Research article

An application of Pascal distribution involving Kamali type related to leaf like domain

  • Received: 08 February 2023 Revised: 25 March 2023 Accepted: 29 March 2023 Published: 10 May 2023
  • MSC : 52A41, 32W50

  • This paper aims to study the Geometric properties of analytic function in the open unit disk. In the present investigation, we obtain some geometric properties of Pascal distribution involving Kamali type related to leaf like domain. In this paper, we find coefficient inequality, Radii Properties, convolution product, partial sum of the class Σ(δ,Φ,β,s,t,m). Furthermore, we examine the distortion bounds belonging to the same class.

    Citation: K. Saritha, K. Thilagavathi. An application of Pascal distribution involving Kamali type related to leaf like domain[J]. AIMS Mathematics, 2023, 8(7): 16511-16527. doi: 10.3934/math.2023844

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  • This paper aims to study the Geometric properties of analytic function in the open unit disk. In the present investigation, we obtain some geometric properties of Pascal distribution involving Kamali type related to leaf like domain. In this paper, we find coefficient inequality, Radii Properties, convolution product, partial sum of the class Σ(δ,Φ,β,s,t,m). Furthermore, we examine the distortion bounds belonging to the same class.



    Let G be the holomorphic function in the open unit disc U which is defined by

    ȷ(ζ)=ζ+k=2bkζk,ζU, (1.1)

    and let k be the subclass of G consisting of functions of the form

    ȷ(ζ)=ζk=2bkζk,ζU, (1.2)

    which are univalent and normalized in U. For ȷG and of the form (1.1) and ı(ζ)G given by

    ı(ζ)=ζ+k=2ckζk,ζU, (1.3)

    convolution of ȷ(ζ) and ı(ζ) is given by

    (ȷı)(ζ)=ζ+k=2bkckζk,ζU. (1.4)

    Let ȷ(ζ) and ı(ζ) be holomorphic functions and b and c are coefficient of the function which is belonging to G, so we state that ȷ is subordinate to ı it is denoted by ȷı (see [10]), then there is a Schwarz function that is holomorphic in U including (0)=0 and |(ζ)|<1 for every ζU, such that ȷ(ζ)=ı((ζ)), for ζU. Moreover, we have ȷ is univalent in U.

    ȷıȷ(0)=ı(0)andȷ(U)ı(U).

    A Variable Y is said to have the Pascal distribution if it takes the values 0, 1, 2, 3... with the probabilities (1t)m,tm(1t)m1!,t2m(m+1)(1t)m2!,t3m(m+1)(m+2)(1t)m3!, ... respectively, where t,m are called the parameters and thus,

    P(Y=k)=(k+m1m1)tk(1t)m,k{0,1,2,...}. (1.5)

    Many essentially interesting proof techniques involving a power series, whose co-efficients are probabilities of the Pascal distribution series introduced by El-Deeb et al. [15] that is

    Qmt(ζ)=ζ+(k+m1m1)t(k1)(1t)mζk,kU,(m1,0t1). (1.6)

    The family of an holomorphic function as follows

    E={F:F(ζ)=ȷQmt(ζ)=ζ+k=2(k+m2m1)tk1(1t)mbkζk,ȷG}. (1.7)

    Muhammet Kamali et al. [11] introduced the class of function and gave the following condition.

    Let Φ:UC be holomorphic and for 0δ1. We define the class Σ(δ,Φ,β,s,t,m) as

    Σ(δ,Φ,β,s,t,m)={ȷG:δζ3F(ζ)+(1+2δ)F(ζ)ζ2+ζF(ζ)δζ2F(ζ)+ζF(ζ)}=ζ+k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk. (1.8)

    Atshan et al. [19] was stuided in the class of function and the following condition is given in Eq (1.8). Paprocki and Sokół [12] studied the class of analytic and univalent functions defined by S(α,b), where α1,b12. For the choice of α=1, the class of S(α,b) investigated by Janowski [9]. For the choice of α=2,b=1, the class S(2,1) investigated by Sokół [18]. It is easy to see that fS(α,b) iff

    ζf(ζ)f(ζ)q0(ζ)=(1+ζ1+(1bb)ζ)1α,q0(0)=1,

    which is a leaf like set.

