(t)g(t), that the solution energy was a general decay, not necessarily of exponential or polynomial type. {Under the same assumptions on a relaxation function, Liu [7] studied a viscoelastic wave equation with the dispersion term and proved that the decay rate of the solution energy was similar to that of the relaxation function. Furthermore, Messaoudi and Al-Khulaifi [8] established a general and optimal decay of the solution energy where the relaxation function satisfies g(t)ξ(t)gθ(t), 1θ<32. In [9], the author established the optimal explicit and general energy decay results under the condition g(t)ξ(t)H(g(t)), where H is an increasing and convex function near the origin and ξ is a non-increasing function.

    Subsequently, the above methods used in the single viscoelastic wave equation were extended to coupled wave systems. For example, Li [10] considered the following wave system:

    {|ut|ρuttΔu+t0g1(tτ)Δu(τ)dτ+|ut|m1ut=f1(u,v),(x,t)Ω×(0,+),|vt|ρvttΔv+t0g2(tτ)Δv(τ)dτ+|vt|r1vt=f2(u,v),(x,t)Ω×(0,+),u(x,t)=v(x,t)=0,(x,t)Ω×(0,),u(x,0)=u0(x),ut(x,0)=u1(x),xΩ,v(x,0)=v0(x),vt(x,0)=v1(x),xΩ, (1.3)

    where ΩRn (n1) is a bounded domain with a smooth boundary Ω, 0<ρ, m,r1. Under the following assumptions on the relaxation functions: gi(t)ξi(t)gi(t),t0,i=1,2. Based on the potential well method and the perturbed energy method, the author obtained a general decay result of the solution. Furthermore, in [11], the author got some sufficient conditions on initial data such that the solution blows up in finite time at arbitrarily high initial energy. In the same direction and in the case of ρ=0, Liu et al. [12] proved that the solution energy was an exponential decay or polynomial decay. Later, this result was furthered by Said-Houari [13], who demonstrated that the solution energy was a general decay. In the same nature, Liu [14] considered the following system:

    {|ut|ρuttΔuγ1Δutt+t0g(tτ)Δu(τ)dτ+f(u,v)=0,(x,t)Ω×(0,+),|vt|ρvttΔvγ2Δvtt+t0h(tτ)Δv(τ)dτ+k(u,v)=0,(x,t)Ω×(0,+),u(x,t)=v(x,t)=0,(x,t)Ω×(0,),u(x,0)=u0(x),ut(x,0)=u1(x),xΩ,v(x,0)=v0(x),vt(x,0)=v1(x),xΩ,

    where γ1,γ20 are constans, ρ is a real number, 0<ρ, and ΩRn (n1) is a bounded domain with a smooth boundary Ω. By exploiting the perturbed energy method, the author proved that the solution energy was an exponential and polynomial decay.

    As far as we know, the decay property for the coupled system (1.1) has not been considered. Inspired by the literature [8], our aim in this paper is to extend some existing results for a single equation to the case of a couple viscoelastic wave system (1.1), while handling the additional difficulty caused by the nonlinear weak damping term and coupled source term. In this article, the energy decay result is new and the assumptions on the relaxation functions are weak. Then, the purpose of this paper is to study the decay property of solution energy for the system (1.1) by modifying the method used in the above literatures. Namely, under a certain class of relaxation functions and initial data, by using some inequalities and constructing a suitable Lyapunov function, we establish a general decay result for the system (1.1). Moreover, without restrictive conditions, we also obtain the optimal polynomial decay rate which seldom appears in previous literatures.

    This article is organized as follows: In Section 2, some materials needed for our work are presented. In Section 3, we show the global existence of a solution and establish the general and optimal decay rates of the solution for the system (1.1).

    In this part, some theorems and lemmas needed for our work are given. First, we make the following assumptions:

    (A1) gi:(0,+)(0,+)(i=1,2) are non-increasing C1 functions satisfying

    gi(0)>0,10g1(τ)dτ=l1>0,10g2(τ)dτ=l2>0.

    (A2) There exists two positive differentiable functions ξi(t):[0,+)(0,+) such that

    gi(t)ξi(t)gγi(t),t0,1γ<32,i=1,2,

    and the function ξi(t) satisfies

    ξi(t)0,+0ξi(t)dt=+,t>0.

    (A3) For the functions f1andf2, we assume that

    f1(u,v):=[|u+v|2(p+1)(u+v)+|u|pu|v|p+2],f2(u,v):=[|u+v|2(p+1)(u+v)+|v|pv|u|p+2].

    It is easy to verify that

    uf1(u,v)+vf2(u,v)=2(p+2)F(u,v),utf1(u,v)+vtf2(u,v)=ddtF(u,v),

    where

    F(u,v)=12(p+2)[|u+v|2(p+2)+2|uv|p+2].

    (A4) For the nonlinearity, we assume that

    {1<p<+,n=1,2,1<pnn2,n3,2m,r<+,n=1,2,2m,r2nn2,n3.

