In this paper we treat the problem of connection between the convergence in m−capacity and the convergence of the Hessian measure for a sequencefj of m−subharmonic functions. We prove first that, under some conditions, the convergence of fj in capacity Capm implies the weak convergence of the Hessian measures Hm(fj). Then we show that the converse sense of convergence is also true in some particular cases.
Citation: Jawhar Hbil, Mohamed Zaway. Some results on the convergence of Hessian operator and m−subharmonic functions[J]. AIMS Mathematics, 2022, 7(5): 9023-9038. doi: 10.3934/math.2022502
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In this paper we treat the problem of connection between the convergence in m−capacity and the convergence of the Hessian measure for a sequencefj of m−subharmonic functions. We prove first that, under some conditions, the convergence of fj in capacity Capm implies the weak convergence of the Hessian measures Hm(fj). Then we show that the converse sense of convergence is also true in some particular cases.
The notion of capacity represents a very useful tool in the study of several problems in complex analysis regarding its effectiveness in the proof of the continuity for the Monge-Ampˊere operator and also in the resolution of the Dirichlet problem. In [1], Bedford and Taylor noticed that the weak convergence of a uniformly bounded sequence of plurisubharmonic (psh) functions fj defined on a domain Ω of Cn does not necessarily imply the convergence of the associated Monge-Ampˊere measures (ddcfj)n. This is why different works gave sufficient conditions to establish a suitable connection between the two notions of convergence. In [9], Xing proved that the convergence in capacity Cn introduced by Bedford and Taylor gives the continuity of the Monge-Ampˊere operator. This work was extended in [10] to the case of psh functions, that are only bounded near the boundary of Ω. In [3], Blocki introduced a more general notion called the m−subharmonic function (m−sh for short) for 1≤m≤n which coincides with the psh functions in the limit case m=n. This has given rise to various works which aim to extend the results proved in the case of psh to the case of m−sh. Some of those problems are linked to the complex Hessian operator which itself generalizes the famous Monge-Ampˊere operator. In this paper we deal with the problem of connection between the convergence in capacity Capm and the continuity of the associated Hessian operator in the general case of m−subharmonic functions that are bounded near ∂Ω. To establish such relation we will prove firstly several results of convergence that represent itself a useful tool in the study of problems related to the Hessian operator and also a generalization of Xing's inequalities for the class of m−subharmonic function that are bounded only near the boundary of Ω. Based on the established inequalities and the works of Xing [10] and Lu [7] we will prove the following main result:
Theorem: Let E⋐Ω and g∈SHm(Ω) a bounded function on Ω∖E. Assume that there is fk∈SHm(Ω) satisfying:
(1) |fk|≤|g| in Ω for all k.
(2) There exists an m−subharmonic function f in Ω such that fk→f in Capm on each E⋐F,
then the sequence of measures (ddcfk)m∧γn−m converges weakly to (ddcf)m∧γn−m in Ω.
We prove also that every sequence of m−subharmonic functions, that converges weakly (with respect to the Lebesgue measure dλ) converges with respect to any measure that has no mass on m−polar sets.
In the last part of this paper, we discuss the converse sense of the above theorem and we prove, under suitable conditions, that the weak convergence of the Hessian measures (ddcfk)m∧γn−m to (ddcf)m∧γn−m implies the convergence of (fj)j to f with respect to the capacity Capm.
In this paper we denote by Ω a bounded domain of Cn, d:=∂+¯∂, dc:=i(¯∂−∂) and Λp(Ω) the set of (p,p)−forms in Ω. The classic K¨ahler form γ defined on Cn will be denoted as γ:=ddc|z|2.
Definition 1. [3] Let ζ∈Λ1(Ω) and m∈N∩[1,n]. The form ζ is called m−positive if it satisfies
ζj∧γn−j≥0, ∀j=1,⋯,m |
at every point of Ω.
Definition 2. [3] Let ζ∈Λp(Ω) and m∈N∩[p,n]. We say that ζ is m−positive on Ω if the following measure
ζ∧βm−n∧ψ1∧⋯∧ψm−p |
is positive at every point of Ω where ψ1,⋯,ψm−p∈Λ1(Ω).
We will denote by Λmp(Ω) the set of all (p,p)−forms on Ω that are m−positive. In 2005, Blocki [3] introduced the notion of m−subharmonic functions to generalize the plurisubharmonic functions and he developed an analogous pluripotential theory. This notion is given as follows.
Definition 3. Let f:Ω→R∪{−∞}. The function f is called m−subharmonic if it satisfies the following:
(1) The function f is subharmonic.
(2) For all ζ1,⋯,ζm−1∈Λm1(Ω) one has
ddcf∧γn−m∧ζ1∧⋯∧ζm−1≥0. |
We denote by SHm(Ω) the cone of m−subharmonic functions defined on Ω and Bm(Ω) the set of functions u∈SHm(Ω) that are locally uniformly bounded.
Remark 1. In the case m=n we have the following:
(1) The definition of m−positivity coincides with the classic definition of positivity given by Lelong [8] for forms.