    Making use of this the class C(β,s) and is a leaf like set. For the choice of β=2,s=1, the class C(2,1) are investigated by Paprocki and Sokół [12]. The concept of leaf like domain was investigated by Paprocki and Sokół [12]. For more details related to the leaf-like domain, one may refer to the recent papers (see[1,17]).

    For fixed parameter β,s we say that FG is in the class Σ(δ,Φ,β,s,t,m) if it satisfies the following subordination condition.

    1+ζ(Σt,mβ,sF(ζ))(Σt,mβ,sF(ζ))(1+ω(ζ)1+(1ss)ω(ζ))1β. (1.9)

    In view of the definition of subordination is equivalent to the following conditions:

    |ω(ζ)|<1.|[(Σt,mβ,s)+ζ(Σt,mβ,s)]β[(Σt,mβ,s)]β[(Σt,mβ,s)]β(1ss)[(Σt,mβ,s)+ζ(Σt,mβ,s)]β|<1. (1.10)

    This is used to obtain geometric properties like coefficient inequality, Radius of starlikeness, convolution properties, partial sum of the class Σ(δ,Φ,β,s,t,m) involving Pascal distribution series related to the leaf like domain. The following theorem gives a necessary and sufficient condition for a function F to be in the class Σ(δ,Φ,β,s,t,m).

    Theorem 2.1. Let a function FG which is belonging to the class Σ(δ,Φ,β,s,t,m) if only if

    k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(βk(s+1)+s(12β)s)bk2s1s. (2.1)

    Proof. Let FΣ(δ,Φ,β,s,t,m) then,

    1+ζ(Σt,mβ,sF(ζ))(Σt,mβ,sF(ζ))(1+ω(ζ)1+(1ss)ω(ζ))1β. (2.2)

    Therfore, there exists an holomorphic function ω such that,

    ω(ζ)=[(Σt,mβ,s)+ζ(Σt,mβ,s)]β[(Σt,mβ,s)]β[(Σt,mβ,s)]β(1ss)[(Σt,mβ,s)+ζ(Σt,mβ,s)]β. (2.3)

    Hence,

    |ω(ζ)|=|[(Σt,mβ,s)+ζ(Σt,mβ,s)]β[(Σt,mβ,s)]β[(Σt,mβ,s)]β(1ss)[(Σt,mβ,s)+ζ(Σt,mβ,s)]β|<1, (2.4)

    let

    [(Σt,mβ,s)+ζ(Σt,mβ,s)]β[(Σt,mβ,s)]β[(Σt,mβ,s)]β(1ss)[(Σt,mβ,s)+ζ(Σt,mβ,s)]β<1.
    [(Σt,mβ,s)+ζ(Σt,mβ,s)]β[(Σt,mβ,s)]β<[(Σt,mβ,s)]β(1ss)[(Σt,mβ,s)+ζ(Σt,mβ,s)]β.

    To solve this we get,

    [(Σt,mβ,s)+ζ(Σt,mβ,s)]β<2[(Σt,mβ,s)]β(1ss)[(Σt,mβ,s)+ζ(Σt,mβ,s)]β.

    Here,

    [(Σt,mβ,s)+ζ(Σt,mβ,s)]β=1+βk=2(k+m2m1)tk1(1t)mk2(δkδ+1)bkζn1, (2.5)

    and

    2[(Σt,mβ,s)]β(1ss)[(Σt,mβ,s)+ζ(Σt,mβ,s)]β=(3s1s)+k=2(k+m2m1)tk1(1t)m×k2(δkδ+1)(2βsβk+ss)bkζn1. (2.6)

    Compare the Eqs (2.4) and (2.5) we get,

    k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(βk(s+1)+s(12β)s)bk2s1s.

    Conversely, let

    k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(βk(s+1)+s(12β)s)bk2s1s.