    For our work, we introduce the following functionals:

    J(t):=12(||ut||22+||vt||22)+12(1t0g1(τ)dτ)||u||22+12(1t0g2(τ)dτ)||v||22+12[(g1u)(t)+(g2v)(t)]ΩF(u,v)dx,
    I(t):=||ut||22+||vt||22+(1t0g1(τ)dτ)||u||22+(1t0g2(τ)dτ)||v||22+(g1u)(t)+(g2v)(t)2(p+2)ΩF(u,v)dx,
    E(t):=12(||ut||22+||vt||22+||ut||22+||vt||22)+12(1t0g1(τ)dτ)||u||22ΩF(u,v)dx+12[(g1u)(t)+(g2v)(t)]+12(1t0g2(τ)dτ)||v||22,

    where

    (g1u)(t)=t0g1(tτ)||u(t)u(τ)||22dτ,
    (g2v)(t)=t0g2(tτ)||v(t)v(τ)||22dτ.

    The following result is concerned with local existence and uniqueness of weak solutions to the system (1.1). We can easily obtain it by using the Faedo-Galerkin approximation methods and the Banach contraction mapping principle, which is similar to [15] with slight modification, and the process of the proof is standard, so we omit it here.

    Theorem 2.1 ([15], Theorem 2.1). Suppose that (A1), (A2), and (A4) hold and initial data (u0,u1)H10(Ω)×L2(Ω), (v0,v1)H10(Ω)×L2(Ω) are given. Then there exists a unique local weak solution (u,v) of problem (1.1) defined in [0,T] for some T>0 small enough.

    Lemma 2.2. Assume that (A1)(A4) hold. Let (u,v) be the solution of the system (1.1). Then the energy functional E(t) is non-increasing. In addition, we get the following energy inequality:

    dE(t)dt||ut||mm||vt||rr+12(g1u)(t)+12(g2v)(t)0,t0. (2.1)

    Proof. Multiplying the first two equations in system (1.1) by ut and vt, respectively, integrating over Ω, and then adding them up, we can get

    ddt[12(||ut||22+||vt||22+||u||22+||v||22+||ut||22+||vt||22)ΩF(u,v)dx]=||ut||mm||vt||rr+t0g1(tτ)Ωut(t)u(τ)dxdτ+t0g2(tτ)Ωvt(t)v(τ)dxdτ, (2.2)

    where

    t0g1(tτ)Ωut(t)u(τ)dxdτ=t0g1(tτ)Ωut(t)[u(τ)u(t)]dxdτ+t0g1(tτ)Ωut(t)u(t)dxdτ=12t0g1(tτ)(ddtΩ|u(τ)u(t)|2dx)dτ+t0g1(τ)(ddt12Ω|u(t)|2dx)dτ=12ddt[t0g1(tτ)Ω|u(τ)u(t)|2dxdτ]+12ddt[t0g1(τ)Ω|u(t)|2dxdτ]+12t0g1(tτ)Ω|u(τ)u(t)|2dxdτ12g1(t)Ω|u(t)|2dx. (2.3)

    Similarly, we have

    t0g2(tτ)Ωvt(t)v(τ)dxdτ=12ddt[t0g2(tτ)Ω|v(τ)v(t)|2dxdτ]+12ddt[t0g2(τ)Ω|v(t)|2dxdτ]+12t0g2(tτ)Ω|v(τ)v(t)|2dxdτ12g2(t)Ω|v(t)|2dx. (2.4)

    Substituting (2.3) and (2.4) into (2.2) yields

    ddt[12(||ut||22+||vt||22+||ut||22+||vt||22)+12(1t0g1(τ)dτ)||u||22+12(1t0g2(τ)dτ)||v||22+12[(g1u)(t)+(g2v)(t)]ΩF(u,v)dx]=||ut||mm||vt||rr+12[(g1u)(t)+(g2v)(t)]12g1(t)||u||2212g2(t)||v||22.

    Then, we have

    E(t)=||ut||mm||vt||rr+12[(g1u)(t)+(g2v)(t)]12g1(t)||u||2212g2(t)||v||22||ut||mm||vt||rr+12[(g1u)(t)+(g2v)(t)]0. (2.5)

    This completes the proof.

    Now, we establish the global existence theorem.

