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Commentary on the Pinotsis and Friston Neural Fields DCM and the Cadonic and Albensi Oscillations and NMDA Receptors Articles

  • Received: 03 July 2014 Accepted: 17 August 2014 Published: 16 September 2014
  • Citation: Robert A. Moss, Jarrod Moss. Commentary on the Pinotsis and Friston Neural Fields DCM and the Cadonic and Albensi Oscillations and NMDA Receptors Articles[J]. AIMS Neuroscience, 2014, 1(2): 158-162. doi: 10.3934/Neuroscience.2014.2.158

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  • Mathematical inequalities are powerful tools that establish relationships and bounds between mathematical quantities. They have gained increasing importance in recent years, driving research and advancements in various fields of study. For investigations related to the theory of mathematical inequalities, we refer the reader to several key works. Foundational results on operator inequalities and numerical radius inequalities can be found in [1,2]. Classical refinements of the Cauchy-Schwarz inequality and discrete inequalities are discussed in [3,4,5]. Comprehensive studies on numerical radius inequalities and matrix exponential inequalities are presented in [6,7]. Recent developments involving preinvexity and stochastic harmonically convexity are explored in [8,9]. Further insights and related results are available in [10] and the references therein. Additionally, for inequalities in different spaces, we refer to the works of S. Shi et al. [11], G. Wang et al. [5], and Y. Wu et al. [12].

    Recently, the authors of this paper have previously investigated the Selberg inequality and the Selberg operator in [13,14], focusing specifically on norm and numerical radius inequalities related to any positive operator, since every Selberg operator is a positive contraction. This work builds upon their previous research in this area.

    Before delving into these results, we let $ \mathcal{B}(\mathcal{H}) $ denote the $ C^* $-algebra of all bounded linear operators on $ \mathcal{H} $, with the identity operator denoted by $ I $. If $ S\in \mathcal{B}(\mathcal{H}) $, then $ S^* $ denotes the adjoint of $ S $. We define a positive operator, denoted $ S \geq 0 $, as one for which $ \langle Sy, y\rangle \geq 0 $ holds for all $ y\in \mathcal{H} $. This notion of positivity induces an ordering $ A \geq B $ for self-adjoint operators if and only if $ A-B\geq 0 $.

    The numerical radius and operator norm of $ S\in \mathcal{B}(\mathcal{H}) $ are respectively given by:

    $ \omega(S) = \sup\{|\lambda|: \lambda \in W(S)\} = \sup\limits_{\|y\| = 1} |\langle Sy, y\rangle|\quad\text{and}\quad\|S\| = \sup\limits_{\|y\| = 1} \|Sy\|, $

    where $ W(S) = \{\langle Sy, y\rangle\, :\; y\in {\mathcal{H}}, \; \|y\| = 1\} $ is the numerical range of $ S $. Recent developments and research on numerical range, norm, and numerical radius inequalities of operators are discussed in several key works. For refinements and improvements of generalized numerical radius inequalities, see [15,16,17]. Numerical radius inequalities for operator matrices and certain $ 2 \times 2 $ operator matrices are explored in [18,19]. Additionally, norm and numerical radius inequalities for sums of operators are presented in [20]. Further insights and related results can be found in these works and the references cited therein.

    It is well known that the numerical radius is not submultiplicative, meaning that we cannot assert $ \omega(AB) \leq \omega(A)\omega(B) $ for operators $ A $ and $ B $, even when $ A $ and $ B $ commute. Due to this fact, it is essential to find upper bounds for the numerical radius of the product of operators. For this reason, several authors have explored various bounds concerning the norms and numerical radii of products and sums of Hilbert space operators. This line of research is documented in works such as [21,22], along with their respective references. In a recent study by Sababheh et al. [23], the following result was established: for $ A, B, P \in \mathcal{B}(\mathcal{H}) $ with $ P $ a positive contraction, i.e., $ 0\leq P\leq I $, then the following inequality holds:

    $ ω(BPA)12(12|B|2+|A|2+ω(BA)).
    $
    (1.1)

    We are motivated by the inequality (1.1), which prompts us to extend this result to a broader context involving a positive non-zero operator $ P $ on $ \mathcal{H} $. We also explore norm and numerical radius inequalities for bounded linear operators on $ \mathcal{H} $, focusing on scenarios involving the sum or product of three operators, one of which is a positive non-zero operator $ P $ acting on $ \mathcal{H} $. Our results contribute to extending various inequalities established by other mathematicians in recent years.