    Then from Eq (1.10), we have

    2[(Σt,mβ,s)]β(1ss)[(Σt,mβ,s)+ζ(Σt,mβ,s)]β=(3s1s)+k=2(k+m2m1)tk1(1t)m×k2(δkδ+1)(2βsβk+ss)bkζn1.[(Σt,mβ,s)+ζ(Σt,mβ,s)]β<2[(Σt,mβ,s)]β(1ss)[(Σt,mβ,s)+ζ(Σt,mβ,s)]β. (2.7)
    |ω(ζ)|=|[(Σt,mβ,s)+ζ(Σt,mβ,s)]β[(Σt,mβ,s)]β[(Σt,mβ,s)]β(1ss)[(Σt,mβ,s)+ζ(Σt,mβ,s)]β|<1. (2.8)

    Thus,

    ω(ζ)=[(Σt,mβ,s)+ζ(Σt,mβ,s)]β[(Σt,mβ,s)]β[(Σt,mβ,s)]β(1ss)[(Σt,mβ,s)+ζ(Σt,mβ,s)]β, (2.9)

    this proves that,

    1+ζ(Σt,mβ,sF(ζ))(Σt,mβ,sF(ζ))(1+ω(ζ)1+(1ss)ω(ζ))1β, (2.10)

    and hence FΣ(δ,Φ,β,s,t,m).

    The concept of neighborhoods was first introduced by Goodman [7] and then generalized by Ruscheweyh [13] and studied by some authors, Atshan [2] and Atshan and Kulkarni [3].

    Theorem 3.1. Let a function FG is in the class FΣ(δ,Φ,β,s,t,m) then,

    Ω=2s1(k+m2m1)tk1(1t)mk(δkδ+1)(βk(s+1)+s(12β)).

    Proof. It follows from Theorem 2.1 that if FΣt,mβ,sF1(ζ) then we have,

    k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(βk(s+1)+s(12β)s)bk2s1s.

    Hence

    kbk=(2s1s)s(k+m2m1)tk1(1t)mk(δkδ+1)(βk(s+1)+s(12β)),

    which implies that

    kbk=2s1(k+m2m1)tk1(1t)mk(δkδ+1)(βk(s+1)+s(12β))=Ω.

    Theorem 4.1. For functions Fj(ζ)(j=1,2) defined by (1.2) let F1(ζ)Σt,mβ,s and F2(ζ)Σt,mβ,s then F1(ζ)F2(ζ)Σt,mβ,s where

    §=βk(s+1)+s(12β)[1βk(r+1)+r(12β)](2s1)(2r1)[β(k2)+1]2[βk(s+1)+s(12β)][βk(r+1)+r(12β)]Ψ(k).

    Here,

    Ψ(k)=(k+m2m1)tk1(1t)mk2(δkδ+1).

    Proof. In the view of Theorem 2.1 it suffices to prove that

    k=2βk(§+1)+§(12β)2§1Ψ(k)bk,1bk,21,

    where § is defined by Theorem 2.1 under the hypothesis it follows from Theorem 2.1 and the Cauchy-Schwarz inequality that

    k=2[βk(s+1)+s(12β)]12[βk(r+1)+r(12β)]12(2s1)(2r1)Ψ(k)bk,1bk,21. (4.1)

    To find largest § such that

    n=2βk(§+1)+§(12β)2§1Ψ(k)bk,1bk,2k=2[βk(s+1)+s(12β)]12[βk(r+1)+r(12β)]12(2s1)(2r1)Ψ(k)bk,1bk,21,

    or equivalently that

    bk,1bk,2[βk(s+1)+s(12β)]12[βk(r+1)+r(12β)]12(2s1)(2r1)×2§1βk(§+1)+§(12β).

    From (2.10) we have,

    bk,1bk,2(2s1)(2r1)[βk(s+1)+s(12β)]12[βk(r+1)+r(12β)]12Ψ(k).

    It is sufficient to find the largest Ψ such that

    (2s1)(2r1)[βk(s+1)+s(12β)]12[βk(r+1)+r(12β)]12Ψ(k)[βk(s+1)+s(12β)]12[βk(r+1)+r(12β)]12(2s1)(2r1)×2§1βk(§+1)+§(12β),

    which implies to

    §=βk(s+1)+s(12β)[1βk(r+1)+r(12β)](2s1)(2r1)[β(k2)+1]2[βk(s+1)+s(12β)][βk(r+1)+r(12β)]Ψ(k).

    Here,

    Ψ(k)=(k+m2m1)tk1(1t)mk2(δkδ+1).

    This completes the proof.

    A distortion property for the functions in the class Σ(δ,Φ,β,s,t,m) is given as follows.

