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Research article

Some results on the convergence of Hessian operator and msubharmonic functions

  • Received: 19 October 2021 Revised: 17 February 2022 Accepted: 28 February 2022 Published: 08 March 2022
  • MSC : 32U40, 32U05, 32U20

  • In this paper we treat the problem of connection between the convergence in mcapacity and the convergence of the Hessian measure for a sequencefj of msubharmonic functions. We prove first that, under some conditions, the convergence of fj in capacity Capm implies the weak convergence of the Hessian measures Hm(fj). Then we show that the converse sense of convergence is also true in some particular cases.

    Citation: Jawhar Hbil, Mohamed Zaway. Some results on the convergence of Hessian operator and msubharmonic functions[J]. AIMS Mathematics, 2022, 7(5): 9023-9038. doi: 10.3934/math.2022502

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  • In this paper we treat the problem of connection between the convergence in mcapacity and the convergence of the Hessian measure for a sequencefj of msubharmonic functions. We prove first that, under some conditions, the convergence of fj in capacity Capm implies the weak convergence of the Hessian measures Hm(fj). Then we show that the converse sense of convergence is also true in some particular cases.



    The notion of capacity represents a very useful tool in the study of several problems in complex analysis regarding its effectiveness in the proof of the continuity for the Monge-Ampˊere operator and also in the resolution of the Dirichlet problem. In [1], Bedford and Taylor noticed that the weak convergence of a uniformly bounded sequence of plurisubharmonic (psh) functions fj defined on a domain Ω of Cn does not necessarily imply the convergence of the associated Monge-Ampˊere measures (ddcfj)n. This is why different works gave sufficient conditions to establish a suitable connection between the two notions of convergence. In [9], Xing proved that the convergence in capacity Cn introduced by Bedford and Taylor gives the continuity of the Monge-Ampˊere operator. This work was extended in [10] to the case of psh functions, that are only bounded near the boundary of Ω. In [3], Blocki introduced a more general notion called the msubharmonic function (msh for short) for 1mn which coincides with the psh functions in the limit case m=n. This has given rise to various works which aim to extend the results proved in the case of psh to the case of msh. Some of those problems are linked to the complex Hessian operator which itself generalizes the famous Monge-Ampˊere operator. In this paper we deal with the problem of connection between the convergence in capacity Capm and the continuity of the associated Hessian operator in the general case of msubharmonic functions that are bounded near Ω. To establish such relation we will prove firstly several results of convergence that represent itself a useful tool in the study of problems related to the Hessian operator and also a generalization of Xing's inequalities for the class of msubharmonic function that are bounded only near the boundary of Ω. Based on the established inequalities and the works of Xing [10] and Lu [7] we will prove the following main result:

    Theorem: Let EΩ and gSHm(Ω) a bounded function on ΩE. Assume that there is fkSHm(Ω) satisfying:

    (1) |fk||g| in Ω for all k.

    (2) There exists an msubharmonic function f in Ω such that fkf in Capm on each EF,

    then the sequence of measures (ddcfk)mγnm converges weakly to (ddcf)mγnm in Ω.

    We prove also that every sequence of msubharmonic functions, that converges weakly (with respect to the Lebesgue measure dλ) converges with respect to any measure that has no mass on mpolar sets.

    In the last part of this paper, we discuss the converse sense of the above theorem and we prove, under suitable conditions, that the weak convergence of the Hessian measures (ddcfk)mγnm to (ddcf)mγnm implies the convergence of (fj)j to f with respect to the capacity Capm.

    In this paper we denote by Ω a bounded domain of Cn, d:=+¯, dc:=i(¯) and Λp(Ω) the set of (p,p)forms in Ω. The classic K¨ahler form γ defined on Cn will be denoted as γ:=ddc|z|2.

    Definition 1. [3] Let ζΛ1(Ω) and mN[1,n]. The form ζ is called mpositive if it satisfies

    ζjγnj0,  j=1,,m

    at every point of Ω.

    Definition 2. [3] Let ζΛp(Ω) and mN[p,n]. We say that ζ is mpositive on Ω if the following measure

    ζβmnψ1ψmp

    is positive at every point of Ω where ψ1,,ψmpΛ1(Ω).