    In this section, we will present the proofs of our main results. In order to achieve this, we will make use of the following lemma, which draws its inspiration from the research conducted by Bottazzi and Conde in [24].

    Lemma 2.1. Let $ P\in {\mathcal{B}(\mathcal{H})} $ be a non-zero positive operator. Then for any $ x, y \in \mathcal{H} $ the following inequality holds:

    $ |(1PP12I)x,y|12xy.
    $
    (2.1)

    Proof. By the positivity of $ P $ and [10, Lemma 3.2], we deduce that

    $ \left\|\frac{2}{\|P\|}P-I\right\|\leq 1, $

    or equivalently $ \left\|\frac{1}{\|P\|}P-\frac 12 I\right\|\leq \frac 12. $

    Then, by the Cauchy–Bunyakovsky–Schwarz inequality, we note that

    $ |(1PP12I)x,y|(1PP12I)xy1PP12Ixy12xy. 
    $

    This proves (2.1) as requested.

    Based on Lemma 2.1 and recent results obtained for the Selberg operator in [13], we can derive the following inequalities for operator norms.

    Theorem 2.1. Let $ A, B, P \in \mathcal{B}(\mathcal{H}) $, with $ P $ being a non-zero positive operator. Then, for any $ z_k \in \mathbb{C} $ with $ k = 1, \dots, n $, we determine the following norm inequalities:

    $ nk=1zkB(1PP12I)Ank=1|zk|2AB,
    $
    (2.2)

    and

    $ nk=1zkB(1PP12I)Ank=1|zk|2nAB.
    $
    (2.3)

    Proof. From Lemma 2.1, we see that for $ Ax $ instead of $ x $ and $ B^{\ast }y $ instead of $ y $, that

    $ |nk=1zk(1PP12I)Ax,By|nk=1|zk|2AxBy,
    $

    and

    $ |nk=1zk(1PP12I)Ax,By|nk=1|zk|2nAxBy
    $

    for all $ x, y\in \mathcal{H} $. This is equivalent to

    $ |nk=1zkB(1PP12I)Ax,y|nk=1|zk|2AxBy,
    $

    and

    $ |nk=1zkB(1PP12I)Ax,y|nk=1|zk|2nAxBy
    $
    (2.4)

    for all $ x, y\in \mathcal{H} $. If we take the supremum over $ x, y\in \mathcal{H} $ with $ \left\Vert x\right\Vert = \left\Vert y\right\Vert = 1, $ then we get the norm inequalities (2.2) and (2.3).

    To derive the following power inequalities, we recall McCarthy's inequality [25, Theorem 1.2], which asserts that if $ Q\geq0 $, then the following inequality holds for all $ s\geq 1 $ and for all $ x\in \mathcal{H} $ with $ \left\Vert x\right\Vert = 1 $:

    $ Qx,xsQsx,x.
    $
    (2.5)

    Theorem 2.2. Let $ A, B, P\in {\mathcal{B}(\mathcal{H})} $ with $ P $ being a non-zero positive operator; then for any $ z_{k}\in \mathbb{C} $, we have the numerical radius inequalities

    $ ω(nk=1zkB(1PP12I)A)nk=1|zk|21p|A|rp+1q|B|rq1r,
    $
    (2.6)

    and

    $ ω(nk=1zkB(1PP12I)A)nk=1|zk|2n1p|A|rp+1q|B|rq1r,
    $
    (2.7)

    where $ r\geq 1, $ $ p, q > 1 $ with $ \frac{1}{p}+\frac{1}{q} = 1 $ and $ rp\geq 2, $ $ rq\geq 2. $

    Proof. We will only demonstrate inequality (2.7). The proof of (2.6) follows a similar approach.

    From Young's inequality

    $ ab1pap+1qbq, a, b0, p,q>1 with 1p+1q=1,
    $
    (2.8)

    we infer that

    $ AxrBxr1pAxrp+1qBxrq=1pAx2rp2+1qBx2rq2=1p|A|2x,xrp2+1q|B|2x,xrq2
    $

    for all $ x\in \mathcal{H} $, where $ \left\vert T\right\vert^2 = T^*T $ for any $ T\in {\mathcal{B}(\mathcal{H})} $.

