Citation: Daniel Borchert, Diego A. Suarez-Zuluaga, Yvonne E. Thomassen, Christoph Herwig. Risk assessment and integrated process modeling–an improved QbD approach for the development of the bioprocess control strategy[J]. AIMS Bioengineering, 2020, 7(4): 254-271. doi: 10.3934/bioeng.2020022
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Fractional differential equations frequently appear in the mathematical modelling of many physical and engineering problems. One can find the potential application of fractional-order operators in malaria and HIV/AIDS model [1], bioengineering [2], ecology [3], viscoelasticity [4], fractional dynamical systems [5,6] and so forth. Influenced by the practical applications of fractional calculus tools, many researchers turned to the further development of this branch of mathematical analysis. For the theoretical background of fractional derivatives and integrals, we refer the reader to the texts [7], while a detailed account of fractional differential equations can be found in [8,9,10]. In a recent monograph [11], the authors presented several results on initial and boundary value problems of Hadamard-type fractional differential equations and inclusions.
Fractional-order differential equations equipped with a variety of boundary conditions have been studied in the last few decades. The literature on the topic includes the existence and uniqueness results related to classical, periodic/anti-periodic, nonlocal, multi-point, and integral boundary conditions; for instance, see [12,13,14,15,16,17,18,19,20,21] and the references therein.
Recently, in [22], Ahmad et al. considered a boundary value problem involving sequential fractional derivatives given by
(cDq+μcDq−1)x(t)=f(t,x(t),cDκx(t)),μ>0,0<κ<1,1<q≤2,t∈(0,1), | (1.1) |
supplemented with nonlocal integro-multipoint boundary conditions:
{ρ1x(0)+ρ2x(1)=m−2∑i=1αix(σi)+p−2∑j=1rj∫ηjξjx(s)ds,ρ3x′(0)+ρ4x′(1)=m−2∑i=1δix′(σi)+p−2∑j=1γj∫ηjξjx′(s)ds,0<σ1<σ2<…<σm−2<…<ξ1<η1<ξ2<η2<…<ξp−2<ηp−2<1, | (1.2) |
where cDq,cDκ denote the Caputo fractional derivative of order q and κ respectively (for the definition of Caputo fractional derivative, see Definition 2.2), f is a given continuous function, ρp(p=1,2,3,4) are real constants and αi,δi(i=1,2,…,m−2),rj,γj(j=1,2,…,p−2), are positive real constants. Existence and uniqueness results for the problem (1.2) were proved by using the fixed point theorems due to Banach and Krasnoselskii.
In [23], Ahmad et al. studied the existence and uniqueness of solutions for a new class of boundary value problems for multi-term fractional differential equations supplemented with four-point boundary conditions
{λCDαx(t)+CDβx(t)=f(t,x(t)),t∈J:=(0,T),x′(ξ)=νCDγx(η),x(T)=μIδx(θ),0<ξ,η,θ<T, | (1.3) |
where CDχ is Caputo fractional derivatives of order χ∈{α,β,γ}, λ,ν,μ∈R, 1<α≤2, 1<β<α, 0≤γ<α−β<1, δ>0, Iδ is the Riemann-Liouville fractional integral of order δ, and f:[0,T]×R→R is a continuous function.
In [24], the authors studied the existence of solutions for a nonlinear Liouville-Caputo-type fractional differential equation on an arbitrary domain:
cDqax(t)=f(t,x(t)),3<q≤4, t∈(a,b), | (1.4) |
supplemented with non-conjugate Riemann-Stieltjes integro-multipoint boundary conditions of the form:
x(a)=n−2∑i=1αix(ηi)+∫bax(s)dA(s), x′(a)=0, x(b)=0, x′(b)=0, | (1.5) |
where cDqa denotes the Caputo fractional derivative of order q, a<η1<η2<⋯<ηn−2<b, f:[a,b]×R⟶R is a given continuous function, A is a function of bounded variation, and αi∈R, i=1,2,⋯,n−2.
In the present paper, we investigate the existence of solutions for an abstract nonlinear multi-term Caputo fractional differential equation with nonlinearity depending on the unknown function together with its lower-order Caputo fractional derivatives given by
μcDqax(t)+ξcDrax(t)=f(t,x(t),cDpax(t),cDp+1ax(t)),3<q≤4,0<p,r≤1,t∈(a,b), | (1.6) |
supplemented with Riemann-Stieltjes integro-multipoint boundary conditions
x(a)=n−2∑i=1αix(ηi)+∫bax(s)dA(s), x′(a)=0, x(b)=0, x′(b)=0, | (1.7) |
where cDθa denotes the Caputo fractional differential operator of order θ with θ=q,r,p, a<η1<η2<⋯<ηn−2<b, f:[a,b]×R3⟶R is a given continuous function, A is a function of bounded variation, and μ(μ≠0),ξ,αi∈R, i=1,2,⋯,n−2.