    We will denote by Λmp(Ω) the set of all (p,p)forms on Ω that are mpositive. In 2005, Blocki [3] introduced the notion of msubharmonic functions to generalize the plurisubharmonic functions and he developed an analogous pluripotential theory. This notion is given as follows.

    Definition 3. Let f:ΩR{}. The function f is called msubharmonic if it satisfies the following:

    (1) The function f is subharmonic.

    (2) For all ζ1,,ζm1Λm1(Ω) one has

    ddcfγnmζ1ζm10.

    We denote by SHm(Ω) the cone of msubharmonic functions defined on Ω and Bm(Ω) the set of functions uSHm(Ω) that are locally uniformly bounded.

    Remark 1. In the case m=n we have the following:

    (1) The definition of mpositivity coincides with the classic definition of positivity given by Lelong [8] for forms.

    (2) The set SHn(Ω) coincides with the set of plurisubharmonic functions on Ω.

    For more details about the properties of msubharmonicity one can refer to [3,5,7].

    Example 1. (1) If

    ζ:=i(4.dz1d¯z1+4.dz2d¯z2dz3d¯z3)

    then ζΛ21(C3)Λ31(C3).

    (2) If

    f(z):=2|z1|2+2|z2|2|z3|

    then fSH2(C3)SH3(C3).

    In the following we give the notion of scapacity for every integer s. Such notion will be useful throughout this paper and was defined on every subset E as follows:

    Definition 4. [5] The scapacity of a compact subset K in Ω denoted by Caps(K) is defined as

    Caps(K,Ω)=Caps(K):=sup{K(ddcf)sγns,fSHm(Ω),0f1},

    for 1sm. If EΩ, then Caps(E,Ω)=sup{Caps(K),K compact of E}.

    One of the most known property for msubharmonic functions is the continuity outside a subset of small capacity. Such property is known as the quasicontinuity and will represent an essential tool in the proof of several result in this paper.

    Proposition 1. Every fSHm(Ω) is Capm-quasicontinuous. That means for all ε>0 there exists an open subset Oε such that Capm(Oε)<ε and f is continuous on ΩOε. As a consequence f can be written as follows

    f=f1+f2

    where f1 is continuous on Ω and f20 on ΩOε.

    Definition 5. (1) A positive measure μ defined on Ω is said to be absolutely continuous with respect to the capacity Capm (μ<<Capm for short) on a Borel subset E in Ω if

    t>0, s>0 such that for any E1E; Capm(E1)<sμ(E1)<t.

    (2) Let fj,fSHm(Ω), we say that lim infzΩ(fjf)0 if and only if

    ε>0,Ω1Ω, such that fj(z)f(z)ε

    for every zΩΩ1 and jN.

    Definition 6. (1) The set Ω is said to be mhyperconvex if it is open, bounded, connected and there exists a negative msubharmonic function g such that for all c<0, one has {zΩ, g(z)<c}Ω.

    (2) A set MΩ is called mpolar if there exist uSHm(Ω) such that

    M{u=}.

    (3) A sequence of functions (fj)j defined on Ω is said to be convergent with respect to Capm to f on E if for all t>0, one has

    limj+Capm(E{|ffj|>t})=0.

    In this section we prove that the convergence in mcapacity of a sequence (fj)jSHm(Ω) implies the convergence of the associated Hessian measure Hm(fj):=(ddcfj)mγnm for functions fj that are only bounded near the boundary. We will start by establishing the following theorem.

    Theorem 1. Let fSHm(Ω) and assume that there is a sequence fjSHm(Ω)L(Ω) satisfying the following assumptions:

    (1) For all jN, fj is uniformly bounded near Ω.

    (2) fjf in Capm on each EΩ.

    (3) For every EΩ, one has (ddcfj)mγnmCapm uniformly.

    Then the sequence of measures (ddcfj)mγnm converges weakly to (ddcf)mγnm in Ω and (ddcf)mγnmCapm on each EΩ.

    Proof. Using the assumption (1), we get that f is bounded near Ω. So the Borel measure (ddcf)mγnm is well defined, see [4]. To prove the convergence of (ddcfj)mγnm toward (ddcf)mγnm, we take a smooth function φ with compact support in Ω. So we have for all constant r>0

    Ωφ((ddcfj)m(ddcf)m)γnm=Ωφ((ddcfj)m(ddcmax(fj,r))m)γnm+Ωφ((ddcmax(fj,r))m(ddcmax(f,r))m)γnm+Ωφ((ddcmax(f,r))m(ddcf)m)γnm:=A+B+C.