    Since $ rp\geq 2 $ and $ rq\geq 2 $, we can apply McCarthy's inequality (2.5) to obtain:

    $ 1p|A|2x,xrp2+1q|B|2x,xrq21p|A|rpx,x+1q|B|rqx,x=(1p|A|rp+1q|B|rq)x,x
    $

    for $ x\in {\mathcal{H}}, $ $ \left\Vert x\right\Vert = 1. $

    By (2.4)

    $ |nk=1zkB(1PP12I)Ax,x|nk=1|zk|2n(1p|A|rp+1q|B|rq)x,x1r
    $

    for all $ x\in \mathcal{H} $.

    By taking the supremum over $ x\in {\mathcal{H}}, $ $ \left\Vert x\right\Vert = 1, $ we deduce (2.7). This concludes the proof of our result.

    By considering the particular values $ r = 1 $ and $ p = q = 2 $ in the Theorem 2.2, we derive the following inequalities

    $ ω(nk=1zkB(1PP12I)A)nk=1|zk|4|A|2+|B|2,
    $
    (2.9)

    and

    $ ω(nk=1zkB(1PP12I)A)nk=1|zk|2n+1|A|2+|B|2.
    $
    (2.10)

    Corollary 2.1. Let $ A, B, P\in {\mathcal{B}(\mathcal{H})} $ with $ P $ being a positive operator; then for any $ z_{k}\in \mathbb{C} $, we have the following inequality:

    $ ω(nk=1zkBPA)Pnk=1|zk|2(1p|A|rp+1q|B|rq1r+ω(BA)),
    $

    where $ r\geq 1, $ $ p, q > 1 $ with $ \frac{1}{p}+\frac{1}{q} = 1 $ and $ rp\geq 2, $ $ rq\geq 2, $

    Proof. We will only consider the case $ P \neq 0 $, as the other case is trivial. Using the well-known fact that the numerical radius is a norm and (2.6), we obtain that

    $ |ω(nk=1zkB1PPA)ω(nk=1zk2BA)|ω(nk=1zkB(1PP12I)A).nk=1|zk|21p|A|rp+1q|B|rq1r.
    $

    Then, for the triangle inequality for the modulus of a complex number, we conclude that

    $ ω(nk=1zkB1PPA)|ω(nk=1zkB1PPA)ω(nk=1zk2BA)|+ω(nk=1zk2BA)nk=1|zk|21p|A|rp+1q|B|rq1r+ω(nk=1zk2BA)nk=1|zk|2(1p|A|rp+1q|B|rq1r+ω(BA)).
    $

    Multiplying the last inequality by $ \|P\| $, we derive the desired inequality.

    Remark 2.1. Corollary 2.1 extends the inequality (1.1) by considering specific values: $ r = 1 $, $ p = q = 2 $, $ z_1 = 1 $, and $ z_k = 0 $ for any $ k = 2, \cdots, n $. This particular choice of parameters allows us to recover the mentioned inequality.

    Now, we are able to derive new upper bounds for the sum or product of operators. In these bounds, one of the operators is a linear combination of a positive operator and the identity operator, incorporating convex combinations of the operators.

    Theorem 2.3. Let $ A, B, P\in {\mathcal{B}(\mathcal{H})} $ with $ P $ being a positive operator; then for any $ z_{k}\in \mathbb{C} $, we have the numerical radius inequalities

    $ ω(nk=1zkB(1PP12I)A)nk=1|zk|2(1α)|A|2+α|B|212AαB1α,
    $
    (2.11)

    and

    $ ω(nk=1zkB(1PP12I)A)nk=1|zk|2n(1α)|A|2+α|B|212AαB1α
    $
    (2.12)

    for all $ \alpha \in \left[0, 1\right]. $

    Proof. Observe that

    $ Ax2Bx2=|A|2x,x|B|2x,x=|A|2x,x1α|B|2x,xα|A|2x,xα|B|2x,x1α((1α)|A|2x,x+α|B|2x,x)Ax2αBx2(1α)=[(1α)|A|2+α|B|2]x,xAx2αBx2(1α),
    $
    (2.13)

    for all $ x\in \mathcal{H} $.