The rest of the paper is arranged as follows. In section 2, we prove a basic result related to the linear variant of the problem (1.6)-(1.7), which plays a key role in the forthcoming analysis. We also recall some basic concepts of fractional calculus. The existence result is presented in Section 3, while the uniqueness result in Section 4. Examples illustrating the obtained results are also presented. The paper concludes with Section 5 with some interesting observations.
Before presenting an auxiliary lemma, we recall some basic definitions of fractional calculus [8].
Definition 2.1. The Riemann-Liouville fractional integral of order σ with lower limit a for function ϕ is defined as
Iσaϕ(t)=1Γ(σ)∫ta(t−s)σ−1ϕ(s)ds, σ>a, |
provided the integral exists.
Definition 2.2. For (n-1)-times absolutely continuous function ϕ:(a,∞)⟶R, the Caputo derivative of fractional order σ is defined as
cDσaϕ(t)=1Γ(n−σ)∫ta(t−s)n−σ−1ϕ(n)(s)ds, n−1<σ≤n, n=[σ]+1, |
where [σ] denotes the integer part of the real number σ.
In passing we remark that we write cDσa and Iσa as cDσ and Iσ respectively when a=0.
Lemma 2.1. [8] For n−1<q<n, the general solution of the fractional differential equation cDqax(t)=0,t∈(a,b), is
x(t)=c0+c1(t−a)+c2(t−a)2+…+cn−1(t−a)n−1, |
where ci∈R,i=0,1,…,n−1. Furthermore,
IqacDqax(t)=x(t)+n−1∑i=0ci(t−a)i. |
Lemma 2.2. Let ψ∈C([a,b]). Then the unique solution of the linear multi-term fractional differential equation
μcDqax(t)+ξcDrax(t)=ψ(t), 3<q≤4,0<r<1, t∈(a,b), | (2.1) |
subject to the boundary conditions (1.7) is given by
x(t)=−ξμIq−rax(t)+1μIqaψ(t)+1μ[ϕ1(t)(ξIq−rax(b)−Iqaψ(b))+ϕ2(t)(ξIq−r−1ax(b)−Iq−1aψ(b))+ϕ3(t)(ξn−2∑i=1αiIq−rax(ηi)−n−2∑i=1αiIqaψ(ηi)+ξ∫baIq−rax(s)dA(s)−∫baIqaψ(s)dA(s))], | (2.2) |
where
ϕi(t)=(t−a)3σi+(t−a)2δi+λi,i=1,2,3, | (2.3) |
λ1=1−(b−a)3σ1−(b−a)2δ1,λj=−(b−a)3σj−(b−a)2δj,j=2,3, | (2.4) |
δ1=−3(b−a)σ12,δ2=1−3(b−a)2σ22(b−a),δ3=−3(b−a)σ32, | (2.5) |
σ1=−2A1γ1,σ2=2γ2γ1,σ3=2γ1, | (2.6) |
γ1=(b−a)3A1−3(b−a)A2+2A3,γ2=(b−a)2A1−A22(b−a), | (2.7) |
A1=n−2∑i=1αi+∫badA(s)−1,A2=n−2∑i=1αi(ηi−a)2+∫ba(s−a)2dA(s), | (2.8) |
A3=n−2∑i=1αi(ηi−a)3+∫ba(s−a)3dA(s), | (2.9) |
and it is assumed that γ1≠0.
Proof. Applying the integral operator Iqa on both sides of fractional differential equation (2.1) and using Lemma 2.1, we get
x(t)=−ξμIq−rax(t)+1μIqaψ(t)+c0+c1(t−a)+c2(t−a)2+c3(t−a)3, | (2.10) |
x′(t)=−ξμIq−r−1ax(t)+1μIq−1aψ(s)+c1+2c2(t−a)+3c3(t−a)2, | (2.11) |
where ci∈R,i=0,1,2,3 are unknown arbitrary constants. Using the boundary conditions (1.7) in (2.10) and (2.11), we obtain c1=0 and
c0+(b−a)2c2+(b−a)3c3=J1, | (2.12) |
2(b−a)c2+3(b−a)2c3=J2, | (2.13) |
A1c0+A2c2+A3c3=J3, | (2.14) |
where Ai(i=1,2,3) are given by (2.8), (2.9) and
J1=1μ(ξIq−rax(b)−Iqaψ(b)),J2=1μ(ξIq−r−1ax(b)−Iq−1aψ(b)),J3=1μ(ξn−2∑i=1αiIq−rax(ηi)−n−2∑i=1αiIqaψ(ηi)+ξ∫baIq−rax(s)dA(s)−∫baIqaψ(s)dA(s)). | (2.15) |
Eliminating c0 from (2.12) and (2.14), we get
(A2−(b−a)2A1)c2+(A3−(b−a)3A1)c3=J3−A1J1. | (2.16) |
Solving (2.13) and (2.16), we find that
c2=δ1J1+δ2J2+δ3J3, | (2.17) |
c3=σ1J1+σ2J2+σ3J3, | (2.18) |
where δi and σi(i=1,2,3) are defined by (2.5) and (2.6) respectively. Using (2.17) and (2.18) in (2.12), we get
c0=λ1J1+λ2J2+λ3J3, | (2.19) |
where λi(i=1,2,3) are given by (2.4). Inserting the values of c0,c1,c2 and c3 in (2.10) together with notations (2.3), we obtain the solution (2.2). The converse of the lemma follows by direct computation.