    Using Theorem 2.12 in [6], we obtain that for each r>0 sufficiently large

    A=fjrφ((ddcfj)m(ddcmax(fj,r))m)γnmmaxΩ|φ|(fjr(ddcfj)mγnm+fjr(ddcmax(fj,r))mγnm).

    Now by Lemma 3 in [4] we get

    fjr(ddcmax(fj,r))mγnmfjr(12fjr)m(ddcmax(fj,r))mγnm2mfj<r2(r2fj)m(ddcmax(fjr,1))mγnm2m(m!)2fj<r2(ddcfj)mγnm.

    It follows that for each r large enough and all j

    A∣≤(1+2m(m!)2)maxΩ|φ|fj<r2(ddcfj)mγnm.

    As Capm{f<r2}0 as r and fjf in Capm, we obtain that Capm{fj<r2} is uniformly convergent to zero for all j when r. Using the assumption of the uniformly absolute continuity of (ddcfj)mγnm we get that the integral fj<r2(ddcfj)mγnm tends uniformly to zero for all j when r.

    Hence, for every ε>0 there exits a constant r0 such that |A|ε for all j, and by Theorem 2 in [4] we can also require that |C|ε. However, for a such fixed constant r the assumption (2) implies that functions max(fj,r) converge to max(f,r) in Capm on each EΩ as j and hence we conclude by Theorem 1.3.7 in [7] that B0 as j. Therefore, we obtain that (ddcfj)mγnm converges weakly to (ddcf)mγnm.

    To finish the proof it suffices to show that (ddcf)mγnmCapm on any open set EΩ. Let ε>0 and take δ>0 such that inequalities (ddcfj)mγnm(F)ε hold for all j and all Borel sets FE with Capm(F)<δ. Let (χk)k be a sequence of non-negative smooth functions that increases to the characteristic function of F in Ω.

    Then

    F(ddcf)mγnm=limkΩχk(ddcf)mγnm=limklimjΩχk(ddcfj)mγnmlim supjF(ddcfj)mγnmε.

    Hence (ddcf)mγnmCapm on E and we have completed the proof of the Theorem.

    In the next lemmas we will be interested to prove some estimations known as Xing inequalities. Some of those inequalities were proved by Bedford and Taylor in [1] for bounded psh function and have several applications on the Dirichlet problem. In [9], Xing obtained a stronger version of those inequalities. In the following we will generalize those results to the class of msubharmonic functions that are only bounded near the boundary.

    Lemma 1. Let fj,fSHm(Ω) such that (ddcfj)mγnm(ddcf)mγnm on Ω. Then the following assertions are equivalent

    (1) (ddcf)mγnm has zero mass on any mpolar set and h(ddcfj)mγnmh(ddcf)mγnm for every locallybounded msh function h on Ω.

    (2) The sequence (ddcfj)mγnm puts uniformly small mass on sets of small mcapacity.

    The proof of the above result will be omitted since it is inspired from to the proof Theorem 2 in [2] which was established in the case of plurisubharmonic functions.

    Lemma 2. Let fj be a sequence of bounded msh functions in Ω that decreases to fSHm(Ω). Assume that

    (1) The function f is bounded near Ω.

    (2) (ddcf)mγnmCapm on any relativelycompact subset of Ω.

    Then (ddcfj)mγnmCapmuniformly for all j on each EΩ.

    Proof. Using the proof of Theorem 2 in [4] we obtain that g(ddcfj)mγnmg(ddcf)mγnm weakly in Ω for any locally bounded msh function g on Ω. Thus, the Lemma follows directly from Lemma 1.

    Remark 2. As a consequence of the previous lemma, we can deduce that "a function f is bounded near Ω and have absolute continuous Hessian measure with respect to Capm if and only if f is the limit of functions given in Theorem 1". Indeed if we assume that f is bounded near Ω and (ddcf)γnmCapm then the sequence fj:=max(f,j) is bounded and decreases to f. Using the quasicontiuity combined with the Dini's theorem we deduce that fj converges to f with respect to Capm. Now the lemma 2 implies that (ddcfj)γnmCapm. Hence the sequence fj satisfies Theorem Theorem 1.