    Lemma 2.3. Assume the assumptions (A1)(A4) hold and the initial data (u0,u1)H10(Ω)×L2(Ω), (v0,v1)H10(Ω)×L2(Ω) such that

    {β=η[2(p+2)p+1E(0)]p+1<1,I(0)=I(u0,v0)>0, (2.6)

    and then we have

    I(t)=I(u(t),v(t))>0,t[0,Tm]. (2.7)

    Proof. Due to I(u0)>0, then by continuity of I(t) about variable t, there exists a maximal time 0<T<T such that

    I(t)0,t[0,T],

    which implies that t[0,T],

    J(t)=12(||ut||22+||vt||22)+12(1t0g1(τ)dτ)||u||22+12(1t0g2(τ)dτ)||v||22+12[(g1u)(t)+(g2v)(t)]ΩF(u,v)dx=12(p+2)I(t)+p+12(p+2)[(1t0g1(τ)dτ)||u||22+||ut||22+||vt||22+(1t0g2(τ)dτ)||v||22+(g1u)(t)+(g2v)(t)]p+12(p+2)[(1t0g1(τ)dτ)||u||22+(g1u)(t)+||ut||22+||vt||22+(1t0g2(τ)dτ)||v||22+(g2v)(t)]. (2.8)

    By (A1) and (2.1), we see that

    l1||u||22+l2||v||22(1t0g1(τ)dτ)||u||22+(1t0g2(τ)dτ)||v||222(p+2)p+1J(t)2(p+2)p+1E(t)2(p+2)p+1E(0). (2.9)

    By (A3), (2.25), and (2.6), we can deduce that

    2(p+2)ΩF(u,v)dxη(l1||u||22+l2||v||22)p+2=η(l1||u||22+l2||v||22)p+1(l1||u||22+l2||v||22)η[2(p+2)p+1E(0)]p+1(l1||u||22+l2||v||22),t[0,T]. (2.10)

    From (2.6) and (2.10), we infer that

    2(p+2)ΩF(u,v)dxβ(l1||u||22+l2||v||22)β(1t0g1(τ)dτ)||u||22+β(1t0g2(τ)dτ)||v||22(1t0g1(τ)dτ)||u||22+(1t0g2(τ)dτ)||v||22.

    Therefore,

    I(t)>0,t[0,T].

    By repeating these steps, T is extended to Tm.

    Theorem 2.4. Assume that (A1)(A4) hold, the initial data (u0,u1)H10(Ω)×L2(Ω), (v0,v1)H10(Ω)×L2(Ω), and satisfies (2.6). Then the solution is bounded and global in time.

    Proof. Applying Lemmas 2.2 and 2.3, we can obtain

    E(0)E(t)=J(t)+12(||ut||22+||vt||22)p+12(p+2)(l1||u||22+l2||v||22+||ut||22+||vt||22), (2.11)

    which implies that the solution of system (1.1) is global and bounded.

    Lemma 2.5 ([16]). Suppose that gC[0,], ωL1loc(0,), and 0θ1; and then we have that

    t0|g(τ)ω(τ)|dτ{t0|g(τ)|1θ|ω(τ)|dτ}1σ+1{t0|g(τ)|1+θσ|ω(τ)|dτ}σσ+1. (2.12)

    Lemma 2.6 ([8]). Assume that gi satisfies (A1) and (A2), for i=1,2, and then

    +0ξi(t)g1θi(t)dt<+,0θ<2γ. (2.13)

    Proof. From (A1) and (A2), we can obtain

    ξi(t)g1θi(t)=ξi(t)gγi(t)g1θγi(t)gi(t)g1θγi(t). (2.14)

    Integrating (2.14) over (0,+) and using the condition 0θ<2γ, we can deduce that

    +0ξi(t)g1θi(t)dt+0gi(t)g1θγi(t)dt=g2θγi(t)2θγ|+0<+. (2.15)

    Lemma 2.7 ([17]). Suppose that the conditions (A1)(A4), (2.6), and (2.11) hold, uL(0,T;H10(Ω)), and g is a continuous function. For 0<θ<1, there exists C>0 such that

    (g1u)(t)C{(t0g1θ1(τ)dτ)E(0)}γ1γ1+θ[(gγ1u)]θγ1+θ(t). (2.16)

    Proof. From the hypothesis on u and Lemma 2.7, we can obtain

    (g1u)(t)=Ωt0g1(tτ)|u(t)u(τ)|2dτdx{Ωt0g1θ1(tτ)|u(t)u(τ)|2dτdx}γ1γ1+θ{Ωt0gγ1(tτ)|u(t)u(τ)|2dτdx}θγ1+θ. (2.17)

    Now, for 0<θ<1 and the conditions (2.6) and (2.11), we have

    Ωt0g1θ1(tτ)|u(t)u(τ)|2dτdx=t0g1θ1(tτ)Ω|u(t)u(τ)|2dxdτCt0g1θ1(τ)dτ||u||22Ct0g1θ1(τ)dτE(0). (2.18)

    The proof is now complete.

    By taking θ=12, we have

    (g1u)(t)C{t0g121(τ)dτ}2γ22γ1[(gγ1u)]12γ1(t). (2.19)

    Similarly, we have

    (g2v)(t)C{t0g1/22(τ)dτ}2γ22γ1[(gγ2v)]12γ1(t). (2.20)

    The following lemmas are crucial for studying the decay of a solution.

