Stability prediction of circular sliding failure soil slopes based on a genetic algorithm optimization of random forest algorithm

Shengming Hu; Yongfei Lu; Xuanchi Liu; Cheng Huang; Zhou Wang; Lei Huang; Weihang Zhang; Xiaoyang Li; Shengming Hu; Yongfei Lu; Xuanchi Liu; Cheng Huang; Zhou Wang; Lei Huang; Weihang Zhang; Xiaoyang Li

doi:10.3934/era.2024284

Electronic Research Archive

2024, Volume 32, Issue 11: 6120-6139. doi: 10.3934/era.2024284

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Research article Special Issues

Stability prediction of circular sliding failure soil slopes based on a genetic algorithm optimization of random forest algorithm

1.
National and Provincial Joint Engineering Laboratory for the Hydraulic Engineering Safety and Efficient Utilization of Water Resources of Poyang Lake Basin, Nanchang Institute of Technology, Nanchang, Jiangxi 330099, China
2.
Jiangxi Academy of Water Science and Engineering, Nanchang, Jiangxi 330029, China
3.
Badong National Observation and Research Station of Geohazards, China University of Geosciences, Wuhan, Hubei 430074, China

Received: 20 May 2024 Revised: 22 July 2024 Accepted: 29 October 2024 Published: 14 November 2024

Accurate and effective landslide prediction and early detection of potential geological hazards are of great importance for landslide hazard prevention and control. However, due to the hidden, sudden, and uncertain nature of landslide disasters, traditional geological survey and investigation methods are time-consuming and laborious, and it is difficult to timely and accurately investigate and predict slope stability over a large area. Machine learning approaches provide an opportunity to address this limitation. Here, we present an intelligent slope stability assessment method based on a genetic algorithm optimization of random forest algorithm (GA-RF algorithm). Based on 80 sets of typical slope samples, weight (γ), slope height (H), pore pressure value (P), cohesion force (C), internal friction angle (φ) and slope inclination angle (°) were selected as characteristic variables for slope stability evaluation. Based on the GA-RF algorithm and incorporating 10-fold cross validation, a regression prediction model is trained on the training dataset, and then regression prediction is performed on the test dataset to verify the predictive performance of the model. The results indicate that the GA-RF prediction model has decent regression performance and has certain potential for slope stability analysis.

Keywords:

Citation: Shengming Hu, Yongfei Lu, Xuanchi Liu, Cheng Huang, Zhou Wang, Lei Huang, Weihang Zhang, Xiaoyang Li. Stability prediction of circular sliding failure soil slopes based on a genetic algorithm optimization of random forest algorithm[J]. Electronic Research Archive, 2024, 32(11): 6120-6139. doi: 10.3934/era.2024284

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Abstract

1. Introduction

Nonlinear conformable evolution equations (NLCEEs) became significantly useful tools in the modeling of many problems in sciences and technology. Exact wave solutions of these models are very important and active research area. NLCEEs are getting the attention of researchers and becoming phenomenal subject in the contemporary science. Many systems in mathematical physics and fluid dynamics are modeled via fractional differential equations. Exact wave solutions of these models are quite active and important research area in science. For the numerical and exact solutions of NLCEEs, there are some efficient techniques in the literature such as method of $(G'/G)-$ expansion, extended sinh-Gordon equation expansion, Kudryashov, exp-function, exponential rational function, modified Khater, functional variable, improved Bernoulli sub-equation function, sub-equation, tanh, Jacobi elliptic function expansion, auxiliary equation, extended direct algebraic, etc., see ^{[1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27]}. The functional variable (FV) method was introduced in ^[28] and was further developed in the studies ^{[29,30,31,32,33]}. FV method treats nonlinear PDEs with linear techniques and constructs interesting type of soliton solutions (kink, black, white, pattern, etc). The conformable fractional derivatives don’t have a physical meaning as the Caputo or Riemann-Liouville derivatives. This situation is a general open problem for fractional calculus. Despite this many physical applications of conformable fractional derivative appear in the literature. Dazhi Zhao and Maokang Luo generalized the conformable fractional derivative and give the physical interpretation of generalized conformable derivative. In addition, with the help of this fractional derivative and some important formulas, one can convert conformable fractional partial differential equations into integer-order differential equations by travelling wave transformation ^[39].