    Conversely it is easy to check that every limit of functions in Theorem Theorem 1 is bounded near the boundary of Ω and with Hessian measure absolutely continuous with respect to Capm.

    Lemma 3. Let f,gSHm(Ω) such that

    (1) lim infzΩ(f(z)g(z))0.

    (2) The functions f and g are bounded near Ω and with Hessian measure absolutely continuous with respect to Capm on each EΩ.

    Then for any constant c1 and allhj SHm(Ω) with 0hj1, j=1,2,...,m, one has

    1m!2f<g(gf)mddch1...ddchmγnm+f<g(ch1)(ddcg)mγnm
    f<g(ch1)(ddcf)mγnm.

    Moreover if we assume that

    (ddcf)mγnm(ddcg)mγnm

    in Ω, then{f<g}=.

    Proof. Replacing f by f+2t and then taking t0, we may assume that there exists a subset EΩ such that {f<g}E. Take fk:=max(f,k) and gj=max(g,j). Then {fk<gj}E for k and j large enough. Using Lemma 3 in [4] we obtain that for any constant c1 and all hjSHm(Ω) such that 0hj1, j=1,2,...,m

    1m!2fk<gj(gjfk)mddch1...ddchmγnm+fk<gj(ch1)(ddcgj)mγnm
    fk<gj(ch1)(ddcfk)mγnm

    where k and j are large enough. Since fkf then (ddcfk)mγnm tends weakly to (ddcf)mγnm then by Lemma 2 we get that (ddcfk)mγnmCapm uniformly for all k in the set E. Similarly, (ddcgj)mγnmCapm uniformly for all j in E. Now take ε>0, and let U be an open subset of Ω with Capm(U)<ε such that f, g are continuous on F=ΩU. Thus, we can write g=φ1+φ2 where φ1 is continuous on ¯F and φ2=0 outside of U. Then

    (ch1)(ddcgj)mγnm(ch1)(ddcg)mγnm

    weakly on Ω and we have

    fk<φ1(ch1)(ddcg)mγnmlimjfk<φ1(ch1)(ddcgj)mγnm.

    The last inequality implies that

    fk<g(ch1)(ddcg)mγnmfk<φ1(ch1)(ddcg)mγnm+U(ch1)(ddcg)mγnmlimjfk<φ1(ch1)(ddcgj)mγnm+Capm(U)limjfk<g(ch1)(ddcgj)mγnm+O(ε)limjfk<gj(ch1)(ddcgj)mγnm+O(ε).

    Hence if we let j, we get

    1m!2f<g(gf)mddch1...ddchmγnm+fk<g(ch1)(ddcg)mγnm
    fkg(ch1)(ddcfk)mγnm+O(ε).

    Since the functions f, g are continuous on the set Ω and fkf, we get

    fg(ch1)(ddcf)mγnm{fg}F(ch1)(ddcf)mγnmlimk{fg}F(ch1)(ddcfk)mγnmlimk{fkg}F(ch1)(ddcfk)mγnmlimkfkg(ch1)(ddcfk)mγnmO(ε).

    Now let k and as ε>0 is arbitrary, we obtain

    1m!2f<g(gf)mddch1...ddchmγnm+f<g(ch1)(ddcg)mγnm
    fg(ch1)(ddcf)mγnm.

    If we apply the last inequality to f+t instead of f and then letting t0, we obtain the desired result.

    Our main result in this paper is the following theorem where we give sufficient conditions combined with the convergence in capacity Capm for a sequence of msubharmonic functions fk to guarantee the weak convergence of the Hessian measures (ddcfk)mγnm. Such result generalizes well known results in [7,10]. It suffices to take m=n in our result to recover it.

    Theorem 2. Let gSHm(Ω) a bounded function on ΩE for some EΩ. Assume that there is fkSHm(Ω) satisfying

    (1) |fk||g| in Ω for all k.

    (2) There exists an msubharmonic function f in Ω such that fkf in Capm on each EΩ.

    Then the sequence of measures (ddcfk)mγnm converges weakly to (ddcf)mγnm in Ω.

    Before giving the proof of the Theorem, we need to establish some intermediate lemmas.

    Lemma 4. Let f1,f2,...,fmSHm(Ω) such that f1 is bounded in Ω and the functions f2,...,fm are bounded near Ω. For every EΩ there exists CE>0 such that for all Borel subset G in E the following estimate holds

    Gddcf1ddcf2...ddcfmγnmCE(Capm(G))12m.