    Lemma 2.8 ([8]). Assume that gi(t) satisfies (A1) and (A2), and (u,v) is the solution of (1.1), and then we obtain

    ξ1(t)(g1u)(t)C[E(t)]12γ1,ξ2(t)(g2v)(t)C[E(t)]12γ1. (2.21)

    Proof. Multiplying both sides of (2.19) by ξ1(t) and using (A2), (2.1), and (2.13), we can deduce that

    ξ1(t)(g1u)(t)Cξ2γ22γ11(t)[t0g121(τ)dτ]2γ22γ1ξ12γ11(t)(gγ1u)12γ1(t)C[t0ξ1(τ)g121(τ)dτ]2γ22γ1(ξ1gγ1u)12γ1(t)C[t0ξ1(τ)g121(τ)dτ]2γ22γ1(g1u)12γ1(t)C[E(t)]12γ1. (2.22)

    Similarly, we have

    ξ2(t)(g2v)(t)C[E(t)]12γ1. (2.23)

    Lemma 2.9 ([18], Lemma 4.2). There exist two positive constants γ1 and γ2 such that

    Ω|fi(u,v)|2dxγi(l1||u||22+l2||v||22)2p+3,i=1,2. (2.24)

    Lemma 2.10 ([18], Lemma 3.2). Assume that (A4) holds. Then there exists η>0 such that, for any (u,v)H10(Ω)×H10(Ω), we obtain

    ||u+v||2(p+2)2(p+2)+2||uv||p+2p+2η(l1||u||22+l2||v||22)p+2. (2.25)

    In this section, we state and prove the decay result for the global solutions. For obtaining the general decay rate estimate, let us consider the following functionals:

    L(t):=ME(t)+εχ(t)+ζ(t), (3.1)

    where M and ε are positive constants and

    χ(t):=Ωutudx+Ωvtvdx+Ωuutdx+Ωvvtdx, (3.2)
    ζ(t):=Ω(Δutut)t0g1(tτ)(u(t)u(τ))dτdx+Ω(Δvtvt)t0g2(tτ)(v(t)v(τ))dτdx. (3.3)

    Lemma 3.1. For M large enough and ε small enough, we have that the following relation

    ν1L(t)E(t)ν2L(t) (3.4)

    holds, where ν1 and ν2 are two positive constants.

    Proof. Applying the Hölder inequality, Young inequality, Sobolev embedding theorem, and (2.9), for δ>0, we have

    Ωutudx||ut||2||u||212||ut||22+12||u||2212||ut||22+C22||u||22,Ωutudx||ut||2||u||212||ut||22+12||u||22,
    ΩΔutt0g1(tτ)(u(t)u(τ))dτdxΩutt0g1(tτ)(u(t)u(τ))dτdxδ||ut||22+14δΩ(t0g1(tτ)|u(t)u(τ)|dτ)2dxδ||ut||22+1l14δ(g1u)(t),
    Ωutt0g1(tτ)(u(t)u(τ))dτdxδ||ut||22+14δΩ(t0g1(tτ)(u(t)u(τ))dτ)2dxδ||ut||22+(1l1)C24δ(g1u)(t).

    Similarly, we have

    Ωvtvdx12||vt||22+C22||v||22,Ωvtvdx12||vt||22+12||v||22,ΩΔvtt0g2(tτ)(v(t)v(τ))dτdxδ||vt||22+1l24δ(g2v)(t),Ωvtt0g2(tτ)(v(t)v(τ))dτdxδ||vt||22+(1l2)C24δ(g2v)(t).

    When M is large enough and ε is small enough, we arrive at

    L(t)ME(t)+ε2||ut||22+εC22||u||22+ε2||vt||22+εC22||v||22+ε2||ut||22+ε2||u||22+ε2||vt||22+ε2||v||22+δ||ut||22+1l14δ(g1u)(t)+δ||ut||22+(1l1)C24δ(g1u)(t)+δ||vt||22+1l24δ(g2v)(t)+δ||vt||22+(1l2)C24δ(g2v)(t)(M2+ε2+δ)||ut||22+(M2+ε2+δ)||vt||22+(M2+ε2)||ut||22+(M2+ε2)||vt||22MΩF(u.v)dx+[M2(1t0g1(τ)dτ)+εC22+ε2]||u||22+[M2(1t0g2(τ)dτ)+εC22+ε2]||v||22+[M2+1l14δ(1+C2)](g1u)(t)+[M2+1l24δ(1+C2)](g2v)(t)1ν1E(t).

    Analogously, we have

    L(t)(M2ε2δ)||ut||22+(M2ε2δ)||vt||22+(M2ε2)||ut||22+(M2ε2)||vt||22MΩF(u.v)dx+[M2(1t0g1(τ)dτ)εC22ε2]||u||22+[M2(1t0g2(τ)dτ)εC22ε2]||v||22+[M21l14δ(1+C2)](g1u)(t)+[M21l24δ(1+C2)](g2v)(t)1ν2E(t).