Now we recall some preliminary concepts from functional analysis related to our work.
Definition 2.3. Let Ω be a bounded set in metric space (Y,d). The Kuratowski measure of noncompactness, α(Ω), is defined as
inf{ε:Ωcovered by a finitely many sets such that the diameter of each set≤ε}. |
Definition 2.4. [25] Let J:D(J)⊆Y⟶Y be a bounded and continuous operator on Banach space Y. Then J is called a condensing map if α(J(A))<α(A) for all bounded sets A⊂D(J), where α denotes the Kuratowski measure of noncompactness.
Lemma 2.3. [26] The map F+G is a k-set contraction with 0≤k<1, and thus also condensing, if the following conditions hold:
(i) F,G:D⊆Y⟶Y are operators on the Banach space Y;
(ii) F is k-contractive, that is, for all x,y∈D and a fixed k∈[0,1), ‖Fx−Fy‖≤k‖x−y‖;
(iii) G is compact.
Lemma 2.4. (Sadovskii Theorem [27]) Let A be a convex, bounded and closed subset of a Banach space Y and J:A⟶A be a condensing map. Then J has a fixed point.
For 0<p≤1, let A={x:x,cDpax(t),cDp+1ax(t)∈C([a,b],R)} denote the Banach space of all continuous functions from [a,b]⟶R endowed with the norm defined by
‖x‖∗=supt∈[a,b]{|x(t)|+|cDpax(t)|+|cDp+1ax(t)|}. | (3.1) |
In view of Lemma 2.2, we transform the problem (1.6)-(1.7) into an equivalent fixed point problem as
x=Fx, | (3.2) |
where F:A⟶A is defined by
(Fx)(t)=−ξμIq−rax(t)+1μIqaˆf(x(t))+ϕ1(t)μ[ξ∫ba(b−s)q−r−1Γ(q−r)x(s)ds−∫ba(b−s)q−1Γ(q)ˆf(x(s))ds]+ϕ2(t)μ[ξ∫ba(b−s)q−r−2Γ(q−r−1)x(s)ds−∫ba(b−s)q−2Γ(q−1)ˆf(x(s))ds]+ϕ3(t)μ[ξn−2∑i=1αi∫ηia(ηi−s)q−r−1Γ(q−r)x(s)ds−n−2∑i=1αi∫ηia(ηi−s)q−1Γ(q)ˆf(x(s))ds+ξ∫ba(∫sa(s−u)q−r−1Γ(q−r)x(u)du)dA(s)−∫ba(∫sa(s−u)q−1Γ(q)ˆf(x(u))du)dA(s)], | (3.3) |
where ϕi(t),i=1,2,3 are defined by (2.3) and ˆf(x(t))=f(t,x(t),cDpax(t),cDp+1ax(t)).
From (3.3), we have
(cDpaFx)(t)=−ξμIq−p−rax(t)+1μIq−paˆf(x(t))+ω1(t)μ[ξ∫ba(b−s)q−r−1Γ(q−r)x(s)ds−∫ba(b−s)q−1Γ(q)ˆf(x(s))ds]+ω2(t)μ[ξ∫ba(b−s)q−r−2Γ(q−r−1)x(s)ds−∫ba(b−s)q−2Γ(q−1)ˆf(x(s))ds]+ω3(t)μ[ξn−2∑i=1αi∫ηia(ηi−s)q−r−1Γ(q−r)x(s)ds−n−2∑i=1αi∫ηia(ηi−s)q−1Γ(q)ˆf(x(s))ds+ξ∫ba(∫sa(s−u)q−r−1Γ(q−r)x(u)du)dA(s)−∫ba(∫sa(s−u)q−1Γ(q)ˆf(x(u))du)dA(s)], | (3.4) |
where