(2) The set SHn(Ω) coincides with the set of plurisubharmonic functions on Ω.
For more details about the properties of m−subharmonicity one can refer to [3,5,7].
Example 1. (1) If
ζ:=i(4.dz1∧d¯z1+4.dz2∧d¯z2−dz3∧d¯z3) |
then ζ∈Λ21(C3)∖Λ31(C3).
(2) If
f(z):=2|z1|2+2|z2|2−|z3| |
then f∈SH2(C3)∖SH3(C3).
In the following we give the notion of s−capacity for every integer s. Such notion will be useful throughout this paper and was defined on every subset E as follows:
Definition 4. [5] The s−capacity of a compact subset K in Ω denoted by Caps(K) is defined as
Caps(K,Ω)=Caps(K):=sup{∫K(ddcf)s∧γn−s,f∈SHm(Ω),0≤f≤1}, |
for 1≤s≤m. If E⊂Ω, then Caps(E,Ω)=sup{Caps(K),K compact of E}.
One of the most known property for m−subharmonic functions is the continuity outside a subset of small capacity. Such property is known as the quasicontinuity and will represent an essential tool in the proof of several result in this paper.
Proposition 1. Every f∈SHm(Ω) is Capm-quasicontinuous. That means for all ε>0 there exists an open subset Oε such that Capm(Oε)<ε and f is continuous on Ω∖Oε. As a consequence f can be written as follows
f=f1+f2 |
where f1 is continuous on Ω and f2≡0 on Ω∖Oε.
Definition 5. (1) A positive measure μ defined on Ω is said to be absolutely continuous with respect to the capacity Capm (μ<<Capm for short) on a Borel subset E in Ω if
∀t>0, ∃s>0 such that for any E1⊂E; Capm(E1)<s⇒μ(E1)<t. |
(2) Let fj,f∈SHm(Ω), we say that lim infz→∂Ω(fj−f)≥0 if and only if
∀ε>0,∃Ω1⋐Ω, such that fj(z)−f(z)≥−ε |
for every z∈Ω∖Ω1 and j∈N.
Definition 6. (1) The set Ω is said to be m−hyperconvex if it is open, bounded, connected and there exists a negative m−subharmonic function g such that for all c<0, one has {z∈Ω, g(z)<c}⋐Ω.
(2) A set M⊂Ω is called m−polar if there exist u∈SHm(Ω) such that
M⊂{u=−∞}. |
(3) A sequence of functions (fj)j defined on Ω is said to be convergent with respect to Capm to f on E if for all t>0, one has
limj→+∞Capm(E∩{|f−fj|>t})=0. |
In this section we prove that the convergence in m−capacity of a sequence (fj)j⊂SHm(Ω) implies the convergence of the associated Hessian measure Hm(fj):=(ddcfj)m∧γn−m for functions fj that are only bounded near the boundary. We will start by establishing the following theorem.
Theorem 1. Let f∈SHm(Ω) and assume that there is a sequence fj∈SHm(Ω)∩L∞(Ω) satisfying the following assumptions:
(1) For all j∈N, fj is uniformly bounded near ∂Ω.
(2) fj→f in Capm on each E⋐Ω.
(3) For every E⋐Ω, one has (ddcfj)m∧γn−m≪Capm uniformly.
Then the sequence of measures (ddcfj)m∧γn−m converges weakly to (ddcf)m∧γn−m in Ω and (ddcf)m∧γn−m≪Capm on each E⋐Ω.
Proof. Using the assumption (1), we get that f is bounded near ∂Ω. So the Borel measure (ddcf)m∧γn−m is well defined, see [4]. To prove the convergence of (ddcfj)m∧γn−m toward (ddcf)m∧γn−m, we take a smooth function φ with compact support in Ω. So we have for all constant r>0
∫Ωφ((ddcfj)m−(ddcf)m)∧γn−m=∫Ωφ((ddcfj)m−(ddcmax(fj,−r))m)∧γn−m+∫Ωφ((ddcmax(fj,−r))m−(ddcmax(f,−r))m)∧γn−m+∫Ωφ((ddcmax(f,−r))m−(ddcf)m)∧γn−m:=A+B+C. |
Using Theorem 2.12 in [6], we obtain that for each r>0 sufficiently large
∣A∣=∣∫fj≤−rφ((ddcfj)m−(ddcmax(fj,−r))m)∧γn−m∣≤maxΩ|φ|(∫fj≤−r(ddcfj)m∧γn−m+∫fj≤−r(ddcmax(fj,−r))m∧γn−m). |
Now by Lemma 3 in [4] we get
∫fj≤−r(ddcmax(fj,−r))m∧γn−m≤∫fj≤−r(−1−2fjr)m(ddcmax(fj,−r))m∧γn−m≤2m∫fj<−r2(−r2−fj)m(ddcmax(fjr,−1))m∧γn−m≤2m(m!)2∫fj<−r2(ddcfj)m∧γn−m. |
It follows that for each r large enough and all j
∣A∣≤(1+2m(m!)2)maxΩ|φ|∫fj<−r2(ddcfj)m∧γn−m. |
As Capm{f<−r2}→0 as r→∞ and fj→f in Capm, we obtain that Capm{fj<−r2} is uniformly convergent to zero for all j when r→∞. Using the assumption of the uniformly absolute continuity of (ddcfj)m∧γn−m we get that the integral ∫fj<−r2(ddcfj)m∧γn−m tends uniformly to zero for all j when r→∞.