    Lemma 3.2. Under the assumptions (A1)(A4), let (u,v) be the solution of system (1.1). Then the functional

    χ(t)=Ωutudx+Ωvtvdx+Ωuutdx+Ωvvtdx (3.5)

    satisfies

    χ(t)||ut||22+||vt||22+2(p+2)ΩF(u,v)dx+(C24αl12)u22+1l12l1(g1u)(t)+(C24αl22)v22+1l22l2(g2v)(t)+[1+αC2m2(2(p+2)E(0)p+1)m2]||ut||22+[1+αC2r2(2(p+2)E(0)p+1)r2]||vt||22. (3.6)

    Proof. Taking a time derivative of (3.5) and applying Eq (1.1), we can deduce

    χ(t)=Ωuttudx+||ut||22+Ωvttvdx+||vt||22+Ωuuttdx+||ut||22+Ωvvttdx+||vt||22=||ut||22||u||22+||ut||22+Ωt0g1(tτ)u(τ)dτu(t)dτdx+||vt||22||v||22+||vt||22+Ωt0g2(tτ)v(τ)dτv(t)dτdxΩ|ut|m2utudx+Ωuf1dxΩ|vt|r2vtudx+Ωvf2dx. (3.7)

    We now estimate the third term on the right-hand side of (3.7), yielding

    Ωu(t)t0g1(tτ)u(τ)dτdx12||u||22+12Ω(t0g1(tτ)u(τ)dτ)2dx12||u||22+12Ω(t0g1(tτ)(|u(τ)u(t)|+|u(t)|)dτ)2dx, (3.8)

    at present. We estimate the second term in the right-hand side of (3.8), for η1>0, and we arrive at

    Ω(t0g1(tτ)(|u(τ)u(t)|+|u(t)|)dτ)2dxΩ(t0g1(tτ)|u(τ)u(t)|dτ)2dx+Ω(t0g1(tτ)|u(t)|dτ)2dx+2Ω(t0g1(tτ)|u(τ)u(t)|dτ)(t0g1(tτ)|u(t)|dτ)dx(1+1η1)Ω(t0g1(tτ)|u(τ)u(t)|dτ)2dx+(1+η1)Ω(t0g1(tτ)|u(t)|dτ)2dx(1+1η1)(1l1)(g1u)(t)+(1+η1)(1l1)2u22. (3.9)

    Inserting (3.9) into (3.8), we get

    Ωu(t)t0g1(tτ)u(τ)dτdx12(1+(1+η1)(1l1)2)u22+12(1+1η1)(1l1)(g1u)(t). (3.10)

    Similarly, for η2>0, we have

    Ωv(t)t0g2(tτ)v(τ)dτdx12(1+(1+η2)(1l2)2)v22+12(1+1η2)(1l2)(g2v)(t). (3.11)

    For the fourth term in the right-hand side of (3.7), for α>0, we can get

    Ω|ut|m2utudxα||ut||2m22m2+14α||u||22αC2m2||ut||2m22+C24α||u||22αC2m2(2(p+2)E(0)p+1)m2||ut||22+C24α||u||22. (3.12)

    Similarly, we can get

    Ω|vt|r2vtvdxαC2r2(2(p+2)E(0)p+1)r2||vt||22+C24α||v||22. (3.13)

    Inserting (3.10)–(3.13) into (3.7), and choosing

    η1=l1/(1l1),η2=l2/(1l2),

    we can deduce

    χ(t)||ut||22+||vt||22+2(p+2)ΩF(u,v)dx+(C24αl12)u22+1l12l1(g1u)(t)+(C24αl22)v22+1l22l2(g2v)(t)+[1+αC2m2(2(p+2)E(0)p+1)m2]||ut||22+[1+αC2r2(2(p+2)E(0)p+1)r2]||vt||22. (3.14)

    Lemma 3.3. Under the assumptions (A1)(A4), letting (u,v) be the solution of (1.1), then the functional

    ζ(t)=Ω(Δutut)t0g1(tτ)(u(t)u(τ))dτdx+Ω(Δvtvt)t0g2(tτ)(v(t)v(τ))dτdx (3.15)

    satisfies

    ζ(t)δ(1+2(1l1)2+γ1l1(2(p+2)p+1E(0))2(p+1))||u||22+(1l1)(2δ+12δ+C22δ)(g1u)(t)g1(0)4δ(1+C2)(g1u)(t)+[δt0g1(τ)dτ+δC2m2(2(p+2)E(0)p+1)m2]||ut||22(t0g1(τ)dτδ))||ut||22+δ(1+2(1l2)2+γ2l2(2(p+2)p+1E(0))2(p+1))||v||22+(1l2)(2δ+12δ+C22δ)(g2v)(t)+[δt0g2(τ)dτ+δC2r2(2(p+2)E(0)p+1)r2]||vt||22g2(0)4δ(1+C2)(g2v)(t)(t0g2(τ)dτδ))||vt||22. (3.16)