ω1(t)=cDpaϕ1(t)=cDpa((t−a)3σ1+(t−a)2δ1+λ1)=6σ1(t−a)3−pΓ(4−p)+2δ1(t−a)2−pΓ(3−p),ω2(t)=cDpaϕ2(t)=cDpa((t−a)3σ2+(t−a)2δ2+λ2)=6σ2(t−a)3−pΓ(4−p)+2δ2(t−a)2−pΓ(3−p),ω3(t)=cDpaϕ3(t)=cDpa((t−a)3σ3+(t−a)2δ3+λ3)=6σ3(t−a)3−pΓ(4−p)+2δ3(t−a)2−pΓ(3−p), | (3.5) |
and
(cDp+1Fx)(t)=−ξμIq−p−r−1ax(t)+1μIq−p−1aˆf(x(t))+ν1(t)μ[ξ∫ba(b−s)q−r−1Γ(q−r)x(s)ds−∫ba(b−s)q−1Γ(q)ˆf(x(s))ds]+ν2(t)μ[ξ∫ba(b−s)q−r−2Γ(q−r−1)x(s)ds−∫ba(b−s)q−2Γ(q−1)ˆf(x(s))ds]+ν3(t)μ[ξn−2∑i=1αi∫ηia(ηi−s)q−r−1Γ(q−r)x(s)ds−n−2∑i=1αi∫ηia(ηi−s)q−1Γ(q)ˆf(x(s))ds+ξ∫ba(∫sa(s−u)q−r−1Γ(q−r)x(u)du)dA(s)−∫ba(∫sa(s−u)q−1Γ(q)ˆf(x(u))du)dA(s)], | (3.6) |
where
ν1(t)=cDp+1aϕ1(t)=cDp+1a((t−a)3σ1+(t−a)2δ1+λ1)=6σ1(t−a)2−pΓ(3−p)+2δ1(t−a)1−pΓ(2−p),ν2(t)=cDp+1aϕ2(t)=cDp+1a((t−a)3σ2+(t−a)2δ2+λ2)=6σ2(t−a)2−pΓ(3−p)+2δ2(t−a)1−pΓ(2−p),ν3(t)=cDp+1aϕ3(t)=cDp+1a((t−a)3σ3+(t−a)2δ3+λ3)=6σ3(t−a)2−pΓ(3−p)+2δ3(t−a)1−pΓ(2−p). | (3.7) |
For the sake of computational convenience, we introduce
Λ1=|ξ||μ|[(b−a)q−rΓ(q−r+1)+ˉϕ1(b−a)q−rΓ(q−r+1)+ˉϕ2(b−a)q−r−1Γ(q−r)+ˉϕ3(n−2∑i=1|αi|(ηi−a)q−rΓ(q−r+1)+∫ba(s−a)q−rΓ(q−r+1)dA(s))],ˉΛ1=1|μ|[(b−a)qΓ(q+1)+ˉϕ1(b−a)qΓ(q+1)+ˉϕ2(b−a)q−1Γ(q)+ˉϕ3(n−2∑i=1|αi|(ηi−a)qΓ(q+1)+∫ba(s−a)qΓ(q+1)dA(s))], | (3.8) |
Λ2=|ξ||μ|[(b−a)q−p−rΓ(q−p−r+1)+ˉω1(b−a)q−rΓ(q−r+1)+ˉω2(b−a)q−r−1Γ(q−r)+ˉω3(n−2∑i=1|αi|(ηi−a)q−rΓ(q−r+1)+∫ba(s−a)q−rΓ(q−r+1)dA(s))],ˉΛ2=1|μ|[(b−a)q−pΓ(q−p+1)+ˉω1(b−a)qΓ(q+1)+ˉω2(b−a)q−1Γ(q)+ˉω3(n−2∑i=1|αi|(ηi−a)qΓ(q+1)+∫ba(s−a)qΓ(q+1)dA(s))], | (3.9) |
Λ3=|ξ||μ|[(b−a)q−p−r−1Γ(q−p−r)+ˉν1(b−a)q−rΓ(q−r+1)+ˉν2(b−a)q−r−1Γ(q−r)+ˉν3(n−2∑i=1|αi|(ηi−a)q−rΓ(q−r+1)+∫ba(s−a)q−rΓ(q−r+1)dA(s))],ˉΛ3=1|μ|[(b−a)q−p−1Γ(q−p)+ˉν1(b−a)qΓ(q+1)+ˉν2(b−a)q−1Γ(q)+ˉν3(n−2∑i=1|αi|(ηi−a)qΓ(q+1)+∫ba(s−a)qΓ(q+1)dA(s))], | (3.10) |
where ˉϕi=supt∈[a,b]|ϕi(t)|,ˉωi=supt∈[a,b]|ωi(t)|,ˉνi=supt∈[a,b]|νi(t)|,i=1,2,3,
Δ=max{Λ1,Λ2,Λ3}, | (3.11) |
ˉΔ=max{ˉΛ1,ˉΛ2,ˉΛ3}. | (3.12) |
In the following result, we prove the existence of solutions for the problem (1.6)-(1.7) by applying Lemma 2.4.
Theorem 3.1. Let f:[a,b]×R3⟶R be a continuous function. Assume that:
(O1) there exists a function ρ∈C([a,b],R+) such that
|f(t,x1,x2,x3)|≤ρ(t),fort∈[a,b],andeachxi∈R,i=1,2,3; |
(O2) κ<1, where κ=3Δ and Δ is defined by (3.11).
Then problem (1.6)-(1.7) has at least one solution on [a,b].