Hence, for every ε>0 there exits a constant r≥0 such that |A|≤ε for all j, and by Theorem 2 in [4] we can also require that |C|≤ε. However, for a such fixed constant r the assumption (2) implies that functions max(fj,−r) converge to max(f,−r) in Capm on each E⋐Ω as j→∞ and hence we conclude by Theorem 1.3.7 in [7] that B→0 as j→∞. Therefore, we obtain that (ddcfj)m∧γn−m converges weakly to (ddcf)m∧γn−m.
To finish the proof it suffices to show that (ddcf)m∧γn−m≪Capm on any open set E⋐Ω. Let ε>0 and take δ>0 such that inequalities (ddcfj)m∧γn−m(F)≤ε hold for all j and all Borel sets F⊂E with Capm(F)<δ. Let (χk)k be a sequence of non-negative smooth functions that increases to the characteristic function of F in Ω.
Then
∫F(ddcf)m∧γn−m=limk→∞∫Ωχk(ddcf)m∧γn−m=limk→∞limj→∞∫Ωχk(ddcfj)m∧γn−m≤lim supj→∞∫F(ddcfj)m∧γn−m≤ε. |
Hence (ddcf)m∧γn−m≪Capm on E and we have completed the proof of the Theorem.
In the next lemmas we will be interested to prove some estimations known as Xing inequalities. Some of those inequalities were proved by Bedford and Taylor in [1] for bounded psh function and have several applications on the Dirichlet problem. In [9], Xing obtained a stronger version of those inequalities. In the following we will generalize those results to the class of m−subharmonic functions that are only bounded near the boundary.
Lemma 1. Let fj,f∈SHm(Ω) such that (ddcfj)m∧γn−m→(ddcf)m∧γn−m on Ω. Then the following assertions are equivalent
(1) (ddcf)m∧γn−m has zero mass on any m−polar set and h(ddcfj)m∧γn−m→h(ddcf)m∧γn−m for every locallybounded m−sh function h on Ω.
(2) The sequence (ddcfj)m∧γn−m puts uniformly small mass on sets of small m−capacity.
The proof of the above result will be omitted since it is inspired from to the proof Theorem 2 in [2] which was established in the case of plurisubharmonic functions.
Lemma 2. Let fj be a sequence of bounded m−sh functions in Ω that decreases to f∈SHm(Ω). Assume that
(1) The function f is bounded near ∂Ω.
(2) (ddcf)m∧γn−m≪Capm on any relativelycompact subset of Ω.
Then (ddcfj)m∧γn−m≪Capmuniformly for all j on each E⋐Ω.
Proof. Using the proof of Theorem 2 in [4] we obtain that g(ddcfj)m∧γn−m→g(ddcf)m∧γn−m weakly in Ω for any locally bounded m−sh function g on Ω. Thus, the Lemma follows directly from Lemma 1.
Remark 2. As a consequence of the previous lemma, we can deduce that "a function f is bounded near ∂Ω and have absolute continuous Hessian measure with respect to Capm if and only if f is the limit of functions given in Theorem 1". Indeed if we assume that f is bounded near ∂Ω and (ddcf)∧γn−m≪Capm then the sequence fj:=max(f,−j) is bounded and decreases to f. Using the quasicontiuity combined with the Dini's theorem we deduce that fj converges to f with respect to Capm. Now the lemma 2 implies that (ddcfj)∧γn−m≪Capm. Hence the sequence fj satisfies Theorem Theorem 1.
Conversely it is easy to check that every limit of functions in Theorem Theorem 1 is bounded near the boundary of Ω and with Hessian measure absolutely continuous with respect to Capm.
Lemma 3. Let f,g∈SHm(Ω) such that
(1) lim infz→∂Ω(f(z)−g(z))≥0.
(2) The functions f and g are bounded near ∂Ω and with Hessian measure absolutely continuous with respect to Capm on each E⋐Ω.
Then for any constant c≥1 and allhj ∈ SHm(Ω) with 0≤hj≤1, j=1,2,...,m, one has
1m!2∫f<g(g−f)mddch1∧...∧ddchm∧γn−m+∫f<g(c−h1)(ddcg)m∧γn−m |
≤∫f<g(c−h1)(ddcf)m∧γn−m. |
Moreover if we assume that
(ddcf)m∧γn−m≥(ddcg)m∧γn−m |
in Ω, then{f<g}=∅.