    Proof. Taking the derivative of ζ(t) with respect to variable t, we have

    ζ(t)=Ω(Δuttutt)t0g1(tτ)(u(t)u(τ))dτdx+Ω(Δutut)t0g1(tτ)(u(t)u(τ))dτdx(t0g1(τ)dτ)||ut||22(t0g1(τ)dτ)||ut||22+Ω(Δvttvtt)t0g2(tτ)(v(t)v(τ))dτdx+Ω(Δvtvt)t0g1(tτ)(v(t)v(τ))dτdx(t0g2(τ)dτ)||vt||22(t0g2(τ)dτ)||vt||22. (3.17)

    Inserting Eq (1.1) into (3.17), we get

    ζ(t)=ΩΔut0g1(tτ)(u(t)u(τ))dτdx+Ω(t0g1(tτ)Δu(τ)dτ)(t0g1(tτ)(u(t)u(τ))dτ)dx+Ω|ut|m2utt0g1(tτ)(u(t)u(τ))dτdxΩf1(u,v)t0g1(tτ)(u(t)u(τ))dτdx+ΩΔutt0g1(tτ)(u(t)u(τ))dτdxΩutt0g1(tτ)(u(t)u(τ))dτdx(t0g1(τ)dτ)||ut||22(t0g1(τ)dτ)||ut||22ΩΔvt0g2(tτ)(v(t)v(τ))dτdx+Ω(t0g2(tτ)Δv(τ)dτ)(t0g2(tτ)(v(t)v(τ))dτ)dx+Ω|vt|r2vtt0g2(tτ)(v(t)v(τ))dτdxΩf2(u,v)t0g2(tτ)(v(t)v(τ))dτdx+ΩΔvtt0g2(tτ)(v(t)v(τ))dτdxΩvtt0g2(tτ)(v(t)v(τ))dτdx(t0g1(τ)dτ)||ut||22(t0g1(τ)dτ)||ut||22. (3.18)

    We now estimate the terms in the right-hand side of (3.18), for δ>0, and we can deduce

    ΩΔut0g1(tτ)(u(t)u(τ))dτdxΩut0g1(tτ)(u(t)u(τ))dτdxδ||u||22+1l14δ(g1u)(t), (3.19)
    Ω(t0g1(tτ)Δu(τ)dτ)(t0g1(tτ)(u(t)u(τ))dτ)dxΩ(t0g1(tτ)u(τ)dτ)(t0g1(tτ)(u(t)u(τ))dτ)dxδΩ(t0g1(tτ)u(τ)dτ)2dx+14δΩ(t0g1(tτ)(u(t)u(τ))dτ)2dxδΩ(t0g1(tτ)(|u(τ)u(t)|+|u(t)|)dτ)2dx+14δt0g1(tτ)dsΩt0g1(tτ)|u(t)u(τ)|2dτdx2δΩ(t0g1(tτ)|u(τ)u(t)|dτ)2dx+2δ(1l1)2Ω|u|2dx+14δ(1l1)(g1u)(t)(2δ+14δ)(1l1)(g1u)(t)+2δ(1l1)2||u||22, (3.20)
    Ω|ut|m2utt0g1(tτ)(u(t)u(τ))dτdxδut2m22m2+14δΩ(t0g1(tτ)(u(t)u(τ))dτ)2dxδC2m2ut2m22+(1l1)C24δΩt0g1(tτ)(u(t)u(τ))2dτdxδC2m2(2(p+2)E(0)p+1)m2ut22+(1l1)C24δ(g1u)(t). (3.21)

    For the fourth term, it follows from Lemma 2.9 that

    Ωf1(u,v)t0g1(tτ)(u(t)u(τ))dτdxδΩf21(u,v)dx+(1l1)C24δ(g1u)(t)δγ1(l1||u||22+l2||v||22)2p+3+(1l1)C24δ(g1u)(t)δγ1(l1||u||22+l2||v||22)2(p+1)(l1||u||22+l2||v||22)+(1l1)C24δ(g1u)(t)δγ1(2(p+2)p+1E(0))2(p+1)(l1||u||22+l2||v||22)+(1l1)C24δ(g1u)(t), (3.22)
    ΩΔutt0g1(tτ)(u(t)u(τ))dτdxΩutt0g1(tτ)(u(t)u(τ))dτdxδ||ut||22+14δΩ(t0g1(tτ)|u(t)u(τ)|dτ)2dxδ||ut||22g1(0)4δ(g1u)(t), (3.23)
    Ωutt0g1(tτ)(u(t)u(τ))dτdxδ||ut||22+14δΩ(t0g1(tτ)|u(t)u(τ)|dτ)2dxδ||ut||22g1(0)C24δ(g1u)(t). (3.24)