    Proof. Without loss of generality we can assume that for all i, the functions fi can be written, near Ω, as follows

    fi=αφ(z)+β

    where α>0, β>0 and φ is a defining function of Ω. Let GE be a Borel subset and

    fG(z)=sup{u(z):uSHm(Ω),u1 on G,u<0 on Ω}

    and fG the associated upper semicontinuous regularization of G defined by

    fG(z)=lim supζzfG(ζ).

    We have Capm(G)=Ω(ddcfG)mγnm, limzΩfG(z)=0 and fG=1 on GM for some mpolar set M, (see [7]). By the Cauchy-Schwarz inequality we obtain

    Gddcf1ddcf2...ddcfmγnmΩfGddcf1ddcf2...ddcfmγnm=ΩdfGdcf2ddcf1ddcf3...ddcfmγnmA(ΩdfGdcfGddcf1ddcf3...ddcfmγnm)12=A(ΩfGddcfGddcf1ddcf3...ddcfmγnm)12

    where

    A=(Ωdf2dcf2ddcf1ddcf3...ddcfmγnm)12

    is a finite constant because of the bounded assumption of the function f1. By repeating the same argument m1 more times we get

    Gddcf1ddcf2...ddcfmγnmAE(ΩfG(ddcfG)mγnm)12mCE(Ω(ddcfG)mγnm)12m=CE(Capm(G))12m

    for some constant CE>0. This proves the lemma.

    Lemma 5. Let f,g,h1,...,hm1SHm(Ω) bounded functions near Ω and hmSHm(Ω)L(Ω). If lim infzΩ(f(z)g(z))0 and the set {f<g} is open, then for any rsupΩh1 one has

    f<g(gf)ddch1ddch2...ddchmγnm+f<g(rh1)ddcgddch2...ddchmγnmf<g(rh1)ddcfddch2...ddchmγnm.

    Proof. Without loss of generality, one can suppose that Ω is a mhyperconvex domain and that there exists a function φ defined on Ω such that

    f=g=h1=φ near Ω.

    Let {fk}, {gj} and {hl1} be a sequence of continuous msh functions such that fk=gj=hl1=φ near Ω and fkf as k, gjg as j and hl1h1 as l. By Lemma 3 in [4] we get

    fk<gj(gjfk)ddchl1ddch2...ddchmγnm+fk<gj(rhl1)ddcgjddch2...ddchmγnmfk<gj(rhl1)ddcfkddch2...ddchmγnm.

    If we let k then by Fatou's lemma we obtain

    f<gj(gjf)ddchl1ddch2...ddchmγnm+f<gj(rhl1)ddcgjddch2...ddchmγnmlim infkf<gj(rhl1)ddcfkddch2...ddchmγnm.

    Since

    limk(rhl1)ddcfkddch2...ddchmγnm=(rhl1)ddcfddch2...ddchmγnm

    weakly in Ω we obtain using Lemma 4 that

    (rhl1)ddcfkddch2...ddchmγnm<<Capm

    for all k on each EΩ. Hence ε>0,k0>0 such that

    lim infkf<gj(rhl1)ddcfkddch2...ddchmγnmlim infkfk0gj+ε(rhl1)ddcfkddch2...ddchmγnm+εfk0gj+ε(rhl1)ddcfddch2...ddchmγnm+ε.

    As ffk0 and ggj and ε is arbitrary chosen, we obtain

    f<gj(gjf)ddchl1ddch2...ddchmγnm+f<g(rhl1)ddcgjddch2...ddchmγnmfgj(rhl1)ddcfddch2...ddchmγnm.

    By letting l and using the fact that

    (gjf)ddchl1ddch2...ddchmγnm(gjf)ddch1ddch2...ddchmγnm

    weakly in Ω when l we get

    f<gj(gjf)ddch1ddch2...ddchmγnm+f<g(rh1)ddcgjddch2...ddchmγnmfgj(rh1)ddcfddch2...ddchmγnm.

    Now if we let j and using the weak convergence of (rh1)ddcgjddch2...ddchmγnm combined with the Fatou lemma and the fact that the set {f<g} is supposed open, we get

    f<g(gf)ddch1ddch2...ddchmγnm+f<g(rh1)ddcgddch2...ddchmγnmfg(rh1)ddcfddch2...ddchmγnm.