Proof. Replacing f by f+2t and then taking t↘0, we may assume that there exists a subset E⋐Ω such that {f<g}⊂E. Take fk:=max(f,−k) and gj=max(g,−j). Then {fk<gj}⊂E for k and j large enough. Using Lemma 3 in [4] we obtain that for any constant c≥1 and all hj∈SHm(Ω) such that 0≤hj≤1, j=1,2,...,m
1m!2∫fk<gj(gj−fk)mddch1∧...∧ddchm∧γn−m+∫fk<gj(c−h1)(ddcgj)m∧γn−m |
≤∫fk<gj(c−h1)(ddcfk)m∧γn−m |
where k and j are large enough. Since fk↘f then (ddcfk)m∧γn−m tends weakly to (ddcf)m∧γn−m then by Lemma 2 we get that (ddcfk)m∧γn−m≪Capm uniformly for all k in the set E. Similarly, (ddcgj)m∧γn−m≪Capm uniformly for all j in E. Now take ε>0, and let U be an open subset of Ω with Capm(U)<ε such that f, g are continuous on F=Ω∖U. Thus, we can write g=φ1+φ2 where φ1 is continuous on ¯F and φ2=0 outside of U. Then
(c−h1)(ddcgj)m∧γn−m→(c−h1)(ddcg)m∧γn−m |
weakly on Ω and we have
∫fk<φ1(c−h1)(ddcg)m∧γn−m≤limj→∞∫fk<φ1(c−h1)(ddcgj)m∧γn−m. |
The last inequality implies that
∫fk<g(c−h1)(ddcg)m∧γn−m≤∫fk<φ1(c−h1)(ddcg)m∧γn−m+∫U(c−h1)(ddcg)m∧γn−m≤limj→∞∫fk<φ1(c−h1)(ddcgj)m∧γn−m+Capm(U)≤limj→∞∫fk<g(c−h1)(ddcgj)m∧γn−m+O(ε)≤limj→∞∫fk<gj(c−h1)(ddcgj)m∧γn−m+O(ε). |
Hence if we let j→∞, we get
1m!2∫f<g(g−f)mddch1∧...∧ddchm∧γn−m+∫fk<g(c−h1)(ddcg)m∧γn−m |
≤∫fk≤g(c−h1)(ddcfk)m∧γn−m+O(ε). |
Since the functions f, g are continuous on the set Ω and fk↘f, we get
∫f≤g(c−h1)(ddcf)m∧γn−m≥∫{f≤g}∩F(c−h1)(ddcf)m∧γn−m≥limk→∞∫{f≤g}∩F(c−h1)(ddcfk)m∧γn−m≥limk→∞∫{fk≤g}∩F(c−h1)(ddcfk)m∧γn−m≥limk→∞∫fk≤g(c−h1)(ddcfk)m∧γn−m−O(ε). |
Now let k→∞ and as ε>0 is arbitrary, we obtain
1m!2∫f<g(g−f)mddch1∧...∧ddchm∧γn−m+∫f<g(c−h1)(ddcg)m∧γn−m |
≤∫f≤g(c−h1)(ddcf)m∧γn−m. |
If we apply the last inequality to f+t instead of f and then letting t↘0, we obtain the desired result.
Our main result in this paper is the following theorem where we give sufficient conditions combined with the convergence in capacity Capm for a sequence of m−subharmonic functions fk to guarantee the weak convergence of the Hessian measures (ddcfk)m∧γn−m. Such result generalizes well known results in [7,10]. It suffices to take m=n in our result to recover it.
Theorem 2. Let g∈SHm(Ω) a bounded function on Ω∖E for some E⋐Ω. Assume that there is fk∈SHm(Ω) satisfying
(1) |fk|≤|g| in Ω for all k.
(2) There exists an m−subharmonic function f in Ω such that fk→f in Capm on each E⋐Ω.
Then the sequence of measures (ddcfk)m∧γn−m converges weakly to (ddcf)m∧γn−m in Ω.
Before giving the proof of the Theorem, we need to establish some intermediate lemmas.
Lemma 4. Let f1,f2,...,fm∈SHm(Ω) such that f1 is bounded in Ω and the functions f2,...,fm are bounded near ∂Ω. For every E⋐Ω there exists CE>0 such that for all Borel subset G in E the following estimate holds
∫Gddcf1∧ddcf2∧...∧ddcfm∧γn−m≤CE(Capm(G))12m. |
Proof. Without loss of generality we can assume that for all i, the functions fi can be written, near ∂Ω, as follows
fi=αφ(z)+β |
where α>0, β>0 and φ is a defining function of Ω. Let G⊂E be a Borel subset and
fG(z)=sup{u(z):u∈SHm(Ω),u≤−1 on G,u<0 on Ω} |
and f∗G the associated upper semicontinuous regularization of G defined by
f∗G(z)=lim supζ→zfG(ζ). |
We have Capm(G)=∫Ω(ddcf∗G)m∧γn−m, limz→∂Ωf∗G(z)=0 and f∗G=−1 on G∖M for some m−polar set M, (see [7]). By the Cauchy-Schwarz inequality we obtain
∫Gddcf1∧ddcf2∧...∧ddcfm∧γn−m≤∫Ω−f∗Gddcf1∧ddcf2∧...∧ddcfm∧γn−m=∫Ωdf∗G∧dcf2∧ddcf1∧ddcf3∧...∧ddcfm∧γn−m≤A(∫Ωdf∗G∧dcf∗G∧ddcf1∧ddcf3∧...∧ddcfm∧γn−m)12=A(∫Ω−f∗Gddcf∗G∧ddcf1∧ddcf3∧...∧ddcfm∧γn−m)12 |
where
A=(∫Ωdf2∧dcf2∧ddcf1∧ddcf3∧...∧ddcfm∧γn−m)12 |
is a finite constant because of the bounded assumption of the function f1. By repeating the same argument m−1 more times we get
∫Gddcf1∧ddcf2∧...∧ddcfm∧γn−m≤AE(∫Ω−f∗G(ddcf∗G)m∧γn−m)12m≤CE(∫Ω(ddcf∗G)m∧γn−m)12m=CE(Capm(G))12m |
for some constant CE>0. This proves the lemma.