    Theorem 5.1. If the function FΣt,mβ,s then,

    R(2s1)2(2β+s)R2|Σt,mβ,s(ζ)|R+(2s1)2(2β+s)R2

    with equality for

    Σt,mβ,s(ζ)=ζ(2s1)2(2β+s)ζ2.

    Proof. If FΣt,mβ,s, Theorem 2.1 yields the inequality,

    k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(βk(s+1)+s(12β)s)bk2s1s.

    Therefore, we have

    k=2bk=2s1(mm1)t(1t)m4(δ+1)(2β(s+1)+s(12β)).

    Thus,

    |Σt,mβ,s|ζ+k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζkR+R2(mm1)t(1t)m2(δ+1)k=2bkR+R2(mm1)t(1t)m2(δ+1)×2s1(mm1)t(1t)m4(δ+1)(2β(s+1)+s(12β))R+(2s1)2(2β+s)R2.

    Similarly,

    |Σt,mβ,s|ζk=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζkRR2(mm1)t(1t)m2(δ+1)k=2bkRR2(mm1)t(1t)m2(δ+1)×2s1(mm1)t(1t)m4(δ+1)(2β(s+1)+s(12β))R(2s1)2(2β+s)R2.

    Theorem 5.2. If the function FΣt,mβ,s then,

    1(2s1)(2β+s)R|(Σt,mβ,s(ζ))|1+(2s1)(2β+s)R

    with equality for

    Σt,mβ,s(ζ)=1(2s1)2(2β+s)ζ.

    Proof. If FΣt,mβ,s, Theorem 2.1 yields the inequality,

    k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(βk(s+1)+s(12β)s)bk2s1s.

    Therefore, we have

    k=2kbk=2s1(mm1)t(1t)m2(δ+1)(2β(s+1)+s(12β)).

    Thus,

    |(Σt,mβ,s)|1+k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkkζk11+R(mm1)t(1t)m2(δ+1)k=2kbk1+R(mm1)t(1t)m2(δ+1)×2s1(mm1)t(1t)m2(δ+1)(2β(s+1)+s(12β))1+(2s1)(2β+s)R.

    Similarly,

    |(Σt,mβ,s)|1k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkkζk11R(mm1)t(1t)m2(δ+1)k=2kbk1R(mm1)t(1t)m2(δ+1)2s1(mm1)t(1t)m2(δ+1)(2β(s+1)+s(12β))1(2s1)(2β+s)R.

    Theorem 5.3. The class FΣ(δ,Φ,β,s,t,m) is closed under convex linear combinations.

    Proof. Suppose that the functions Σt,mβ,sF1(ζ), Σt,mβ,sF2(ζ) defined by

    Σ(δ,Φ,β,s,t,m)Fi(ζ)=ζ+k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk,(i=1,2..,FG)

    by set

    Σt,mβ,sF(ζ)=Σt,mβ,sF1(ζ)+(1)Σt,mβ,sF2(ζ).

    we find from (2.7) that,

    Σt,mβ,sF(ζ)=ζ+k=2{ck,1+(1)ck,2}ζk(01),ζG.

    In view of Theorem 2.1 we have,

    k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(βk(s+1)+s(12β)s){ck,1+(1)ck,2}=k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(βk(s+1)+s(12β)s){ck,1+(1)ck,2}+(1)k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(βk(s+1)+s(12β)s){ck,1+(1)ck,2}(2s1s)+2s1s(2s1s)=2s1s.

    Theorem 6.1. (i) If the function FG be defined by (1.1) is in the class Σ(δ,Φ,β,s,t,m), then F is starlike of order ρ in the disk |ζ|<r1 (i.e) (ζ(Σt,mβ,sF(ζ))Σt,mβ,sF(ζ))>ρ(|ζ|<r1;0ρ1) where,

    r1=(1ρρ+k2)(1k1)(k(αk(s+1)+s(12α))2s1)(1k1).

    (ii) If the function FG be defined by (1.1) is in the class Σ(δ,Φ,β,s,t,m), then F is convex of order ρ in the disk |ζ|<r2 (i.e) (ζΣt,mβ,sF(ζ)Σt,mβ,sF(ζ))>ρ(|ζ|<r2;0ρ1) where,

    r2=(1ρρ+k2)(1k1)((δkδ+1)(αk(s+1)+s(12α))2s1)(1k1).