The aim of the present paper is present new exact solutions to conformable Klein-Gordon (KG) equation with quintic nonlinearity by employing FV method. Nonlinear conformable Klein-Gordon equation has the form (for $\alpha = 1$ , see ^[34])

$\begin{equation} D_{t}^{2\alpha } u-k^{2} u_{xx} +\gamma u-\lambda u^{n} +\sigma u^{2n-1} = 0, \end{equation}$

(1.1)

in which $u$ represents wave profile, and $k, \gamma, \lambda, \sigma \ne 0$ are real valued constants. KG equation arises in theoretical physics, particularly in the area of relativistic quantum mechanics and it is used in modeling of dislocations in crystals.

For $n = 3$ , Eq (1.1) is known as conformable Klein-Gordon equation with quintic nonlinearity ^[24]

$\begin{equation} \frac{\partial ^{2\alpha } u}{\partial t^{2\alpha } } -k^{2} \frac{\partial ^{2} u}{\partial x^{2} } +\gamma u-\lambda u^{3} +\sigma u^{5} = 0,\quad \sigma \ne 0. \end{equation}$

(1.2)

In particular, if $\sigma = 0,$ then Eq (1.2) reduces to some other PDEs including the ones in ^[35,36].

(i) Conformable Klein-Gordon equation

$\begin{equation} \frac{\partial ^{2\alpha } u}{\partial t^{2\alpha } } -\frac{\partial ^{2} u}{\partial x^{2} } +\kappa u+\beta u^{3} = 0. \end{equation}$

(1.3)

(ii) Conformable Landau-Ginzburg-Higgs equation

$\begin{equation} \frac{\partial ^{2\alpha } u}{\partial t^{2\alpha } } -p\frac{\partial ^{2} u}{\partial x^{2} } -m^{2} u+g^{2} u^{3} = 0. \end{equation}$

(1.4)

(iii) Conformable $\Phi$ -four equation

$\begin{equation} \frac{\partial ^{2\alpha } u}{\partial t^{2\alpha } } -\frac{\partial ^{2} u}{\partial x^{2} } +u-u^{3} = 0. \end{equation}$

(1.5)

(iv) Conformable Duffing equation

$\begin{equation} \frac{\partial ^{2\alpha } u}{\partial t^{2\alpha } } +bu+cu^{3} = 0. \end{equation}$

(1.6)

(v) Conformable Sine-Gordon equation

$\begin{equation} \frac{\partial ^{2\alpha } u}{\partial t^{2\alpha } } -\frac{\partial ^{2} u}{\partial x^{2} } +u-\frac{1}{6} u^{3} = 0. \end{equation}$

(1.7)

Next, we overview method of functional variable.

2. Method of functional variable

Consider the NLCEE:

$\begin{equation} F(u,D_{t}^{\alpha } u,u_{x} ,D_{t}^{2\alpha } u,u_{xx} ,\ldots ) = 0,\quad \quad t\ge 0,\; \quad 0 \lt \alpha \le 1, \end{equation}$

(2.1)

in which $F$ is a polynomial function in terms of unknown function $u,$ and $D_{t}^{\alpha } u$ is defined as ^[37]

$\begin{equation} D_{t}^{\alpha } u(x,t) = \mathop{\lim }\limits_{\varepsilon \to 0} \frac{u(x,t+\varepsilon t^{1-\alpha } )-u(x,t)}{\varepsilon } , \end{equation}$

(2.2)

where $0 < t, \, \alpha \in (0, 1].$

Now, let us define the wave variable ^[38]

$\begin{equation} u(x,t) = U(\xi ),\;\;\;\;\;\xi = x-\omega \frac{t^{\alpha } }{\alpha }, \end{equation}$

(2.3)

in which $\omega$ is a parameter which will be determined later. Hence, we can write that

$D_{t}^{\alpha } u = -\omega U'(\xi ),\quad \; u_{x} = U'(\xi ),\; \; \quad D_{t}^{2\alpha } u = \omega ^{2} U''(\xi ),\quad \; \ldots.$

By writing Eq (2.3) in Eq (2.1), we get ordinary differential equations:

$\begin{equation} G(U(\xi ),U'(\xi ),U''(\xi ),U'''(\xi ),\ldots ) = 0. \end{equation}$

(2.4)

Now, define a transformation:

$\begin{equation} U_{\xi } = F(U), \end{equation}$

(2.5)

from which, we obtain

$U_{\xi \xi } = \frac{1}{2} (F^{2} )',$

$\begin{equation} U_{\xi \xi \xi } = \frac{1}{2} (F^{2} )''\sqrt{F^{2} }, \end{equation}$

(2.6)

$U_{\xi \xi \xi \xi } = \frac{1}{2} [(F^{2} )'''F^{2} +(F^{2} )''(F^{2} )'],$

$\;\;\;\vdots$

in which $\textbf{"}\, {'}\, \textbf{''}$ stands for $\frac{d}{dU}$ .

Using Eq (2.6) in Eq (2.3), ordinary differential Eq (2.3) can be reduced to:

$\begin{equation} G(U,F,F',F'',F''',\ldots ) = 0. \end{equation}$

(2.7)

Now, let us consider the equation

$\begin{equation} (U(\xi )_{\xi } )^{2} = aU^{2} (\xi )+bU^{2+n} (\xi )+cU^{2+2n} (\xi ),\,0 \lt n, \end{equation}$

(2.8)

in which $a, b, c$ are parameters.

Next, we present a set of exact wave solutions of (2.8), see e.g., ^[39]:

Case 1. If $a > 0$ , then (2.8) admits hyperbolic function solution:

$\begin{equation} U_{1} (\xi ) = \left[\frac{-ab\sec h^{2} (\frac{n\sqrt{a} }{2} \xi )}{b^{2} -ac(1-\tanh (\frac{n\sqrt{a} }{2} \xi ))^{2} } \right]^{\frac{1}{n} }. \end{equation}$

(2.9)

Case 2. If $a, \; c > 0$ , then (2.8) admits the following hyperbolic function solution

$\begin{equation} U_{2} (\xi ) = \left[\frac{a\csc h^{2} (\frac{n\sqrt{a} }{2} \xi )}{b+2\sqrt{ac} \coth (\frac{n\sqrt{a} }{2} \xi )} \right]^{\frac{1}{n} }, \end{equation}$

(2.10)

$\begin{equation} U_{3} (\xi ) = \left[\frac{4a\left(\cosh (n\sqrt{a} \xi )+\sinh (n\sqrt{a} \xi )\right)}{4ac-\left(b+\cosh (n\sqrt{a} \xi )+\sinh (n\sqrt{a} \xi )\right)^{2} } \right]^{\frac{1}{n} }, \end{equation}$

(2.11)

$\begin{equation} U_{4} (\xi ) = \left[\frac{8a^{2} \sec h(n\sqrt{a} \xi )}{b^{2} +4a(a-c)-4ab\sec h(n\sqrt{a} \xi )+(b^{2} -4a(a+c))\tanh (n\sqrt{a} \xi )} \right]^{\frac{1}{n} }, \end{equation}$

(2.12)

$\begin{equation} U_{5} (\xi ) = \left[\frac{a\csc h(\frac{n\sqrt{a} }{2} \xi )}{b\sinh (\frac{n\sqrt{a} }{2} \xi )+2\sqrt{ac} \cosh (\frac{n\sqrt{a} }{2} \xi )} \right]^{\frac{1}{n} }, \end{equation}$

(2.13)

$\begin{equation} U_{6} (\xi ) = \left[\frac{a\sec h(\frac{n\sqrt{a} }{2} \xi )}{2\sqrt{ac} \sinh (\frac{n\sqrt{a} }{2} \xi )-b\cosh (\frac{n\sqrt{a} }{2} \xi )} \right]^{\frac{1}{n} }. \end{equation}$

(2.14)

Case 3. If $a > 0$ and $b^{2} -4ac > 0$ , then (2.8) admits the following hyperbolic function solution

$\begin{equation} U_{7} (\xi ) = \left[\frac{2a\sec h(n\sqrt{a} \xi )}{-b\sec h(n\sqrt{a} \xi )\pm \sqrt{b^{2} -4ac} } \right]^{\frac{1}{n} }. \end{equation}$

(2.15)