Lemma 5. Let f,g,h1,...,hm−1∈SHm(Ω) bounded functions near ∂Ω and hm∈SHm(Ω)∩L∞(Ω). If lim infz→∂Ω(f(z)−g(z))≥0 and the set {f<g} is open, then for any r≥supΩh1 one has
∫f<g(g−f)ddch1∧ddch2∧...∧ddchm∧γn−m+∫f<g(r−h1)ddcg∧ddch2∧...∧ddchm∧γn−m≤∫f<g(r−h1)ddcf∧ddch2∧...∧ddchm∧γn−m. |
Proof. Without loss of generality, one can suppose that Ω is a m−hyperconvex domain and that there exists a function φ defined on Ω such that
f=g=h1=φ near ∂Ω. |
Let {fk}, {gj} and {hl1} be a sequence of continuous m−sh functions such that fk=gj=hl1=φ near ∂Ω and fk→f as k→∞, gj→g as j→∞ and hl1→h1 as l→∞. By Lemma 3 in [4] we get
∫fk<gj(gj−fk)ddchl1∧ddch2∧...∧ddchm∧γn−m+∫fk<gj(r−hl1)ddcgj∧ddch2∧...∧ddchm∧γn−m≤∫fk<gj(r−hl1)ddcfk∧ddch2∧...∧ddchm∧γn−m. |
If we let k→∞ then by Fatou's lemma we obtain
∫f<gj(gj−f)ddchl1∧ddch2∧...∧ddchm∧γn−m+∫f<gj(r−hl1)ddcgj∧ddch2∧...∧ddchm∧γn−m≤lim infk→∞∫f<gj(r−hl1)ddcfk∧ddch2∧...∧ddchm∧γn−m. |
Since
limk→∞(r−hl1)ddcfk∧ddch2∧...∧ddchm∧γn−m=(r−hl1)ddcf∧ddch2∧...∧ddchm∧γn−m |
weakly in Ω we obtain using Lemma 4 that
(r−hl1)ddcfk∧ddch2∧...∧ddchm∧γn−m<<Capm |
for all k on each E⋐Ω. Hence ∀ε>0,∃k0>0 such that
lim infk→∞∫f<gj(r−hl1)ddcfk∧ddch2∧...∧ddchm∧γn−m≤lim infk→∞∫fk0≤gj+ε(r−hl1)ddcfk∧ddch2∧...∧ddchm∧γn−m+ε≤∫fk0≤gj+ε(r−hl1)ddcf∧ddch2∧...∧ddchm∧γn−m+ε. |
As f≤fk0 and g≤gj and ε is arbitrary chosen, we obtain
∫f<gj(gj−f)ddchl1∧ddch2∧...∧ddchm∧γn−m+∫f<g(r−hl1)ddcgj∧ddch2∧...∧ddchm∧γn−m≤∫f≤gj(r−hl1)ddcf∧ddch2∧...∧ddchm∧γn−m. |
By letting l→∞ and using the fact that
(gj−f)ddchl1∧ddch2∧...∧ddchm∧γn−m→(gj−f)ddch1∧ddch2∧...∧ddchm∧γn−m |
weakly in Ω when l→∞ we get
∫f<gj(gj−f)ddch1∧ddch2∧...∧ddchm∧γn−m+∫f<g(r−h1)ddcgj∧ddch2∧...∧ddchm∧γn−m≤∫f≤gj(r−h1)ddcf∧ddch2∧...∧ddchm∧γn−m. |
Now if we let j→∞ and using the weak convergence of (r−h1)ddcgj∧ddch2∧...∧ddchm∧γn−m combined with the Fatou lemma and the fact that the set {f<g} is supposed open, we get
∫f<g(g−f)ddch1∧ddch2∧...∧ddchm∧γn−m+∫f<g(r−h1)ddcg∧ddch2∧...∧ddchm∧γn−m≤∫f≤g(r−h1)ddcf∧ddch2∧...∧ddchm∧γn−m. |
To complete the proof it suffices to apply the previous inequality to f+t instead of f and then we take t↘0.