Proof. Consider a closed bounded and convex ball Bτ={x∈A:‖x‖∗≤τ}⊆A, where τ is a fixed constant. Let us define F1,F2:Bτ⟶Bτ by
(F1x)(t)=−ξμIq−rax(t)+ξϕ1(t)μ∫ba(b−s)q−r−1Γ(q−r)x(s)ds+ξϕ2(t)μ∫ba(b−s)q−r−2Γ(q−r−1)x(s)ds+ξϕ3(t)μ[n−2∑i=1αi∫ηia(ηi−s)q−r−1Γ(q−r)x(s)ds+∫ba(∫sa(s−u)q−r−1Γ(q−r)x(u)du)dA(s)],t∈[a,b](F2x)(t)=1μIqaˆf(x(t))−ϕ1(t)μ∫ba(b−s)q−1Γ(q)ˆf(x(s))ds−ϕ2(t)μ∫ba(b−s)q−2Γ(q−1)ˆf(x(s))ds−ϕ3(t)μ[n−2∑i=1αi∫ηia(ηi−s)q−1Γ(q)ˆf(x(s))ds+∫ba(∫sa(s−u)q−1Γ(q)ˆf(x(u))du)dA(s)],t∈[a,b]. |
Observe that,
(Fx)(t)=(F1x)(t)+(F2x)(t),t∈[a,b]. |
Now we show that F1 and F2 satisfy all the conditions of Lemma 2.4. The proof will be given in several steps.
Step 1. FBτ⊂Bτ.
Let us choose τ≥3‖ρ‖ˉΔ1−κ, where κ is defined in (O2) and ˉΔ is given by (3.12). For x∈Bτ, we have
|Fx(t)|≤‖x‖∗|ξ||μ|[(b−a)q−rΓ(q−r+1)+ˉϕ1(b−a)q−rΓ(q−r+1)+ˉϕ2(b−a)q−r−1Γ(q−r)+ˉϕ3(n−2∑i=1|αi|(ηi−a)q−rΓ(q−r+1)+∫ba(s−a)q−rΓ(q−r+1)dA(s))]+‖ρ‖|μ|[(b−a)qΓ(q+1)+ˉϕ1(b−a)qΓ(q+1)+ˉϕ2(b−a)q−1Γ(q)+ˉϕ3(n−2∑i=1|αi|(ηi−a)qΓ(q+1)+∫ba(s−a)qΓ(q+1)dA(s))]≤τΛ1+‖ρ‖ˉΛ1≤τ(κ/3)+‖ρ‖ˉΔ, |
Similarly, it can be shown that
|cDpaFx(t)|≤τΛ2+‖ρ‖ˉΛ2≤τ(κ/3)+‖ρ‖ˉΔ,|cDp+1aFx(t)|≤τΛ3+‖ρ‖ˉΛ3≤τ(κ/3)+‖ρ‖ˉΔ. |
Hence
‖Fx||∗=supx∈[a,b]{|Fx(t)|+|cDpaFx(t)|+|cDp+1aFx(t)|}≤τκ+3‖ρ‖ˉΔ<τ. |
Thus we get FBτ⊂Bτ.
Step 2. F1 is a κ-contractive.
For x,y∈Bτ and using the condition O2, we have
|(F1x)(t)−(F1y)(t)|≤|ξ||μ|Iq−ra|x(t)−y(t)|+|ξ||ϕ1(t)||μ|Iq−ra|x(b)−y(b)|+|ξ||ϕ2(t)||μ|Iq−r−1a|x(b)−y(b)|+|ξ||ϕ3(t)||μ|(n−2∑i=1|αi|Iq−ra|x(ηi)−y(ηi)|+∫baIq−ra|x(s)−y(s)|dA(s))≤|ξ||μ|[(b−a)q−rΓ(q−r+1)+ˉϕ1(b−a)q−rΓ(q−r+1)+ˉϕ2(b−a)q−r−1Γ(q−r)+ˉϕ3(n−2∑i=1|αi|(ηi−a)q−rΓ(q−r+1)+∫ba(s−a)q−rΓ(q−r+1)dA(s))]‖x−y‖=Λ1‖x−y‖≤(κ/3)‖x−y‖. |
Similarly, we can obtain
|cDpaF1x(t)−cDpaF1y(t)|≤Λ2‖x−y‖≤(κ/3)‖x−y‖, |
|cDp+1aF1x(t)−cDp+1aF1y(t)|≤Λ3‖x−y‖≤(κ/3)‖x−y‖. |
Hence
‖F1x−F1y‖∗≤κ||x−y‖, |
which proves that F1 is κ-contractive.
Step 3. F2 is compact.
Continuity of f implies that the operator F2 is continuous. Also, F2 is uniformly bounded on Bτ as
|F2x(t)|≤‖ρ‖ˉΛ1,|cDpaF2x(t)|≤‖ρ‖ˉΛ2, and|cDp+1aF2x(t)|≤‖ρ‖ˉΛ3, |
which imply that ‖F2x‖∗≤3‖ρ‖ˉΔ.