Case 4. If $a > 0$ and $b^{2} -4ac < 0$ , then (2.8) admits the following hyperbolic function solution

$\begin{equation} U_{8} (\xi ) = \left[\frac{2a\csc h(n\sqrt{a} \xi )}{\pm \sqrt{4ac-b^{2} } -b\csc h(n\sqrt{a} \xi )} \right]^{\frac{1}{n} }. \end{equation}$

(2.16)

Case 5. If $a > 0$ and $b^{2} -4ac = 0$ , then (2.8) admits the following hyperbolic function solution

$\begin{equation} U_{9} (\xi ) = \left[-\frac{a}{c} \left(1\pm \tanh (\frac{n}{2} \sqrt{a} \xi )\right)\right]^{\frac{1}{n} }, \end{equation}$

(2.17)

$\begin{equation} U_{10} (\xi ) = \left[-\frac{a}{c} \left(1\pm \coth (\frac{n}{2} \sqrt{a} \xi )\right)\right]^{\frac{1}{n} } . \end{equation}$

(2.18)

Case 6. If $a < 0$ and $c > 0$ , then (2.8) admits the following triangular function solution

$\begin{equation} U_{11} (\xi ) = \left[\frac{2a}{-b\pm \sqrt{b^{2} -4ac} \sin (n\sqrt{-a} \xi )} \right]^{\frac{1}{n} }, \end{equation}$

(2.19)

$\begin{equation} U_{12} (\xi ) = \left[\frac{2a}{-b\pm \sqrt{b^{2} -4ac} \cos (n\sqrt{-a} \xi )} \right]^{\frac{1}{n} }, \end{equation}$

(2.20)

$\begin{equation} U_{13} (\xi ) = \left[\frac{a\sec ^{2} (\frac{n\sqrt{-a} }{2} \xi )}{-b+2\sqrt{-ac} \tan (\frac{n\sqrt{-a} }{2} \xi )} \right]^{\frac{1}{n} } , \end{equation}$

(2.21)

$\begin{equation} U_{14} (\xi ) = \left[\frac{a\csc ^{2} (\frac{n\sqrt{-a} }{2} \xi )}{-b+2\sqrt{-ac} \cot (\frac{n\sqrt{-a} }{2} \xi )} \right]^{\frac{1}{n} } , \end{equation}$

(2.22)

$\begin{equation} U_{15} (\xi ) = \left[\frac{-a\left(1+(\tan (n\sqrt{-a} \xi )\pm \sec (n\sqrt{-a} \xi ))^{2} \right)}{b-2\sqrt{-ac} \tan (n\sqrt{-a} \xi )\pm \sec (n\sqrt{-a} \xi )} \right]^{\frac{1}{n} }, \end{equation}$

(2.23)

$\begin{equation} U_{16} (\xi ) = \left[\frac{-a\csc (\frac{n\sqrt{-a} }{2} \xi )}{b\sin (\frac{n\sqrt{-a} }{2} \xi )+2\sqrt{-ac} \cos (\frac{n\sqrt{-a} }{2} \xi )} \right]^{\frac{1}{n} } , \end{equation}$

(2.24)

$\begin{equation} U_{17} (\xi ) = \left[\frac{a\sec (\frac{n\sqrt{-a} }{2} \xi )}{2\sqrt{-ac} \sin (\frac{n\sqrt{-a} }{2} \xi )-b\cos (\frac{n\sqrt{-a} }{2} \xi )} \right]^{\frac{1}{n} } . \end{equation}$

(2.25)

Case 7. If $a > 0$ and $b = 0$ , then (2.8) admits the following hyperbolic function solution

$\begin{equation} U_{18} (\xi ) = \left[\pm \sqrt{\frac{a}{c} } \csc h(n\sqrt{a} \xi )\right]^{\frac{1}{n} } ,\quad \quad (c \gt 0), \end{equation}$

(2.26)

$\begin{equation} U_{19} (\xi ) = \left[\pm \sqrt{-\frac{a}{c} } \sec h(n\sqrt{a} \xi )\right]^{\frac{1}{n} } ,\quad \quad (c \lt 0). \end{equation}$

(2.27)

Case 8. If $a < 0$ and $b = 0$ , then (2.8) admits the following triangular function solution