Now we give the proof of the Theorem 2.
Proof. By hypothesis (1), we may assume without loss of generality that there exists a compact subset K in Ω such that fk=g in Ω∖K for all k and g=fk=0 on ∂Ω. We will assume by induction that the current (ddcfk)l∧γn−m converges weakly to (ddcf)l∧γn−m in Ω for 1≤l≤m−1. Using Lemma 5, we obtain that for any r>0 and all k
∫fk<−r(−fk)(ddcfk)m−p∧γn+p−m≤∫g<−r(−g)(ddcfk)m−p∧γn+p−m≤2∫g<−r2(−g−r2)(ddcfk)m−p∧γn+p−m≤2∫g<−r2(−fk)ddcg∧(ddcfk)m−p−1∧γn+p−m≤2∫g<−r2−gddcg∧(ddcfk)m−p−1∧γn+p−m≤22∫g<−r22−g(ddcg)2∧(ddcfk)m−p−2∧γn+p−m≤...≤2m−p∫g<−r2m−p−g(ddcg)m−p∧γn+p−m. |
Hence we get that (−g)(ddcg)m−p∧γn+p−m≪(ddcg)m−p∧γn+p−m≪Capm on each E⋐Ω. So we obtain that
(−fk)(ddcfk)m−p∧γn+p−m≪Capm(∗) |
on each E⋐Ω uniformly for all k.
Replacing f and fk by max(f,−c) and max(fk,−c) respectively for a fixed constant c if necessary, we can assume that both f and fk are locally uniformly bounded. So by assumption (1) and proposition 1 we get that for any ε>0 the following writing hold
fk=fk,1+fk,2 and f=f1+f2 |
where f1 is a continuous function in Ω and fk,2=f2=0 on Ω∖U for some U⊂Ω with Capr(U)<ε. Furthermore, for each E⋐Ω∖U, one has that |fk,1−f1|<ε on E for large value of k and the functions fk,1, fk,2, f1 and f2 are bounded uniformly by a constant which does not depend on ε. If we consider the following decomposition
fk(ddcfk)m−p∧γn+p−m−f(ddcf)m−p∧γn+p−m=(fk,1−f1)(ddcfk)m−p∧γn+p−m+f1((ddcfk)m−p−(ddcf)m−p)∧γn+p−m+(fk,2(ddcfk)m−p−f2(ddcf)m−p)∧γn+p−m. |
So the proof will be completed if we show that all three terms of the right hand side in the last equality tend weakly to 0. For the third term its suffices to use (∗) to get that it tends to zero weakly and uniformly for all k when ε goes to 0. Since we have
∫E|fk,1−f1|(ddcfk)m−p∧γn+p−m≤ε∫E∖U(ddcfk)m−p∧γn+p−m+supk|fk,1−f1|∫U(ddcfk)m−p∧γn+p−m, |
and (ddcfk)m−p∧γn+p−m converges weakly to (ddcf)m−p∧γn+p−m by induction's assumption we deduce that the first and the second term in the last equality also converges weakly to zero uniformly for all k as ε→0. The result of the theorem follows.
Remark 3. (1) Using the Theorem 2, we deduce that for all j
(r−h1)ddcgj∧ddch2∧...∧ddchm∧γn−m<<Capm |
on every subset E⋐Ω.Then we can deduce that the assumption "the set {f<g} is open" in Lemma 5 is superfluous. This implies that the Lemma 5 is an improved version of Lemma 3
(2) The assumptions in the Theorem 2 can be replaced by the monotically convergence of fk towards f for f,fk∈SHm(Ω)∩L∞(Ω∖E).
Theorem 3. Let fj∈Bm(Ω) and f∈SHm(Ω)∩L∞loc(Ω). The following assertions hold
(1) If fj→f in Capm−1 in every E⋐Ω then for all h in Bm(Ω) one has that h(ddcfj)m∧γn−m converges weakly to h(ddcf)m∧γn−m.
(2) If for every E⋐Ω one has fj→f in Capm then for every ξ∈C∞0(Ω) we have that ∫Ωξh(ddcfj)m∧γn−m→∫Ωξh(ddcf)m∧γn−m uniformly for all h in Bm(Ω).
(3) If fj→f in Capm on each E⋐Ω and hj∈Bm(Ω) converges weakly to h∈Bm(Ω), then hj(ddcfj)m∧γn−m converges weakly to h(ddcf)m∧γn−m in Ω.