    Similarly, we have

    ΩΔvt0g2(tτ)(v(t)v(τ))dτdxδ||v||22+1l24δ(g2v)(t), (3.25)
    Ω(t0g2(tτ)Δv(τ)dτ)(t0g2(tτ)(v(t)v(τ))dτ)dx(2δ+14δ)(1l2)(g2v)(t)+2δ(1l2)2||v||22, (3.26)
    Ω|vt|r2vtt0g2(tτ)(v(t)v(τ))dτdxδC2r2(2(p+2)E(0)p+1)r2vt22+(1l2)C24δ(g2v)(t), (3.27)
    Ωf2(u,v)t0g2(tτ)(v(t)v(τ))dτdxδγ2(2(p+2)p+1E(0))2(p+1)(l1||u||22+l2||v||22)+(1l2)C24δ(g2v)(t), (3.28)
    ΩΔvtt0g2(tτ)(v(t)v(τ))dτdxδ||vt||22g2(0)4δ(g2v)(t), (3.29)
    Ωvtt0g2(tτ)(v(t)v(τ))dτdxδ||vt||22g2(0)C24δ(g2v)(t). (3.30)

    Combining (3.18)–(3.30), we can deduce that

    ζ(t)δ(1+2(1l1)2+γ1l1(2(p+2)p+1E(0))2(p+1))||u||22+(1l1)(2δ+12δ+C22δ)(g1u)(t)g1(0)4δ(1+C2)(g1u)(t)+[δt0g1(τ)dτ+δC2m2(2(p+2)E(0)p+1)m2]||ut||22(t0g1(τ)dτδ))||ut||22+δ(1+2(1l2)2+γ2l2(2(p+2)p+1E(0))2(p+1))||v||22+(1l2)(2δ+12δ+C22δ)(g2v)(t)+[δt0g2(τ)dτ+δC2r2(2(p+2)E(0)p+1)r2]||vt||22g2(0)4δ(1+C2)(g2v)(t)(t0g2(τ)dτδ))||vt||22. (3.31)

    Theorem 3.4. Let initial data (u0,u1),(v0,v1)H10(Ω)×L2(Ω) be given and satisfy (2.6). Assume that (A1)(A4) hold. Then, for each t0>0, there exist strictly positive constants k1,k2, and k3 such that the solution of system (1.1) satisfies, for all tt0,

    E(t)k1ek2tt0ξ(τ)dτ,γ=1, (3.32)
    E(t)k3[11+tt0ξ2γ1(τ)dτ]12γ2,1<γ<32, (3.33)

    where ξ(t):=min{ξ1(t),ξ2(t)}.

    Proof. Taking a derivative of (3.1), we can obtain

    L(t)=ME(t)+εχ(t)+ζ(t). (3.34)

    Since g1 and g2 are continuous and gi(0)>0, then there exists tt0>0 such that

    t0g1(τ)dτt00g1(τ)dτ=g0>0, (3.35)

    and

    t0g2(τ)dτt00g2(τ)dτ=g0>0. (3.36)

    By using (2.1), (3.6), (3.16), and (3.34), we arrive at

    L(t)(g0δε)||ut||22(g0δε)||vt||22[(l12C24α)εδ(1+2(1l1)2+γ1l1(2(p+2)p+1E(0))2(p+1))]||u||22[(l22C24α)εδ(1+2(1l2)2+γ2l2(2(p+2)p+1E(0))2(p+1))]||v||22+[M2g1(0)4δ(1+C2)](g1u)(t)+[M2g2(0)4δ(1+C2)](g2v)(t)+(1l1)[ε2l1+2δ+12δ+C22δ](g1u)(t)+(1l2)[ε2l2+2δ+12δ+C22δ](g2v)(t)[g0δδC2m2(2(p+2)E(0)p+1)m2ε(1+αC2m2(2(p+2)E(0)p+1)m2)]||ut||22[g0δδC2r2(2(p+2)E(0)p+1)r2ε(1+αC2r2(2(p+2)E(0)p+1)r2)]||vt||22M||ut||mmM||vt||rr+2(p+2)εΩF(u,v)dx. (3.37)

    At this point, we choose ε and δ small enough such that

    A1:=g0δε>0,A2:=(l12C24α)εδ(1+2(1l1)2+γ1l1(2(p+2)p+1E(0))2(p+1))>0,A3:=(l22C24α)εδ(1+2(1l2)2+γ2l2(2(p+2)p+1E(0))2(p+1))>0,A4:=g0δδC2m2(2(p+2)E(0)p+1)m2ε[1+αC2m2(2(p+2)E(0)p+1)m2]>0,A5:=g0δδC2r2(2(p+2)E(0)p+1)r2ε[1+αC2r2(2(p+2)E(0)p+1)r2]>0.

    Once ε and δ are fixed, we choose ital "M" sufficiently large such that

    A6:=M2g1(0)4δ(1+C2)>0,A7:=M2g2(0)4δ(1+C2)>0.