    To complete the proof it suffices to apply the previous inequality to f+t instead of f and then we take t0.

    Now we give the proof of the Theorem 2.

    Proof. By hypothesis (1), we may assume without loss of generality that there exists a compact subset K in Ω such that fk=g in ΩK for all k and g=fk=0 on Ω. We will assume by induction that the current (ddcfk)lγnm converges weakly to (ddcf)lγnm in Ω for 1lm1. Using Lemma 5, we obtain that for any r>0 and all k

    fk<r(fk)(ddcfk)mpγn+pmg<r(g)(ddcfk)mpγn+pm2g<r2(gr2)(ddcfk)mpγn+pm2g<r2(fk)ddcg(ddcfk)mp1γn+pm2g<r2gddcg(ddcfk)mp1γn+pm22g<r22g(ddcg)2(ddcfk)mp2γn+pm...2mpg<r2mpg(ddcg)mpγn+pm.

    Hence we get that (g)(ddcg)mpγn+pm(ddcg)mpγn+pmCapm on each EΩ. So we obtain that

    (fk)(ddcfk)mpγn+pmCapm()

    on each EΩ uniformly for all k.

    Replacing f and fk by max(f,c) and max(fk,c) respectively for a fixed constant c if necessary, we can assume that both f and fk are locally uniformly bounded. So by assumption (1) and proposition 1 we get that for any ε>0 the following writing hold

    fk=fk,1+fk,2 and f=f1+f2

    where f1 is a continuous function in Ω and fk,2=f2=0 on ΩU for some UΩ with Capr(U)<ε. Furthermore, for each EΩU, one has that |fk,1f1|<ε on E for large value of k and the functions fk,1, fk,2, f1 and f2 are bounded uniformly by a constant which does not depend on ε. If we consider the following decomposition

    fk(ddcfk)mpγn+pmf(ddcf)mpγn+pm=(fk,1f1)(ddcfk)mpγn+pm+f1((ddcfk)mp(ddcf)mp)γn+pm+(fk,2(ddcfk)mpf2(ddcf)mp)γn+pm.

    So the proof will be completed if we show that all three terms of the right hand side in the last equality tend weakly to 0. For the third term its suffices to use () to get that it tends to zero weakly and uniformly for all k when ε goes to 0. Since we have

    E|fk,1f1|(ddcfk)mpγn+pmεEU(ddcfk)mpγn+pm+supk|fk,1f1|U(ddcfk)mpγn+pm,

    and (ddcfk)mpγn+pm converges weakly to (ddcf)mpγn+pm by induction's assumption we deduce that the first and the second term in the last equality also converges weakly to zero uniformly for all k as ε0. The result of the theorem follows.

    Remark 3. (1) Using the Theorem 2, we deduce that for all j

    (rh1)ddcgjddch2...ddchmγnm<<Capm

    on every subset EΩ.Then we can deduce that the assumption "the set {f<g} is open" in Lemma 5 is superfluous. This implies that the Lemma 5 is an improved version of Lemma 3

    (2) The assumptions in the Theorem 2 can be replaced by the monotically convergence of fk towards f for f,fkSHm(Ω)L(ΩE).

    Theorem 3. Let fjBm(Ω) and fSHm(Ω)Lloc(Ω). The following assertions hold

    (1) If fjf in Capm1 in every EΩ then for all h in Bm(Ω) one has that h(ddcfj)mγnm converges weakly to h(ddcf)mγnm.

    (2) If for every EΩ one has fjf in Capm then for every ξC0(Ω) we have that Ωξh(ddcfj)mγnmΩξh(ddcf)mγnm uniformly for all h in Bm(Ω).

    (3) If fjf in Capm on each EΩ and hjBm(Ω) converges weakly to hBm(Ω), then hj(ddcfj)mγnm converges weakly to h(ddcf)mγnm in Ω.