Proof. To prove the assertion (1), it remains to show, by induction, that for each k⩽m, (ddcfj)k∧γn−m tends weakly to (ddcf)k∧γn−m. The case for k=1 is obvious since the convergence assumption implies that fj→f in L1loc(Ω). Hence, it follows that ddcfj∧γn−m converges weakly to ddcf∧γn−m. Assume, by induction, that it is true for all k=q<m and we have to show that fj(ddcfj)q∧γn−m converges weakly to f(ddcf)q∧γn−m and by taking the operator ddc we will obtain the required statement for k=q+1. Let ε>0, the function f can be written as f=h1+h2 on Ω, where h1 is continuous, h2=0 outside an open subset U⊂Ω with capm(U)<ε, and the supremum norm of h2 depends only on the function h. We have
fj(ddcfj)q∧γn−m−f(ddcf)q∧γn−m=(fj−f)(ddcfj)q∧γn−m+h2[(ddcfj)q∧γn−m−(ddcf)q∧γn−m]+h1[(ddcfj)q∧γn−m−(ddcf)q∧γn−m]=A1+A2+A3. |
The inductive assumption gives that A3 converges to 0 in the sense of currents. On the other hand, it is easy to check that
(ddcfj)q∧γm−q−1∧γn−m+1⩽(ddc(fj+|z|2))m−1∧γn−m+1. |
The last term is dominated by a constant, independent on j, multiplied by Capm. Hence using the convergence assumption we obtain that A1 converges in the sense of currents to 0. Now since h2=0 outside U, then A2 makes arbitrarily small mass for all j by choosing ε small enough. Hence we have obtained the weak convergence of fj(ddcfj)q∧γn−m to f(ddcf)q∧γn−m. To finish the proof of the assertion (1) it suffices to use the quasicontinuity of the function h to get the desired result.
To prove (2), thanks to the assertion (1) we have that (ddcfj)m∧γn−m→(ddcf)m∧γn−m weakly in Ω and hence we may assume that Bm(Ω)={f∈SHm(Ω);0<f<1}. Let ξ∈C∞0(Ω) a test function. Changing the values of fj and f near ∂Ω, we can suppose that there exists a subset E such that supp ξ⋐E and fj=f in Ω∖E. It follows that for every ε>0 and all h in Bm(Ω), an integration by parts yields
∫Ωξh((ddcfj)m−(ddcf)m)∧γn−m=∫E∩{|fj−f|<ε}(fj−f)ddc(ξh)∧(Σm−1k=0(ddcfj)k∧(ddcf)m−1−k)∧γn−m+∫E∩{|fj−f|≥ε}(fj−f)ddc(ξh)∧(Σm−1k=0(ddcfj)k∧(ddcf)m−1−k)∧γn−m:=Aε,j+Bε,j. |
Let ξ∈C∞0(Ω) and C1 a constant sufficiently large satisfying ξ=(ξ+C1|z|2)−C1|z|2:=ξ1−ξ2, where 0≤ξ1,ξ2∈SHm(Ω)∩L∞(Ω). For the cases k=1 and k=2 we get that 2ddc(ξkh)=ddc((ξk+h)2)−ddc(h2)−ddc(ξ2k). It follows that there exists a constant C2 that does not depend on ε and j∈N such that
∣Aε,j(ξ)∣≤∣Aε,j(ξ1)∣+∣Aε,j(ξ2)∣≤C2Capm(E)ε |
and
∣Bε,j(ξ)∣≤∣Bε,j(ξ1)∣+∣Bε,j(ξ2)∣≤C2Capm(E∩{|fj−f|>ε})→0 |
as j→∞. This gives that
∫Ωξh(ddcfj)m∧γn−m→∫Ωξh(ddcf)m∧γn−m |
as j→∞ uniformly in Bm(Ω).
For the assertion (3) we have
hj(ddcfj)m∧γn−m−h(ddcf)m∧γn−m=hj((ddcfj)m−(ddcf)m)∧γn−m+(hj−h)((ddcf)m−(ddcus)m)∧γn−m+(hj−h)(ddcus)m∧γn−m=:A+B+C |
where us are smooth m−sh functions decreasing to f. Using the assertion (2) the term B goes weakly to zero as s→∞ uniformly for all j. Hence if s is a constant sufficiently large we get that both A and C converge weakly to zero as j→∞. So the assertion (3) follows.
Using Theorem 3.3, one can get that the convergence with respect to the Lebegue measure of a sequence of m−sh functions fj implies the weak convergence of fj with respect to any measure that has nos mass on every m−polar sets.
Corollary 1. If ν is a locally finite measure, fk a sequence of m−sh functions in Ω and f0∈SHm(Ω)∩L1loc(Ω,ν) satisfying the following assumptions.
i) For every m−polar set A⊂Ω one has ν(A)=0.
ii) For all k∈N, |fk|≤|f0|.
iii) For every E⋐Ω, ∫E∣fj−f∣dλ→0.
Then ∫E∣fk−f∣dν→0 as k→∞ on any E⋐Ω.