    By Lemma 2.1, we then have

    $ |nk=1zkB(1PP12I)Ax,x|nk=1|zk|2[(1α)|A|2+α|B|2]x,x12AxαBx1α,
    $
    (2.14)

    and

    $ |nk=1zkB(1PP12I)Ax,x|(nk=1|zk|2n)[(1α)|A|2+α|B|2]x,x12AxαBx1α,
    $
    (2.15)

    for all $ x\in \mathcal{H} $.

    Taking the supremum in (2.14) and (2.15) over $ \left\Vert x\right\Vert = 1, $ we derive (2.11) and (2.12).

    Remark 2.2. We observe that for $ \alpha = \frac{1}{2} $ in (2.11) and (2.12), we derive the following inequalities:

    $ ω(nk=1zkB(1PP12I)A)nk=1|zk|2|A|2+|B|2212A12B12,
    $

    and

    $ ω(nk=1zkB(1PP12I)A)nk=1|zk|2n|A|2+|B|2212A12B12.
    $

    We now turn our attention to the bounds obtained above, and we attempt to make a comparison with the inequalities (2.9) and (2.10), respectively. We show that, in general, they are not directly comparable.

    Consider $ A = (1000)

    $ and $ B = (0001)
    $. Then, it is straightforward to verify that $ \|A\|\|B\| = 1 $ and $ \frac12\left\||A|^2+|B^*|^2\right\| = \frac12\left\|(1001)
    \right\| = \frac 12. $ Thus,

    $ \left\Vert \frac{ \left\vert A\right\vert ^{2}+\left\vert B^{\ast }\right\vert ^{2}}{2} \right\Vert = \frac 12 < \frac{1}{\sqrt{2}} = \left\Vert \frac{ \left\vert A\right\vert ^{2}+\left\vert B^{\ast }\right\vert ^{2}}{2} \right\Vert ^{\frac{1}{2}}\left\Vert A\right\Vert ^{\frac{1}{2}}\left\Vert B\right\Vert ^{\frac{1}{2}}. $

    Again, if we consider $ A = (1001)

    $ and $ B = (1002)
    $, then $ \|A\|\|B\| = 2 $ and $ \frac12\left\||A|^2+|B^*|^2\right\| = \frac12\left\|(1005)
    \right\| = \frac 52 $, and in particular, we obtain:

    $ \left\Vert \frac{ \left\vert A\right\vert ^{2}+\left\vert B^{\ast }\right\vert ^{2}}{2} \right\Vert ^{\frac{1}{2}}\left\Vert A\right\Vert ^{\frac{1}{2}}\left\Vert B\right\Vert ^{\frac{1}{2}} = \sqrt{5} < \frac{5}{2} = \left\Vert \frac{ \left\vert A\right\vert ^{2}+\left\vert B^{\ast }\right\vert ^{2}}{2} \right\Vert. $

    Moreover, the preceding examples demonstrate that, in general, the expressions $ \left\Vert A\right\Vert\left\Vert B\right\Vert $ and $ \left\Vert \frac{ \left\vert A\right\vert ^{2}+\left\vert B^{\ast }\right\vert ^{2}}{2}\right\Vert $ are not directly comparable, even though Young's inequality (2.8) might suggest a potential relationship between them.

    By mimicking the idea used in the proof of Corollary 2.1, we obtain the following result.

    Corollary 2.2. Let $ A, B, P\in {\mathcal{B}(\mathcal{H})} $ with $ P $ being a positive operator; then for any $ z_{k}\in \mathbb{C} $, we obtain the following inequality:

    $ ω(nk=1zkBPA)Pnk=1|zk|2((1α)|A|2+α|B|212AαB1α+ω(BA)),
    $

    where $ \alpha \in \left[0, 1\right]. $

    Next, it would be advantageous to consider various specific cases of interest by selecting appropriate values for $ z_k $. We begin by presenting a generalization of Corollary 2.2.