    Proof. To prove the assertion (1), it remains to show, by induction, that for each km, (ddcfj)kγnm tends weakly to (ddcf)kγnm. The case for k=1 is obvious since the convergence assumption implies that fjf in L1loc(Ω). Hence, it follows that ddcfjγnm converges weakly to ddcfγnm. Assume, by induction, that it is true for all k=q<m and we have to show that fj(ddcfj)qγnm converges weakly to f(ddcf)qγnm and by taking the operator ddc we will obtain the required statement for k=q+1. Let ε>0, the function f can be written as f=h1+h2 on Ω, where h1 is continuous, h2=0 outside an open subset UΩ with capm(U)<ε, and the supremum norm of h2 depends only on the function h. We have

    fj(ddcfj)qγnmf(ddcf)qγnm=(fjf)(ddcfj)qγnm+h2[(ddcfj)qγnm(ddcf)qγnm]+h1[(ddcfj)qγnm(ddcf)qγnm]=A1+A2+A3.

    The inductive assumption gives that A3 converges to 0 in the sense of currents. On the other hand, it is easy to check that

    (ddcfj)qγmq1γnm+1(ddc(fj+|z|2))m1γnm+1.

    The last term is dominated by a constant, independent on j, multiplied by Capm. Hence using the convergence assumption we obtain that A1 converges in the sense of currents to 0. Now since h2=0 outside U, then A2 makes arbitrarily small mass for all j by choosing ε small enough. Hence we have obtained the weak convergence of fj(ddcfj)qγnm to f(ddcf)qγnm. To finish the proof of the assertion (1) it suffices to use the quasicontinuity of the function h to get the desired result.

    To prove (2), thanks to the assertion (1) we have that (ddcfj)mγnm(ddcf)mγnm weakly in Ω and hence we may assume that Bm(Ω)={fSHm(Ω);0<f<1}. Let ξC0(Ω) a test function. Changing the values of fj and f near Ω, we can suppose that there exists a subset E such that supp ξE and fj=f in ΩE. It follows that for every ε>0 and all h in Bm(Ω), an integration by parts yields

    Ωξh((ddcfj)m(ddcf)m)γnm=E{|fjf|<ε}(fjf)ddc(ξh)(Σm1k=0(ddcfj)k(ddcf)m1k)γnm+E{|fjf|ε}(fjf)ddc(ξh)(Σm1k=0(ddcfj)k(ddcf)m1k)γnm:=Aε,j+Bε,j.

    Let ξC0(Ω) and C1 a constant sufficiently large satisfying ξ=(ξ+C1|z|2)C1|z|2:=ξ1ξ2, where 0ξ1,ξ2SHm(Ω)L(Ω). For the cases k=1 and k=2 we get that 2ddc(ξkh)=ddc((ξk+h)2)ddc(h2)ddc(ξ2k). It follows that there exists a constant C2 that does not depend on ε and jN such that

    Aε,j(ξ)∣≤∣Aε,j(ξ1)+Aε,j(ξ2)∣≤C2Capm(E)ε

    and

    Bε,j(ξ)∣≤∣Bε,j(ξ1)+Bε,j(ξ2)∣≤C2Capm(E{|fjf|>ε})0

    as j. This gives that

    Ωξh(ddcfj)mγnmΩξh(ddcf)mγnm

    as j uniformly in Bm(Ω).

    For the assertion (3) we have

    hj(ddcfj)mγnmh(ddcf)mγnm=hj((ddcfj)m(ddcf)m)γnm+(hjh)((ddcf)m(ddcus)m)γnm+(hjh)(ddcus)mγnm=:A+B+C

    where us are smooth msh functions decreasing to f. Using the assertion (2) the term B goes weakly to zero as s uniformly for all j. Hence if s is a constant sufficiently large we get that both A and C converge weakly to zero as j. So the assertion (3) follows.

    Using Theorem 3.3, one can get that the convergence with respect to the Lebegue measure of a sequence of msh functions fj implies the weak convergence of fj with respect to any measure that has nos mass on every mpolar sets.

    Corollary 1. If ν is a locally finite measure, fk a sequence of msh functions in Ω and f0SHm(Ω)L1loc(Ω,ν) satisfying the following assumptions.

    i) For every mpolar set AΩ one has ν(A)=0.

    ii) For all kN, |fk||f0|.

    iii) For every EΩ, Efjfdλ0.

    Then Efkfdν0 as k on any EΩ.

    Proof. Without loss of generality we may assume that for every zΩ; fk(z)<0 and f(z)<0. Using hypothesis i) it suffices to show that

    ζC0(Ω),limk+Ωζfkdν=Ωζfdν.