$\begin{equation} U_{20} (\xi ) = \left[\pm \sqrt{-\frac{a}{c} } \csc (n\sqrt{a} \xi )\right]^{\frac{1}{n} } ,\quad \quad (\, c \gt 0), \end{equation}$

(2.28)

$\begin{equation} U_{21} (\xi ) = \left[\pm \sqrt{-\frac{a}{c} } \sec (n\sqrt{-a} \xi )\right]^{\frac{1}{n} } ,\quad \quad (c \lt 0). \end{equation}$

(2.29)

Case 9. If $a > 0$ and $c = 0$ , then (2.8) admits the following hyperbolic function solution

$\begin{equation} U_{22} (\xi ) = \left[-\frac{a}{b} \csc h^{2} (\frac{n\sqrt{a} }{2} \xi )\right]^{\frac{1}{n} }, \end{equation}$

(2.30)

$\begin{equation} U_{23} (\xi ) = \left[\frac{a}{b} \sec h^{2} (\frac{n\sqrt{a} }{2} \xi )\right]^{\frac{1}{n} }. \end{equation}$

(2.31)

Case 10. If $a < 0$ and $c = 0$ , then (2.8) admits the following triangular function solution

$\begin{equation} U_{24} (\xi ) = \left[\frac{a}{b} \csc ^{2} (\frac{n\sqrt{-a} }{2} \xi )\right]^{\frac{1}{n} }, \end{equation}$

(2.32)

$\begin{equation} U_{25} (\xi ) = \left[\frac{a}{b} \sec ^{2} (\frac{n\sqrt{-a} }{2} \xi )\right]^{\frac{1}{n} }. \end{equation}$

(2.33)

3. Conformable Klein-Gordon with quintic nonlinearity

Using transformation of traveling wave; $u(x, t) = U(\xi), \; \xi = x-\omega \frac{t^{\alpha}}{\alpha},$ Eq (1.1) is written as:

$\begin{equation} (w^{2} -k^{2} )U_{\xi \xi } +\gamma U-\lambda U^{3} +\sigma U^{5} = 0, \end{equation}$

(3.1)

$\begin{equation} U_{\xi \xi } = \frac{1}{w^{2} -k^{2} } \left[-\gamma U+\lambda U^{3} -\sigma U^{5} \right]. \end{equation}$

(3.2)

Writing Eq (2.5) in Eq (3.2), we get:

$\begin{equation} \frac{1}{2} (F^{2} )' = \frac{1}{w^{2} -k^{2} } \left[-\gamma U+\lambda U^{3} -\sigma U^{5} \right], \end{equation}$

(3.3)

where the prime denotes differentiation for $\xi$ . From the integrating of Eq (3.3), we obtain:

$\begin{equation} F(U)^{2} = \frac{1}{w^{2} -k^{2} } \left[-\gamma U^{2} +\frac{2\lambda }{4} U^{4} -\frac{\sigma }{3} U^{6} \right]. \end{equation}$

(3.4)

Using the traveling wave transformation (2.5), we have

$\begin{equation} (U_{\xi } )^{2} = aU^{2} +bU^{4} +cU^{6}, \end{equation}$

(3.5)

where

$a = -\frac{\gamma }{w^{2} -k^{2} }, b = \frac{\lambda }{2(w^{2} -k^{2} )}, c = -\frac{\sigma }{3(w^{2} -k^{2} )}.$

By using the relations (16–40), we obtain exact solutions of conformable KG equation with quintic nonlinearity (1.2).

Case 1. If $\frac{\gamma }{w^{2} -k^{2} } < 0$ , then (1.2) admits the following hyperbolic function solution

$\begin{equation} u_{1} (x,t) = \left[\frac{\frac{\gamma \lambda }{2} \sec h^{2} (\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))}{\frac{\lambda ^{2} }{2} -\frac{\gamma \sigma }{3} (1-\tanh (\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } )))^{2} } \right]^{\frac{1}{2} }. \end{equation}$

(3.6)

Case 2. If $\frac{\gamma }{w^{2} -k^{2} } < 0, \; \frac{\sigma }{3(w^{2} -k^{2})} < 0$ , then (1.2) admits the following hyperbolic function solution