    Theorem 2.4. Let $ A, B, P \in \mathcal{B}(\mathcal{H}) $ with $ P $ being a positive operator. Then, for any $ z_k \in \mathbb{C} $ with $ \sum_{k = 1}^{n} \left\vert z_k \right\vert \leq 1 $ and $ r \geq 1 $, we obtain the following numerical radius inequality for $ \alpha \in [0, 1] $:

    $ ω(nk=1zkBPA)P21r[ωr(BA)+(1α)|A|2+α|B|2r2ArαBr(1α)]1r,
    $
    (2.16)

    and

    $ ω(nk=1zkBPA)P21r[ωr(BA)+(1α)|A|2+α|B|2r2α|A|2+(1α)|B|2r2]1r.
    $
    (2.17)

    Proof. Let us note that if $ P = 0 $, the inequality reduces trivially to an equality. Therefore, we shall assume that $ P\neq 0 $. From Lemma 2.1, we conclude the following inequality:

    $ |(nk=1zkB1PPA)x,y||BAx,y|+AxBy2
    $
    (2.18)

    for all $ x, y\in \mathcal{H} $.

    If we take $ y = x $ in (2.18), then we obtain

    $ |(nk=1zkB1PPA)x,x||BAx,x|+AxBx2,
    $
    (2.19)

    for all $ x\in {\mathcal{H}}. $

    For $ r\geq 1 $ and (2.13), then we obtain

    $ AxrBxr[(1α)|A|2+α|B|2]x,xr2AxrαBxr(1α),
    $

    for all $ x\in \mathcal{H} $.

    If we take the power $ r\geq 1 $ in (2.19) and use the convexity of the function $ g(t) = t^r $ with $ t\in [0, \infty) $, then we obtain:

    $ |(nk=1zkB1PPA)x,x|r(|BAx,x|+AxBx2)r|BAx,x|r+AxrBxr2.
    $
    (2.20)

    From (2.20), we then have

    $ |(nk=1zkB1PPA)x,x|r|BAx,x|r+[(1α)|A|2+α|B|2]x,xr2AxrαBxr(1α)2
    $

    for all $ x\in \mathcal{H} $. Taking the supremum over $ \left\Vert x\right\Vert = 1, $ we derive (2.16).

    In a similar way, we obtain

    $ |(nk=1zkB1PPA)x,x|r|BAx,x|r+[(1α)|A|2+α|B|2]x,xr2[α|A|2+(1α)|B|2]x,xr22
    $

    for all $ x\in \mathcal{H} $, which proves (2.17). This marks the completion of our result's proof.

    Remark 2.3. We note that inequality (2.16) can be deduced from Corollary 2.2, repeating the proof idea used in Theorem 2.5.

    We observe that for $ \alpha = \frac{1}{2} $, in Theorem 2.4, we obtain:

    $ ω(nk=1zkBPA)P21r[ωr(BA)+|A|2+|B|22r2Ar2Br2]1r
    $

    for $ r\geq 1. $

    In the case $ r = 1 $, we obtain

    $ ω(nk=1zkBPA)P2[ω(BA)+|A|2+|B|2212A12B12],
    $

    while for $ r = 2, $

    $ ω(nk=1zkBPA)P22ω2(BA)+|A|2+|B|22AB.
    $

    We also conclude that

    Corollary 2.3. Let $ A, B, P\in {\mathcal{B}(\mathcal{H})} $ with $ P $ being a positive operator, then for any $ z_{k}\in \mathbb{C} $ with $ \sum_{k = 1}^{n}\left\vert z_{k}\right\vert \leq1 $, we infer the norm inequality

    $ nk=1zkBPAP2(BA+AB),
    $

    and the numerical radius inequality

    $ ω(nk=1zkBPA)P2(ω(BA)+12|A|2+|B|2).
    $
    (2.21)

    Proof. It is sufficient to consider the case where $ P \neq 0 $. We only prove the inequality (2.21). The other one follows similarly.

    By (2.9), we obtain:

    $ ω(nk=1zkB1PPA)ω(nk=1zkB(1PP12I)A)+ω(12nk=1zkBA)14|A|2+|B|2+12ω(BA),
    $
    (2.22)

    and the inequality (2.21) is proved.