Let t1,t2∈[a,b] with t1<t2 and x∈Bτ. We have
|F2x(t2)−F2x(t1)|≤1|μ|Γ(q)[∫t1a|(t2−s)q−1−(t1−s)q−1||ρ(s)|ds+∫t2t1|(t2−s)q−1||ρ(s)|ds]+|ϕ1(t2)−ϕ1(t1)||μ|∫ba(b−s)q−1Γ(q)|ρ(s)|ds+|ϕ2(t2)−ϕ2(t1)||μ|∫ba(b−s)q−2Γ(q−1)|ρ(s)|ds+|ϕ3(t2)−ϕ3(t1)||μ|[n−2∑i=1|αi|∫ηia(ηi−s)q−1Γ(q)|ρ(s)|ds+∫ba(∫sa(s−u)q−1Γ(q)|ρ(u)|du)dA(s)]≤‖ρ‖|μ|Γ(q+1)[|(t2−a)q−(t1−a)q|+2(t2−t1)q]+‖ρ‖(b−a)q|ϕ1(t2)−ϕ1(t1)||μ|Γ(q+1)+‖ρ‖(b−a)q−1|ϕ2(t2)−ϕ2(t1)||μ|Γ(q)+‖ρ‖|ϕ3(t2)−ϕ3(t1)||μ|Γ(q+1)[n−2∑i=1|αi|(ηi−a)q+∫ba(s−a)qdA(s)], | (3.13) |
|cDpaF2x(t2)−cDpaF2x(t1)|≤‖ρ‖|μ|Γ(q−p+1)[|(t2−a)q−p−(t1−a)q−p|+2(t2−t1)q−p]+‖ρ‖(b−a)q|ω1(t2)−ω1(t1)||μ|Γ(q+1)+‖ρ‖(b−a)q−1|ω2(t2)−ω2(t1)||μ|Γ(q)+‖ρ‖|ω3(t2)−ω3(t1)||μ|Γ(q+1)[n−2∑i=1|αi|(ηi−a)q+∫ba(s−a)qdA(s)], | (3.14) |
and
|cDp+1aF2x(t2)−cDp+1aF2x(t1)|≤‖ρ‖|μ|Γ(q−p)[|(t2−a)q−p−1−(t1−a)q−p−1|+2(t2−t1)q−p−1]+‖ρ‖(b−a)q|ν1(t2)−ν1(t1)||μ|Γ(q+1)+‖ρ‖(b−a)q−1|ν2(t2)−ν2(t1)||μ|Γ(q)+‖ρ‖|ν3(t2)−ν3(t1)||μ|Γ(q+1)[n−2∑i=1|αi|(ηi−a)q+∫ba(s−a)qdA(s)]. | (3.15) |
The right hand sides of the inequalities (3.13)-(3.15) tend to zero as t2−t1⟶0 independent of x. Thus, F2 is equicontinuous on Bτ. Therefore, by Arzelá-Ascoli theorem, F2 is a relatively compact on Bτ.
Step 4. F is condensing. Since F1 is continuous, κ-contractive and F2 is compact, therefore, by Lemma 2.3, the operator F:Bτ⟶Bτ, with F=F1+F2 is a condensing map on Bτ.
Hence, by Lemma 2.4, the operator F has a fixed point. Therefore, the problem (1.6)-(1.7) has at least one solution on [a,b].
Example 3.1. Consider the fractional boundary value problem.
{45cD359x(t)+9cD18x(t)=f(t,x(t),cD14x(t),cD54x(t)),t∈(0,1),x(0)=4∑i=1αix(ηi)+∫10x(s)dA(s),x′(0)=0,x(1)=0,x′(1)=0, | (3.16) |
where q=359,r=18,p=14, a=0,b=1, μ=45, ξ=9,α1=−1300, α2=−122, α3=1240, α4=239, η1=117, η2=217, η3=317, η4=417, and
f(t,x(t),cD14x(t),cD54x(t))=1√e2t+80(|x(t)|1+|x(t)|+sin2(cD14x(t))+cos(cD54x(t))). |
Let us take A(s)=s22. Using the given data, we have that A1≃−0.493339, A2≃0.252328, A3≃0.200616, γ1≃−0.849088, γ2≃−0.372834, σ1≃−1.16204, σ2≃0.878198, σ3≃−2.35546, δ1≃1.74306, δ2≃−0.817295, δ3≃3.53319, λ1≃0.41898, λ2≃−0.060903, λ3≃−1.17773, ˉϕ1≃1.00000, ˉϕ2≃0.113338, ˉϕ3≃1.17773, ˉω1≃0.591136, ˉω2≃0.175009, ˉω3≃1.19823, ˉν1≃0.541872, ˉν2≃1.49758, ˉν3≃1.09837, Λ1≃0.031094, Λ2≃0.034096, Λ3≃0.134535, ˉΛ1≃0.000700, ˉΛ2≃0.002538, ˉΛ3≃0.012289.
Also, the conditions O1 and O2 are satisfied as we have,
|f(t,x(t),cD14x(t),cD54x(t))|≤3√e2t+80=ρ(t), |
and κ≈0.403605<1, where κ is defined in (O2). Hence, the conditions of Theorem (3.1) hold. Therefore, from conclusion of Theorem 3.1 the problem (3.16) has at least one solution on [0,1].