$\begin{equation} u_{2} (x,t) = \left[\frac{-\gamma \csc h^{2} (\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))}{\frac{\lambda }{2} +2\sqrt{\frac{\gamma \sigma }{3} } \coth (\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))} \right]^{\frac{1}{2} }, \end{equation}$

(3.7)

$\begin{equation} U_{3} (x,t) = \left[\frac{-4\gamma \left(\cosh (2\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))+\sinh (2\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\right)}{\frac{4\gamma \sigma }{3(w^{2} -k^{2} )} -\left(\frac{\lambda }{2} +\cosh (2\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))+\sinh (2\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\right)^{2} } \right]^{\frac{1}{2} }, \end{equation}$

(3.8)

$\begin{equation} \begin{array}{l} {u_{4} (x,t) = \left[\frac{8\gamma ^{2} \sec h(2\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))}{\frac{\lambda ^{2} }{4} +4\gamma (\gamma -\frac{\sigma }{3} )+2\gamma \lambda \sec h(2\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))+} \right. } \\ {\left. \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \frac{}{(\frac{\lambda ^{2} }{4} -4\gamma (\gamma -\frac{\sigma }{3} ))\tanh (2\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))} \right]^{\frac{1}{2} } ,} \end{array} \end{equation}$

(3.9)

$\begin{equation} u_{5} (x,t) = \left[\frac{-\gamma \csc h(\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))}{\frac{\lambda }{2} \sinh (\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))+2\sqrt{\frac{\gamma \sigma }{3} } \cosh (\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))} \right]^{\frac{1}{2} }, \end{equation}$

(3.10)

$\begin{equation} u_{6} (x,t) = \left[\frac{-\gamma \sec h(\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))}{2\sqrt{\frac{\gamma \sigma }{3} } \sinh (\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))-\frac{\lambda }{2} \cosh (\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))} \right]^{\frac{1}{2} }. \end{equation}$

(3.11)

Case 3. If $\frac{\gamma }{w^{2} -k^{2} } < 0$ and $\lambda ^{2} > \frac{16}{3} \gamma \sigma$ , then (1.2) admits the following hyperbolic function solution

$\begin{equation} u_{7} (x,t) = \left[\frac{-2\gamma \sec h(2\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))}{-\frac{\lambda }{2} \sec h(2\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\pm \sqrt{3\lambda ^{2} -16\gamma \sigma } } \right]^{\frac{1}{2} } . \end{equation}$

(3.12)

Case 4. If $\frac{\gamma }{w^{2} -k^{2} } < 0$ and $\lambda ^{2} < \frac{16}{3} \gamma \sigma$ , then (1.2) admits the following hyperbolic function solution

$\begin{equation} u_{8} (x,t) = \left[\frac{-2\gamma \csc h(2\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))}{\pm \sqrt{16\gamma \sigma -3\lambda ^{2} } -\frac{\lambda }{2} \csc h(2\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))} \right]^{\frac{1}{2} } . \end{equation}$

(3.13)

Case 5. If $\frac{\gamma }{w^{2} -k^{2} } < 0$ and $\lambda = \pm 4\sqrt{\frac{\gamma \sigma }{3} }$ , then (1.2) admits the following hyperbolic function solution

$\begin{equation} u_{9} (x,t) = \left[-\frac{3\gamma }{\sigma } \left(1\pm \tanh (\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\right)\right]^{\frac{1}{2} }, \end{equation}$

(3.14)

$\begin{equation} u_{10} (x,t) = \left[-\frac{3\gamma }{\sigma } \left(1\pm \coth (\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\right)\right]^{\frac{1}{2} }. \end{equation}$

(3.15)

Case 6. If $\frac{\gamma }{w^{2} -k^{2} } > 0$ and $\frac{\sigma }{3(w^{2} -k^{2})} < 0$ , then (1.2) admits the following triangular function solution

$\begin{equation} u_{11} (x,t) = \left[\frac{-2\gamma }{-\frac{\lambda }{2} \pm \sqrt{3\lambda ^{2} -16\gamma \sigma } \sin (2\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))} \right]^{\frac{1}{2} } , \end{equation}$

(3.16)