    Corollary 2.4. With the assumptions of Corollary 2.3, we establish the following norm inequality:

    $ nk=1zkAPAP2(A2+A2),
    $

    and the numerical radius inequality

    $ ω(nk=1zkAPA)P2(ω(A2)+12|A|2+|A|2).
    $

    We also have:

    Corollary 2.5. Let $ A, B, P\in {\mathcal{B}(\mathcal{H})} $ with $ P $ being a positive operator, then for any $ z_{k}\in \mathbb{C} $ with $ \sum_{k = 1}^{n}\left\vert z_{k}\right\vert \leq 1 $, we have the numerical radius inequality

    $ ω(nk=1zkBPA)P21r[ωr(BA)+1p|A|rp+1q|B|rq]1r,
    $
    (2.23)

    for any $ r\geq 1, $ $ p, q > 1 $ such that $ \frac{1}{p}+\frac{1}{q} = 1 $ and $ rp\geq 2, $ $ rq\geq 2. $

    Proof. Utilizing Corollary 2.1 and the fact that $ f(t) = t^{\frac{1}{r}} $ is concave on $ [0, \infty) $, we obtain:

    $ ω(nk=1zkB1PPA)121p|A|rp+1q|B|rq1r+12[ωr(BA)]1r[121p|A|rp+1q|B|rq+12ωr(BA)]1r=121r[ωr(BA)+1p|A|rp+1q|B|rq]1r.
    $

    This concludes the proof of our result.

    Let $ A, B, P \in \mathcal{B}(H) $ with $ P $ being a non-zero, positive operator. Then, for any $ z_{k} \in \mathbb{C} $ with $ \sum_{k = 1}^{n} \left\vert z_{k} \right\vert \leq 1 $, setting $ r = 1 $ and $ p = q = 2 $ in (2.23), we obtain

    $ ω(nk=1zkBPA)P2[ω(BA)+|A|2+|B|22],
    $

    while for $ r = 2 $ and $ p = q = 2 $, we obtain:

    $ ω(nk=1zkBPA)P22ω2(BA)+|A|4+|B|42.
    $

    Finally, for $ r = 2 $ and $ p, $ $ q > 1 $ with $ \frac{1}{p}+\frac{1}{q} = 1 $, we infer

    $ ω(nk=1zkBPA)P22ω2(BA)+1p|A|2p+1q|B|2q.
    $

    Corollary 2.6. With the assumptions of Corollary 2.5, we deduce that for $ r\geq 1 $,

    $ ω(nk=1zkAPA)P21r[ωr(A2)+|A|2r+|A|2r2]1r.
    $

    If $ r\geq 1, $ then for $ p, q > 1 $ with $ \frac{1}{p}+\frac{1}{q} = 1 $ and $ rp\geq 2, $ $ rq\geq 2, $

    $ ω(nk=1zkAPA)P21r[ωr(A2)+1p|A|rp+1q|A|rq]1r.
    $

    In this paper, we have explored new inequalities for the norms and numerical radii of bounded linear operators on complex Hilbert spaces, specifically involving one positive operator. Our results contribute to extending existing inequalities in the literature, offering a deeper understanding of the relationships between these operators. This work establishes a foundation for further research and serves as a basis for future studies in this area. We hope that our findings will inspire further exploration and development of inequalities involving operators in complex Hilbert spaces, as well as their potential applications in various mathematical fields.

    Najla Altwaijry: Conceptualization, Visualization, Funding, Resources, Writing–review & editing, Formal analysis, Project administration, Validation, Investigation; Cristian Conde: Conceptualization, Visualization, Funding, Writing–review & editing, Formal analysis, Project administration, Validation, Investigation; Silvestru Sever Dragomir: Conceptualization, Visualization, Funding, Writing–review & editing, Formal analysis, Project administration, Validation, Investigation; Kais Feki: Conceptualization, Visualization, Funding, Writing–review & editing, Formal analysis, Project administration, Validation, Investigation. All authors declare that they have contributed equally to this paper. All authors have read and approved the final version of the manuscript for publication.

    The authors declare that they have not used Artificial Intelligence (AI) tools in the creation of this article.

    The authors thank the reviewers for their helpful comments and suggestions that improved this paper. The first author is grateful for the support from the Distinguished Scientist Fellowship Program under the Researchers Supporting Project number (RSP2025R187), King Saud University, Riyadh, Saudi Arabia.

    The authors declare that they have no competing interests.

    [1] Pinotsis D, Friston K. (2014) Gamma Oscillations and Neural Field DCMs can reveal cortical excitability and microstructure. AIMS Neurosci 1: 18-38.
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