Proof. Without loss of generality we may assume that for every z∈Ω; fk(z)<0 and f(z)<0. Using hypothesis i) it suffices to show that
∀ζ∈C∞0(Ω),limk→+∞∫Ωζfkdν=∫Ωζfdν. |
For ζ∈C∞0(Ω), one has the following the following writing
∫Ωζfkdν−∫Ωζfdν=∫Ωζ(fk−max(fk,−s))dν+∫Ωζ(max(fk,−s)−max(f,−s))dν+∫Ωζ(max(f,−s)−f)dν≤2.max∣ζ∣∫suppζ∩{f0<−s}−f0dν+∫Ωζ(max(fk,−s)−max(f,−s))dν. |
As lims→+∞max∣ζ∣∫suppζ∩{f0<−s}−f0dν=0 then
∫Ωζfkdν−∫Ωζfdν≤∫Ωζ(max(fk,−s)−max(f,−s))dν. |
On the other hand, using Theorem 5.3 in [6] there exists α∈SHm(Ω)∩L∞(Ω) and h∈L1(Ω,(ddcα)m∧γn−m) such that h≥0 and 1lsuppζdν=h(ddcα)m∧γn−m. So for every ε>0 there exists s,j>0 such that
|∫Ωζfkdν−∫Ωζfdν|≤|∫Ωζmin(h,j)(max(fk,−s)−max(f,−s))(ddcα)m∧γn−m|+ε. |
So one can take g∈C(Ω) such that ∫suppζ|min(h,k)−g|(ddcα)m∧γn−m<εs. it follows that
|∫Ωζfkdν−∫Ωζfdν|≤|∫Ωζg(max(fk,−s)−max(f,−s))(ddcα)m∧γn−m|+(2max∣ζ∣+1)ε. |
The last integral tends to 0 when k→∞ by Theorem 3. Therefore the proof of the desired Theorem is completed.
In the following theorem we treat the converse sense. So we will prove that the convergence of the hessian measure associated to a sequence of m−sh functions implies, under some conditions, the convergence in capacity Capm for a such sequence.
Theorem 4. Let (fj)j⊂SHm(Ω)∩L∞(Ω) be a sequence of locally uniformly bounded functions that converges weakly to f∈SHm(Ω). Assume that
(1) lim infz→∂Ω(fj−f)≥0 uniformly for all j.
(2) There exists a positive measure dμ in Ω such that h(ddcfj)m∧γn−m converges weakly to hdμ in Ω uniformly for all h∈SHm(Ω) with 0≤h≤1.
Then (ddcf)m∧γn−m=dμ and fj→f in Capm on each E⋐Ω. Hence, if furthermorelim infz→∂Ω(f−fj)≥0 uniformly for all j then fj→f in Capm on Ω.
Proof. Let φ∈SHm(Ω) such that 0<φ<1 and E⋐Ω. For every t>0 one has
∫E∩{|fj−f|>t}(ddcφ)m∧γn−m≤Capm(E∩{fj>f+t})+∫E∩{fj<f−t}(ddcφ)m∧γn−m. |
Using the quasicontinuity of m−sh functions and the Hartog's Lemma we get that Capm(E∩{fj>f+t})→0 when j→∞. Hence, by the assumption (2) and Lemma 3 [4] we obtain
∫fj<f−t(ddcφ)m∧γn−m≤1tm∫fj<f−t(f−fj)m(ddcφ)m∧γn−m≤m!2tm∫fj<f−t(ddcfj)m∧γn−m≤m!2tm+1∫fj<f−t(u−fj)(ddcφ)m∧γn−m. |
Take ε>0, and F1⋐F2⋐Ω such that fj−f≥−ε in Ω∖F1 and {fj<f−t}⋐F1 for all j. Again by the Hartog's Lemma and the quasicontinuity of m−sh functions we get that there exist j0>0 and A⊂F2 with Capm(A)<ε such that ε+f(z)−fj(z)≥0 in F2∖A for all j≥j0. Let χ∈C∞0(F2) such that χ≥0 and χ=1 in F1. Since all the functions fj and f are uniformly bounded in F2, then for j≥j0
∫fj<f−t(ddcfj)m∧γn−m≤m!2tm+1∫fj<f−t(f−fj)(ddcφ)m∧γn−m≤∫F1∖Aχ(ε+f−fj)(ddcfj)m∧γn−m+O(ε)≤∫F2χ(f−fj)(ddcfj)m∧γn−m+O(ε)=∫F2χ(f−fj)((ddcfj)m∧γn−m−dμ)+∫F2χ(f−fj)dμ+O(ε). |
Now using assumption (3) and Corollary 1, we obtain that the last two integrals go to zero when j→∞. Hence fj→f in Capm on each E⋐Ω. Then by [6], we get (ddcf)m∧γn−m=dμ and the proof of the Theorem is complete.
In this paper we have dealt with a problem related to the convergence of a sequence of complex Hessian measures given by a sequence of m−subharmonic functions fj. By introducing some conditions, we have shown that if fj converges in Capm then the associated sequence of measures converges in the weak sense. In addition we have shown that the converse sense still true form some particular classes of m−subharmonic functions. The established results in this paper may be useful not only in the problem related to the convergence of the Hessian measure but also in the resolution of the famous complex Hessian equations.
Authors extend their appreciation to the Deanship of Scientific Research at Jouf University for funding this work through research Grant No. DSR-2021-03-0113.
Authors declare that no conflicts of interest in this manuscript.
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