    Proof. Let FG is starlike of order ρ we have,

    |ζ(Σt,mβ,sF(ζ))Σt,mβ,sF(ζ1|<1ρ. (6.1)

    Thus,

    |k=2(k1)(k+m2m1)tk1(1t)mk(δkδ+1)bkζkζ+k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk|1ρ. (6.2)

    Hence, (2.9) holds true if

    k=2(k1)(k+m2m1)tk1(1t)mk(δkδ+1)bkζk(1ρ)(ζ+k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk).k=2(ρ+k2)(k+m2m1)tk1(1t)mk(δkδ+1)bkζk11ρ.k=2(ρ+k21ρ)(k+m2m1)tk1(1t)mk(δkδ+1)bkζk11.

    From Theorem 2.1, we have

    k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(βk(s+1)+s(12β)s)bk2s1s.
    k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(2s1s)(βk(s+1)+s(12β)s)bk1.

    We say that,

    k=2(ρ+k21ρ)(k+m2m1)tk1(1t)mk(δkδ+1)bkζk1k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(2s1s)(βk(s+1)+s(12β)s)bk.

    Equivalently,

    |ζ|k1=k(βk(s+1)+s(12β))(1ρ)(2s1)(ρ+k2).

    Therefore,

    |ζ|=(1ρρ+k2)(1k1)(k(αk(s+1)+s(12α))2s1)(1k1).

    Hence FG is starlike of order ρ.

    (ⅱ) Let FG is convex of order ρ we have,

    |ζΣt,mβ,sF(ζ)Σt,mβ,sF(ζ)|<1ρ. (6.3)
    |ζ(k=2(k1)(k+m2m1)tk1(1t)mk2(δkδ+1)bkζk2)1+k=2(k+m2m1)tk1(1t)mk2(δkδ+1)bkζk1|1ρ. (6.4)

    Hence (2.9) holds true if

    k=2(k1)(k+m2m1)tk1(1t)mk2(δkδ+1)bkζk1(1ρ)(ζ+k=2(k+m2m1)tk1(1t)mk2(δkδ+1)bkζk1).k=2(ρ+k2)(k+m2m1)tk1(1t)mk2(δkδ+1)bkζk11ρ.k=2(ρ+k21ρ)(k+m2m1)tk1(1t)mk2(δkδ+1)bkζk11.

    From Theorem 2.1, we have

    k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(βk(s+1)+s(12β)s)bk2s1s.
    k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(2s1s)(βk(s+1)+s(12β)s)bk1.

    We say that,

    k=2(ρ+k21ρ)(k+m2m1)tk1(1t)mk2(δkδ+1)bkζk1k=2(k+m2m1)tk1(1t)mk2(δkδ+1)(2s1s)(βk(s+1)+s(12β)s)bk.

    Equivalently,

    |ζ|k1=k(β(s+1)+s(12β))(1ρ)(2s1)(ρ+k2).

    Therefore,

    |ζ|=(1ρρ+k2)(1k1)((αk(s+1)+s(12α))2s1)(1k1).

    Hence FG is convex of order ρ.

    Partial sum is defined by Silverman [16]

    Σt,mβ,sF1(ζ)=ζ,Σt,mβ,sFγ(ζ)=ζ+γk=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk.

    In this paragraph, in the class Σt,mβ,sF(ζ), partial function sums can be considered and sharp lower limits can be reached for the function. For other investigation involving partial sum, one refer to [4,5,8,14].

    Theorem 7.1. Let FΣt,mβ,s is defined by (1.7), then

    {Σt,mβ,sF(ζ)Σt,mβ,sFγ(ζ)}>11hγ+1,ζU,

    where

    Fk=(2s1βk2(s+1)+ks(12β)).

    Proof.

    Fd+1>Fd>1,d=2,3,....

    Thus by Theorem 2.1, we obtain

    k=2|(k+m2m1)tk1(1t)mk(δkδ+1)bk|+Fd+1k=2|(k+m2m1)tk1(1t)mk(δkδ+1)bk|Fmk=2|(k+m2m1)tk1(1t)mk(δkδ+1)bk|1. (7.1)

    By set

    U(Σt,mβ,sF(ζ))=Fd+1{Σt,mβ,sF(ζ)Σt,mβ,sFd(ζ)(11Fd+1)}=1+Fd+1(Σt,mβ,sF(ζ)Σt,mβ,sFd(ζ)1)=1+Fd+1(k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζkzdk=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk)=1+Fd+1(k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk11dk=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk1).U(Σt,mβ,sF(ζ))1=Fd+1(k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk11dk=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk1).U(Σt,mβ,sF(ζ))+1=2+Fd+1(k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk11dk=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk1).