$\begin{equation} u_{12} (x,t) = \left[\frac{-2\gamma }{-\frac{\lambda }{2} \pm \sqrt{3\lambda ^{2} -16\gamma \sigma } \cos (2\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))} \right]^{\frac{1}{2} } , \end{equation}$

(3.17)

$\begin{equation} u_{13} (x,t) = \left[\frac{-\gamma \sec ^{2} (\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))}{-\frac{\lambda }{2} +2\sqrt{-\frac{\gamma \sigma }{3} } \tan (\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))} \right]^{\frac{1}{2} }, \end{equation}$

(3.18)

$\begin{equation} u_{14} (x,t) = \left[\frac{-\gamma \csc ^{2} (\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))}{-\frac{\lambda }{2} +2\sqrt{-\frac{\gamma \sigma }{3} } \cot (\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))} \right]^{\frac{1}{2} }, \end{equation}$

(3.19)

$\begin{equation} u_{15} (x,t) = \left[\frac{\gamma \left(1+(\tan (2\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\pm \sec (2\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } )))^{2} \right)}{\frac{\lambda }{2} -2\sqrt{-\frac{\gamma \sigma }{3} } \tan (2\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\pm \sec (2\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))} \right]^{\frac{1}{2} }, \end{equation}$

(3.20)

$\begin{equation} u_{16} (x,t) = \left[\frac{\gamma \csc (\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))}{\frac{\lambda }{2} \sin (\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))+2\sqrt{-\frac{\gamma \sigma }{3} c} \cos (\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))} \right]^{\frac{1}{2} }, \end{equation}$

(3.21)

$\begin{equation} u_{17} (x,t) = \left[\frac{-\gamma \sec (\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))}{2\sqrt{-\frac{\gamma \sigma }{3} } \sin (\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))-\frac{\lambda }{2} \cos (\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))} \right]^{\frac{1}{2} }. \end{equation}$

(3.22)

Case 7. If $\frac{\gamma }{w^{2} -k^{2} } < 0$ and $\lambda = 0$ , then (1.2) admits the following hyperbolic function solution

$\begin{equation} u_{18} (x,t) = \left[\pm \sqrt{\frac{3\gamma }{\sigma } } \csc h(2\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\right]^{\frac{1}{2} } ,\quad \quad (\frac{\sigma }{3(w^{2} -k^{2} )} \lt 0), \end{equation}$

(3.23)

$\begin{equation} u_{19} (x,t) = \left[\pm \sqrt{-\frac{3\gamma }{\sigma } } \sec h(2\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\right]^{\frac{1}{2} } ,\quad \quad (\frac{\sigma }{3(w^{2} -k^{2} )} \gt 0). \end{equation}$

(3.24)

Case 8. If $\frac{\gamma }{w^{2} -k^{2} } > 0$ and $\lambda = 0$ , then (1.2) admits the following triangular function solution

$\begin{equation} u_{20} (x,t) = \left[\pm \sqrt{-\frac{3\gamma }{\sigma } } \csc (2\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\right]^{\frac{1}{2} } ,\quad \quad (\frac{\sigma }{3(w^{2} -k^{2} )} \lt 0), \end{equation}$

(3.25)

$\begin{equation} u_{21} (x,t) = \left[\pm \sqrt{-\frac{3\gamma }{\sigma } } \sec (2\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\right]^{\frac{1}{2} } ,\quad \quad (\frac{\sigma }{3(w^{2} -k^{2} )} \gt 0). \end{equation}$

(3.26)

Case 9. If $\frac{\gamma }{w^{2} -k^{2} } < 0$ and $\sigma = 0$ , then (1.2) admits the following hyperbolic function solution

$\begin{equation} u_{22} (x,t) = \left[\frac{2\gamma }{\lambda } \csc h^{2} (\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\right]^{\frac{1}{2} }, \end{equation}$

(3.27)

$\begin{equation} u_{23} (x,t) = \left[-\frac{2\gamma }{\lambda } \sec h^{2} (\sqrt{-\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\right]^{\frac{1}{2} }. \end{equation}$

(3.28)

Case 10. If $\frac{\gamma }{w^2-k^2 } > 0$ and $\sigma = 0$ , then ((1.2)) admits the following triangular function solution