Next, we prove the uniqueness of solutions for the problem (1.6)-(1.7) via Banach fixed point theorem.
Theorem 4.1. Assume that f:[a,b]×R3⟶R is a continuous function such that,
|f(t,x1,x2,x3)−f(t,y1,y2,y3)|≤L(|x1−y1|+|x2−y2|+|x3−y3|),L>0,∀t∈[a,b],xi,yi∈R,i=1,2,3. | (4.1) |
Then the problem (1.6)-(1.7) has a unique solution on [a,b] if
κ+3LˉΔ<1, | (4.2) |
where κ is defined in (O2) and ˉΔ is given by (3.12).
Proof. Setting supt∈[a,b]|f(t,0,0,0)|=N<∞, and selecting
r∗≥3NˉΔ1−κ−3LˉΔ, |
we define Br∗={x∈A:‖x‖∗≤r∗}, and show that FBr∗⊂Br∗, where the operator F is defined by (3.3). For x∈Br∗, we use (4.1) to find that
|f(t,x(t),cDpax(t),cDp+1ax(t))|=|f(t,x(t),cDpax(t),cDp+1ax(t))−f(t,0,0,0)+f(t,0,0,0)|≤|f(t,x(t),cDpax(t),cDp+1ax(t))−f(t,0,0,0)|+|f(t,0,0,0)|≤L(|x(t)|+|cDpax(t)|+|cDp+1ax(t)|)+N≤L‖x‖∗+N≤Lr∗+N, |
where we used the norm given by (3.1).
Then, we have
|Fx(t)|≤r∗|ξ||μ|[(b−a)q−rΓ(q−r+1)+ˉϕ1(b−a)q−rΓ(q−r+1)+ˉϕ2(b−a)q−r−1Γ(q−r)+ˉϕ3(n−2∑i=1|αi|(ηi−a)q−rΓ(q−r+1)+∫ba(s−a)q−rΓ(q−r+1)dA(s))]+(Lr∗+N)|μ|[(b−a)qΓ(q+1)+ˉϕ1(b−a)qΓ(q+1)+ˉϕ2(b−a)q−1Γ(q)+ˉϕ3(n−2∑i=1|αi|(ηi−a)qΓ(q+1)+∫ba(s−a)qΓ(q+1)dA(s))]≤r∗Λ1+(Lr∗+N)ˉΛ1≤(κ/3)r∗+(Lr∗+N)ˉΔ. |
Similarly, we have
|cDpaFx(t)|≤r∗Λ2+(Lr∗+N)ˉΛ2≤(κ/3)r∗+(Lr∗+N)ˉΔ.|cDp+1aFx(t)|≤r∗Λ3+(Lr∗+N)ˉΛ3≤(κ/3)r∗+(Lr∗+N)ˉΔ. |
Hence we have
‖Fx‖∗≤κr∗+3(Lr∗+N)ˉΔ<r∗. |
Thus, Fx∈Br∗ for any x∈Br∗. Therefore, FBr∗⊂Br∗. Now, we show that F is a contraction. For x,y∈A and t∈[a,b], we obtain
|(Fx)(t)−(Fy)(t)|≤|ξ||μ|Iq−ra|x(t)−y(t)|+1|μ|Iqa|ˆf(x(t))−ˆf(y(t))|+1|μ|[|ϕ1(t)|(|ξ|∫ba(b−s)q−r−1Γ(q−r)|x(s)−y(s)|ds+∫ba(b−s)q−1Γ(q)|ˆf(x(s))−ˆf(y(s))|ds)+|ϕ2(t)|(|ξ|∫ba(b−s)q−r−2Γ(q−r−1)|x(s)−y(s)|ds+∫ba(b−s)q−2Γ(q−1)|ˆf(x(s))−ˆf(y(s))|ds)+|ϕ3(t)|(|ξ|n−2∑i=1|αi|∫ηia(ηi−s)q−r−1Γ(q−r)|x(s)−y(s)|ds+n−2∑i=1|αi|∫ηia(ηi−s)q−1Γ(q)|ˆf(x(s))−ˆf(y(s))|ds+|ξ|∫ba(∫sa(s−u)q−r−1Γ(q−r)|x(u)−y(u)|du)dA(s)+∫ba(∫sa(s−u)q−1Γ(q)|ˆf(x(u))−ˆf(y(u))|du)dA(s)))≤|ξ||μ|[(b−a)q−rΓ(q−r+1)+ˉϕ1(b−a)q−rΓ(q−r+1)+ˉϕ2(b−a)q−r−1Γ(q−r)+ˉϕ3(n−2∑i=1|αi|(ηi−a)q−rΓ(q−r+1)+∫ba(s−a)q−rΓ(q−r+1)dA(s))]‖x−y‖+1|μ|[(b−a)qΓ(q+1)+ˉϕ1(b−a)qΓ(q+1)+ˉϕ2(b−a)q−1Γ(q)+ˉϕ3(n−2∑i=1|αi|(ηi−a)qΓ(q+1)+∫ba(s−a)qΓ(q+1)dA(s))]L‖x−y‖=(Λ1+LˉΛ1)‖x−y‖≤(κ/3+LˉΔ)‖x−y‖, |
In a similar mannar, we have
|cDpaFx(t)−cDpaFy(t)|≤(Λ2+LˉΛ2)‖x−y‖≤(κ/3+LˉΔ)‖x−y‖,|cDp+1aFx(t)−cDp+1aFy(t)|≤(Λ3+LˉΛ3)‖x−y‖≤(κ/3+LˉΔ)‖x−y‖. |
Consequently, we obtain ‖(Fx)−(Fy)‖∗≤(κ+3LˉΔ)‖x−y‖, which in view of (4.2) implies that the operator F is a contraction. Therefore, F has a unique fixed point, which corresponds to a unique solution of the problem (1.6)-(1.7) on [a,b]. This completes the proof.