    And it is enough to show (Σt,mβ,sF(ζ))>0,ζU applying (2.5) we find

    |U(Σt,mβ,sF(ζ))1U(Σt,mβ,sF(ζ))+1|=|Fd+1(k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk11dk=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk1)2+Fd+1(k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk11dk=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk1)|(Fd+1k=2(k+m2m1)tk1(1t)mk(δkδ+1)|bk|22dk=2(k+m2m1)tk1(1t)mk(δkδ+1)|bk|+Fd+1k=2(k+m2m1)tk1(1t)mk(δkδ+1)|bk|)1,

    which gives

    {Σt,mβ,sF(ζ)Σt,mβ,sFγ(ζ)}>11hγ+1,ζU.

    Theorem 7.2. Let FΣt,mβ,s is defined by (1.7), then

    {Σt,mβ,sFk(ζ)Σt,mβ,sF(ζ)}>Fn+11+Fn+1,ζU,

    where

    Fk=(2s1βk2(s+1)+ks(12β)).

    Proof.

    Fd+1>Fd>1,d=2,3,....

    Thus by Theorem 2.1, we obtain

    k=2|(k+m2m1)tk1(1t)mk(δkδ+1)bk|+Fd+1k=2|(k+m2m1)tk1(1t)mk(δkδ+1)bk|Fmk=2|(k+m2m1)tk1(1t)mk(δkδ+1)bk|1. (7.2)

    By set

    V(Σt,mβ,sF(ζ))=1+Fd+1{Σt,mβ,sFγ(ζ)Σt,mβ,sF(ζ)(dγ+11+dγ+1)}=1+Fd+1(γk=2z(k+m2m1)tk1(1t)mk(δkδ+1)bkζkzk=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk)=1+((1+dγ+1)k=γ+1(k+m2m1)tk1(1t)mk(δkδ+1)bkζkzk=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk)=1+((1+Fd+1)k=γ+1(k+m2m1)tk1(1t)mk(δkδ+1)bkζk11k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk1).V(Σt,mβ,sF(ζ))1=((1+Fd+1)k=γ+1(k+m2m1)tk1(1t)mk(δkδ+1)bkζk11k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk1).V(Σt,mβ,sF(ζ))+1=2+((1+Fd+1)k=γ+1(k+m2m1)tk1(1t)mk(δkδ+1)bkζk11k=2(k+m2m1)tk1(1t)mk(δkδ+1)bkζk1).

    And it is enough to show (Σt,mβ,sF(ζ))>0,ζU applying (7.2) we find

    |V(Σt,mβ,sF(ζ))1V(Σt,mβ,sF(ζ))+1|1,

    which gives

    {Σt,mβ,sFk(ζ)Σt,mβ,sF(ζ)}>Fk+11+Fn+1,ζU.

    Every aspect of human endeavours depends on probability and statistics which are particularly Pascal distribution may be helpful in building models for inverse scattering problems and play a role in inferring the shape and physical properties of obstacles. Works are related to their study may refer [6,20,21,22].

    This paper deals with the application of Pascal distribution. The purpose of this article is to investigate the geometric properties of leaf-like domain, including co-efficient inequality, radius of starlikeness, convolution properties and partial sums of the class Σ(δ,Φ,β,s,t,m) that involve Pascal distribution series. In addition, several theorems are presented which provide necessary and sufficient conditions for a function FΣ(δ,Φ,β,s,t,m). Many interesting particular cases of main theorems are emphazied in the form of geometric properties. Furthermore to illustrate the results of application in various classes of analytic function. We anticipate the Pascal distribution may be helpful in building models for inverse scattering problems and play a role in inferring the shape and physical properties of obstacles. Pascal distribution will be important in several fields related to Mathematics, science and technology.

    The authors are very much thankful to the esteemed referees for their careful reading and valuable suggestions, which improved the paper.

    The authors declare no conflicts of interest.



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