    Hence, the inequality (3.37) can be changed to

    L(t)A1||ut||22A1||vt||22A2||u||22A3||v||22A4||ut||22A5||vt||22+A6(g1u)(t)+A7(g2v)(t)M||ut||mmM||vt||rr+2(p+2)εΩF(u,v)dx+(1l1)[ε2l1+2δ+12δ+C22δ](g1u)(t)+(1l2)[ε2l2+2δ+12δ+C22δ](g2v)(t). (3.38)

    Then, there exist two positive constants m1 and m2 such that

    L(t)m1E(t)+m2[(g1u)(t)+(g2u)(t)],tt0. (3.39)

    We let ξ(t):=min{ξ1(t),ξ2(t)}, since ξ1(t) and ξ2(t) are non-increasing and non-negative functions, and then the function ξ(t) is a non-increasing and non-negative function. In the case when γ=1, by multiplying both sides of (3.39) by ξ(t) and using (A2) and (2.1), we can deduce that

    ξ(t)L(t)m1ξ(t)E(t)+m2ξ(t)(g1u)(t)+m2ξ(t)(g2v)(t)m1ξ(t)E(t)+m2ξ1(t)(g1u)(t)+m2ξ2(t)(g2v)(t)m1ξ(t)E(t)+m2(ξ1g1u)(t)+m2(ξ2g2v)(t)m1ξ(t)E(t)m2(g1u)(t)m2(g2v)(t)m1ξ(t)E(t)m2E(t),tt0. (3.40)

    We let F(t):=ξ(t)L(t)+m2E(t), which is equivalent to E(t), since the function L(t) is also equivalent to E(t) and E(t)0, ξ(t)0. Then we can deduce that ξ(t)L(t)0. Then from (3.40), for some m3,m4>0, we can arrive at

    F(t)=ξ(t)L(t)+ξ(t)L(t)+m2E(t)ξ(t)L(t)+m2E(t)m3ξ(t)E(t)m4ξ(t)F(t). (3.41)

    A simple integration of (3.41) leads to

    F(t)F(t0)em4tt0ξ(τ)dτ,tt0. (3.42)

    In the case when 1<γ<32, we again consider (3.40) and use Lemma 2.8 to get, for C1>0,

    ξ(t)L(t)m1ξ(t)E(t)+m2ξ(t)(g1u)(t)+m2ξ(t)(g2v)(t)m1ξ(t)E(t)+m2ξ1(t)(g1u)(t)+m2ξ2(t)(g2v)(t)m1ξ(t)E(t)+C1[E(t)]12γ1,tt0. (3.43)

    Multiplying both sides of (3.43) by ξσ(t)Eσ(t), where σ=2γ2, then applying the Young inequality, we can infer that

    ξσ+1(t)Eσ(t)L(t)m1ξσ+1(t)Eσ+1(t)+C1(ξE)σ(t)[E(t)]1σ+1,m1ξσ+1(t)Eσ+1(t)+C1[ε(ξE)σ+1(t)CεE(t)]=(m1C1ε)(ξE)σ+1(t)C1CεE(t),tt0. (3.44)

    We choose ε<m1C1 such that m5:=m1C1ε>0 and thanks to ξ(t)0 and E(t)0, we can deduce that

    (ξσ+1EσL)(t)=(σ+1)ξσ(t)ξ(t)Eσ(t)L(t)+σξσ+1(t)Eσ1(t)E(t)L(t)+ξσ+1(t)Eσ(t)L(t)ξσ+1(t)Eσ(t)L(t)m5(ξE)σ+1(t)C1CεE(t),tt0. (3.45)

    Then we have

    (ξσ+1EσL+C1CεE)(t)m5(ξE)σ+1(t).

    Let G:=ξσ+1EσL+C1CεEE. Then we deduce that

    G(t)m5(ξE)σ+1(t)m6ξ2γ1G2γ1,tt0,m6>0.

    By integrating over (t0,t) and applying the condition that GE, we arrive at

    E(t)K[11+tt0ξ2γ1(τ)dτ]12γ2,tt0. (3.46)

    This completes the proof.

    In this paper, we consider a system of two viscoelastic wave equations with Dirichlet boundary conditions. By constructing a suitable Lyapunov function, we establish a general decay result. Moreover, without restrictive conditions, we also obtain the optimal polynomial decay result.

    Qian Li: Conceptualization, methodology, writing original draft, writing and editing, formal analysis, funding acquisition; Yanyuan Xing: methodology, writing and editing, formal analysis supervision, funding acquisition. Both authors have read and approved the final version of the manuscript for publication.

    The authors would like to thank the referees for many valuable comments and suggestions. This work is supported by the Fundamental Science Research Projects of Shanxi Province (No. 202203021222332, 202103021223379), China.

    The authors declare no conflicts of interest.



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