Example 4.1. Consider the following fractional differential equation
45cD359x(t)+9cD18x(t)=16(t2+2)(tan−1x(t)+cos(cD14x(t))+|cD54x(t)|1+|cD54x(t)|), | (4.3) |
t∈[0,1], supplemented with the boundary conditions of Example (3.1).
Obviously
f(t,x(t),cD14x(t),cD54x(t))=16(t2+2)(tan−1x(t)+cos(cD14x(t))+|cD54x(t)|1+|cD54x(t)|). |
Using the given data, we find that Δ≃0.134535 and ˉΔ≃0.012289, where Δ and ˉΔ are respectively given by (3.11) and (3.12). By the following inequality
|f(t,x(t),cD14x(t),cD54x(t))−f(t,y(t),cD14y(t),cD54y(t))|≤112(|x−y|+|cD14x−cD14y|+|cD54x−cD54y|)≤112‖x−y‖, |
we have L=112. Clearly (κ+3LˉΔ)≃0.406677<1. Therefore, the hypothesis of Theorem (4.1) is satisfied and consequently the problem (4.3) has a unique solution on [0,1].
Remark 4.1. Letting ξ=0 and μ=1 in the results of this paper, we obtain the ones for the fractional differential equation of the form:
cDqx(t)=f(t,x(t),cDpx(t),cDp+1x(t)),3<q≤4,0<p≤1,t∈[a,b], |
supplemented with Riemann-Stieltjes integro-multipoint boundary conditions (1.7). In this case fixed point operator takes the form:
(Fx)(t)=Iqˆf(x(t))−ϕ1(t)∫ba(b−s)q−1Γ(q)ˆf(x(s))ds−ϕ2(t)∫ba(b−s)q−2Γ(q−1)ˆf(x(s))ds−ϕ3(t)[n−2∑i=1αi∫ηia(ηi−s)q−1Γ(q)ˆf(x(s))ds+∫ba(∫sa(s−u)q−1Γ(q)ˆf(x(u))du)dA(s)]. |
We have proved the existence and uniqueness results for a multi-term Caputo fractional differential equation with nonlinearity depending upon the known function x together with its lower-order derivatives cDpax, cDp+1ax,0<p<1, complemented with Riemann-Stieltjes integro multipoint boundary conditions.
In Theorem 3.1, the existence of solutions for the given problem is established by means of Sadovskii fixed point theorem. The proof of this result is based on the idea of splitting the operator F into the sum of two operators F1 and F2 such that F1 is κ-contractive and F2 is compact. One can notice that the entire operator F is not required to be contractive. On the other hand, Theorem 4.1 deals with the existence of a unique solution of the given problem via Banach contraction mapping principle, in which the entire operator F is shown to be contractive. Thus, the linkage between contractive conditions imposed in Theorems 3.1 and 4.1 provides a precise estimate to pass onto a unique solution from the existence of a solution for the problem at hand.
As a special case, by letting ξ=0 and μ=1 in the results of this paper, we obtain the ones for the fractional differential equation of the form:
cDqax(t)=f(t,x(t),cDpax(t),cDp+1ax(t)),3<q≤4,0<p≤1,t∈(a,b), |
supplemented with Riemann-Stieltjes integro-multipoint boundary conditions (1.7). In this case, the fixed point operator (3.3) takes the following form:
(Fx)(t)=Iqaˆf(x(t))−ϕ1(t)∫ba(b−s)q−1Γ(q)ˆf(x(s))ds−ϕ2(t)∫ba(b−s)q−2Γ(q−1)ˆf(x(s))ds−ϕ3(t)[n−2∑i=1αi∫ηia(ηi−s)q−1Γ(q)ˆf(x(s))ds+∫ba(∫sa(s−u)q−1Γ(q)ˆf(x(u))du)dA(s)]. |
In case we take αi=0 for all i=1,…,n−2, then our results correspond to the integral boundary conditions:
x(a)=∫bax(s)dA(s), x′(a)=0, x(b)=0, x′(b)=0. |
We thank the reviewers for their constructive remarks on our work.
All authors declare no conflicts of interest in this paper.
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