$\begin{equation} u_{24} (x,t) = \left[-\frac{2\gamma }{\lambda } \csc ^{2} (\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\right]^{\frac{1}{2} }, \end{equation}$

(3.29)

$\begin{equation} u_{25} (x,t) = \left[-\frac{2\gamma }{\lambda } \sec ^{2} (\sqrt{\frac{\gamma }{w^{2} -k^{2} } } (x-\omega \frac{t^{\alpha } }{\alpha } ))\right]^{\frac{1}{2} }. \end{equation}$

(3.30)

4. Graphical representations

In this part, some graphical representations of exact wave solutions of conformable KG equation are presented in three different forms. 3D plots of exact solutions $\left|u_{3} \right|, \, \left|u_{3} \right|, \; \left|u_{3} \right|$ are displayed in Figures 1(a), 2(a), 3(a), respectively. Figures 1(b), , and demonstrate the shape of contour plot of exact wave solutions $\left|u_{3}\right|, \, \left|u_{3}\right|$ and $\left|u_{3}\right|.$ 2D line plot of exact wave solutions $\left|u_{3} \right|, \, \left|u_{3} \right|$ and $\left|u_{3} \right|$ are presented in Figures 1(c), , and with $\; t = \; 0.2, \; t = \; 0.4, \; t = 0.6, \; t = 0.8, \, \, t = 1.$

Figure 1. 3D-plot of the modulus (left), the contour plot (middle) and 2D-polar plot (right) parts of the exact wave solution of

$\left|u_{1} \right|$ when

$\sigma = 0.5, \; \omega = 1, \gamma = 1, \lambda = 1, k = 1.5,$ and

$\alpha = 0.9$ .

DownLoad: Full-Size Img PowerPoint

Figure 2. 3D-plot of the modulus (left), the contour plot (middle) and 2D-polar plot (right) parts of the exact wave solution of

$\left|u_{2} \right|$ when

$\sigma = 3, \; \omega = 1, \gamma = 0.75, \lambda = 1.5, k = 2,$ and

$\alpha = 0.9$ .

DownLoad: Full-Size Img PowerPoint

Figure 3. 3D-plot of the modulus (left), the contour plot (middle) and 2D-polar plot (right) parts of the exact wave solution of

$\left|u_{11} \right|$ when

$\sigma = -1, \; \omega = 2, \gamma = 1.5, \lambda = 2, k = 0.5,$ and

$\alpha = 1$ .

DownLoad: Full-Size Img PowerPoint

Solitary wave solutions (3.6)–(3.15), (3.23), (3.24), (3.26) and (3.27) represent bell-profile and kink-profile solitary wave solutions, and solutions (3.16)–(3.22), (3.25) and (3.28) are triangular periodic wave solutions. These solutions may be useful to explain some physical phenomena in dynamical systems that are described by the system of conformable fractional equations for Klein-Gordon with quantic nonlinearity.

5. Conclusions and outlook

We presented new exact solutions of conformable Klein-Gordon equation with quantic nonlinearity by using method of functional variable. Solutions were expressed in terms of solitary waves such as kink-profile and bell-profile. Moreover, we obtain exact periodic solutions of the KG equation. Computational results show that FV method is a highly efficient technique in the solutions of conformable PDEs. In a future research work, we will investigate the applicability of these results to some fractional-stochastic differential equations.

Acknowledgments

The work was supported by the Natural Science Foundation of China (Grant Nos. 61673169, 11301127, 11701176, 11626101, 11601485).

Conflict of interest

The authors declare that they have no known competing financial interests or personal relationships that could have appeared to influence the work reported in this paper.

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Stability prediction of circular sliding failure soil slopes based on a genetic algorithm optimization of random forest algorithm

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5. Conclusions and outlook

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Stability prediction of circular sliding failure soil slopes based on a genetic algorithm optimization of random forest algorithm

Related Papers:

Abstract

1. Introduction

2. Method of functional variable

3. Conformable Klein-Gordon with quintic nonlinearity

4. Graphical representations

5. Conclusions and outlook

Acknowledgments

Conflict of interest

References

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Abstract

1. Introduction

2. Method of functional variable

3. Conformable Klein-Gordon with quintic nonlinearity

4. Graphical representations

5. Conclusions and outlook

Acknowledgments

Conflict of interest

References