    For ζC0(Ω), one has the following the following writing

    ΩζfkdνΩζfdν=Ωζ(fkmax(fk,s))dν+Ωζ(max(fk,s)max(f,s))dν+Ωζ(max(f,s)f)dν2.maxζsuppζ{f0<s}f0dν+Ωζ(max(fk,s)max(f,s))dν.

    As lims+maxζsuppζ{f0<s}f0dν=0 then

    ΩζfkdνΩζfdνΩζ(max(fk,s)max(f,s))dν.

    On the other hand, using Theorem 5.3 in [6] there exists αSHm(Ω)L(Ω) and hL1(Ω,(ddcα)mγnm) such that h0 and 1lsuppζdν=h(ddcα)mγnm. So for every ε>0 there exists s,j>0 such that

    |ΩζfkdνΩζfdν||Ωζmin(h,j)(max(fk,s)max(f,s))(ddcα)mγnm|+ε.

    So one can take gC(Ω) such that suppζ|min(h,k)g|(ddcα)mγnm<εs. it follows that

    |ΩζfkdνΩζfdν||Ωζg(max(fk,s)max(f,s))(ddcα)mγnm|+(2maxζ+1)ε.

    The last integral tends to 0 when k by Theorem 3. Therefore the proof of the desired Theorem is completed.

    In the following theorem we treat the converse sense. So we will prove that the convergence of the hessian measure associated to a sequence of msh functions implies, under some conditions, the convergence in capacity Capm for a such sequence.

    Theorem 4. Let (fj)jSHm(Ω)L(Ω) be a sequence of locally uniformly bounded functions that converges weakly to fSHm(Ω). Assume that

    (1) lim infzΩ(fjf)0 uniformly for all j.

    (2) There exists a positive measure dμ in Ω such that h(ddcfj)mγnm converges weakly to hdμ in Ω uniformly for all hSHm(Ω) with 0h1.

    Then (ddcf)mγnm=dμ and fjf in Capm on each EΩ. Hence, if furthermorelim infzΩ(ffj)0 uniformly for all j then fjf in Capm on Ω.

    Proof. Let φSHm(Ω) such that 0<φ<1 and EΩ. For every t>0 one has

    E{|fjf|>t}(ddcφ)mγnmCapm(E{fj>f+t})+E{fj<ft}(ddcφ)mγnm.

    Using the quasicontinuity of msh functions and the Hartog's Lemma we get that Capm(E{fj>f+t})0 when j. Hence, by the assumption (2) and Lemma 3 [4] we obtain

    fj<ft(ddcφ)mγnm1tmfj<ft(ffj)m(ddcφ)mγnmm!2tmfj<ft(ddcfj)mγnmm!2tm+1fj<ft(ufj)(ddcφ)mγnm.

    Take ε>0, and F1F2Ω such that fjfε in ΩF1 and {fj<ft}F1 for all j. Again by the Hartog's Lemma and the quasicontinuity of msh functions we get that there exist j0>0 and AF2 with Capm(A)<ε such that ε+f(z)fj(z)0 in F2A for all jj0. Let χC0(F2) such that χ0 and χ=1 in F1. Since all the functions fj and f are uniformly bounded in F2, then for jj0

    fj<ft(ddcfj)mγnmm!2tm+1fj<ft(ffj)(ddcφ)mγnmF1Aχ(ε+ffj)(ddcfj)mγnm+O(ε)F2χ(ffj)(ddcfj)mγnm+O(ε)=F2χ(ffj)((ddcfj)mγnmdμ)+F2χ(ffj)dμ+O(ε).

    Now using assumption (3) and Corollary 1, we obtain that the last two integrals go to zero when j. Hence fjf in Capm on each EΩ. Then by [6], we get (ddcf)mγnm=dμ and the proof of the Theorem is complete.

    In this paper we have dealt with a problem related to the convergence of a sequence of complex Hessian measures given by a sequence of msubharmonic functions fj. By introducing some conditions, we have shown that if fj converges in Capm then the associated sequence of measures converges in the weak sense. In addition we have shown that the converse sense still true form some particular classes of msubharmonic functions. The established results in this paper may be useful not only in the problem related to the convergence of the Hessian measure but also in the resolution of the famous complex Hessian equations.

    Authors extend their appreciation to the Deanship of Scientific Research at Jouf University for funding this work through research Grant No. DSR-2021-03-0113.

    Authors declare that no conflicts of interest in this manuscript.



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